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Let age of Aftab is represented by x

And age of daughter is represented by y

Then Seven years ago,

Age of Aftab = x -7

Age of daughter = y-7

As per the question Aftab was seven times as old as her daughter then were so we get

(x – 7) = 7 (y – 7)

x – 7y = -42 …(1)

Now Three years from now ,

Age of Aftab = x +3

Age of daughter = y+3

As per question Aftab shall be three times as old as her daughter will be so we get

x + 3 = 3 (y + 3)

x -3 y = 6 …(2)

x – 7 y = - 42 …(1)

x -3 y = 6 …(2)

To represent it graphically, we need to plot these equation on the XY coordinate system.

We can choose two values of each equation and plot it on XY coordinate system

x – 7 y = - 42 or

y=(x+42)/7

X |
0 |
7 |

Y=(x+42)/7 |
6 |
7 |

y=(x-6)/3

X |
0 |
6 |

Y=(x-6)/3 |
-2 |
0 |

Let Cost of one bat = Rs x

Let Cost of one ball = Rs y

3 bats and 6 balls for Rs 3900 So that

3 x + 6y = 3900 … (1)

Given that she buys another bat and 2 more balls of the same kind for Rs 1300

So we get

x + 2 y = 1300 … (2)

3 x + 6y = 3900 … (1)

x + 2 y = 1300 … (2)

To represent it graphically, we need to plot these equation on the XY coordinate system.

We can choose two values of each equation and plot it on XY coordinate system

3x +6y = 3900 or

y=(3900-3x)/6

X |
-1300 |
1300 |

y=(3900-3x)/6 |
1300 |
0 |

y=(1300-x)/2

X |
1300 |
-1300 |

y=(1300-x)/2 |
0 |
1300 |

Let cost each kg of apples = Rs x

Cost of each kg of grapes = Rs y

The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160

So that

2 x + y = 160 … (1)

Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300

so we get

4x + 2y= 300 … (2)

2 x + y = 160 … (1)

4x + 2y= 300 … (2)

To represent it graphically, we need to plot these equation on the XY coordinate system.

We can choose two values of each equation and plot it on XY coordinate system

2x +y = 160 or

y=160-2x

X |
80 |
40 |

y=160-2x |
0 |
80 |

X |
0 |
50 |

y=(300-4x)/2 |
150 |
50 |

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