In this page we have NCERT book Solutions for Class 9th Maths:statistics for EXERCISE 1 . Hope you like them and do not forget to like , social share and comment at the end of the page.
Question 1
The blood groups of 30 students of Class VIII are recorded as follows:
A, B, O, O, AB, O, A, O, B, A, O, B, A, O, O,
A, AB, O, A, A, O, O, AB, B, A, O, B, A, B, O.
Represent this data in the form of a frequency distribution table. Which is the most common, and which is the rarest, blood group among these students?
Solution
The number of students who have a certain type of blood group is called frequency of the blood group
The below Frequency distribution is prepared
Blood Group 
Frequency 
A 
9 
B 
6 
O 
12 
AB 
3 
We can clearly see from the frequency distribution table that blood group AB is the rarest and blood group O is the most common.
Question 2
The distance (in km) of 40 engineers from their residence to their place of work were found as follows:
5 
3 
10 
20 
25 
11 
13 
7 
12 
31 
19 
10 
12 
17 
18 
11 
32 
17 
16 
2 
7 
9 
7 
8 
3 
5 
12 
15 
18 
3 
12 
14 
2 
9 
6 
15 
15 
7 
6 
12 
Construct a grouped frequency distribution table with class size 5 for the data given above taking the first interval as 0  5 (5 not included). What main feature do you observe from this tabular representation?
Solution:
It is given that a grouped frequency distribution table of class size 5 has to be constructed. Therefore, the class intervals will be 0 − 5, 5 − 10, 10 − 15, 15 −20…
By observing the data given as above, a grouped frequency distribution table can be constructed as follows.
Class (Distance) 
Frequency 
05 
5 
510 
11 
1015 
11 
1520 
9 
2025 
1 
2530 
1 
3035 
2 
It can be observed that there are very few engineers whose homes are at more than or equal to 20 km distance from their work place. Most of the engineers have their workplace up to 15 km distance from their homes.
Question 3:
The relative humidity (in %) of a certain city for a month of 30 days was as follows
98.1 
98.6 
99.2 
90.3 
86.5 
95.3 
92.9 
96.3 
94.2 
95.1 
89.2 
92.3 
97.1 
93.5 
92.7 
95.1 
97.2 
93.3 
95.2 
97.3 
96.2 
92.1 
84.9 
90.2 
95.7 
98.3 
97.3 
96.1 
92.1 
89 
(i) Construct a grouped frequency distribution table with classes
84  86, 86  88
(ii) Which month or season do you think this data is about?
(iii) What is the range of this data?
Solution:
Class intervals will be as follows 84  86, 86  88, and 88  90... ...
Relative humidity 
Frequency in days 
8486 
1 
8688 
1 
8890 
2 
9092 
2 
9294 
7 
9496 
6 
9698 
7 
98100 
4 
ii) Since relative humidity is high so the data must be of a month of rainy season.
(iii) Range of data = maximum value  minimum value
= 99.2  84.9
= 14.3
Question 4:
The heights of 50 students, measured to the nearest centimeters, have been found to be as follows:
161 
150 
154 
165 
168 
161 
154 
162 
150 
151 
162 
164 
171 
165 
158 
154 
156 
172 
160 
170 
153 
159 
161 
170 
162 
165 
166 
168 
165 
164 
154 
152 
153 
156 
158 
162 
160 
161 
173 
166 
161 
159 
162 
167 
168 
159 
158 
153 
154 
159 
i) Represent the data given above by a grouped frequency distribution table, taking the class intervals as 160  165, 165  170, etc.
(ii) What can you conclude bout their heights from the table?
Solution:
Class intervals will be as follows 160  165, 165  170, etc.
Heights 
Frequency 
150155 
12 
155160 
9 
160165 
14 
165170 
10 
170175 
5 
It is clear from the table, out of 50 students, 35 are below 165 cm. So 50%of the students are below 165cm
Question 5
A study was conducted to find out the concentration of sulphur dioxide in the air in Parts per million (ppm) of a certain city. The data obtained for 30 days is as follows
0.03 
0.08 
0.08 
0.09 
0.04 
0.17 
0.16 
0.05 
0.02 
0.06 
0.18 
0.2 
0.11 
0.08 
0.12 
0.13 
0.22 
0.07 
0.08 
0.01 
0.1 
0.06 
0.09 
0.18 
0.11 
0.07 
0.05 
0.07 
0.01 
0.04 
(i) Make a grouped frequency distribution table for this data with class intervals as 0.00  0.04, 0.04  0.08, and so on.
(ii) For how many days, was the concentration of sulphur dioxide more than 0.11 parts per million?
Solution
Frequency distribution
Interval 
Frequency 
.00.04 
4 
.04.08 
9 
.08  .12 
9 
.12 .16 
2 
.16.20 
4 
.20.24 
2 
ii)The concentration of sulphur dioxide was more than 0.11 parts per million for 8 days.
Question 6
Three coins were tossed 30 times simultaneously. Each time the number of heads occurring was noted down as follows
0 
1 
2 
2 
1 
2 
3 
1 
3 
0 
1 
3 
1 
1 
2 
2 
0 
1 
2 
1 
3 
0 
0 
1 
1 
2 
3 
2 
2 
0 
Prepare a frequency distribution table for the data given above.
Solution
Frequency table
Number of heads 
Frequency 
0 
6 
1 
10 
2 
9 
3 
5 
Question 7:
The value of π up to50 decimal places is given below:
3.14159265358979323846264338327950288419716939937510
(i) Make a frequency distribution of the digits from 0 to 9 after the decimal point.
(ii) What are the most and the least frequently occurring digits?
Solution:
Digits 
Frequency 
0 
2 
1 
5 
2 
5 
3 
8 
4 
4 
5 
5 
6 
4 
7 
4 
8 
5 
9 
8 
(ii) From the above table the least frequency is 2 of digit 0, and the maximum frequency is 8 of digit 3 and 9. So, the most frequently occurring digits are 3 and 9 and the least occurring digit is 0.
Question 8:
Thirty children were asked about the number of hours they watched TV programmes in the previous week. The results were found as follows:
1 
6 
2 
3 
5 
12 
5 
8 
4 
8 
10 
3 
4 
12 
2 
8 
15 
1 
17 
6 
3 
2 
8 
5 
9 
6 
7 
14 
12 

(i) Make a grouped frequency distribution table for this data, taking class width 5 and one of the class intervals as 5  10.
(ii) How many children watched television for 15 or more hours a week?
Solution:
i) Frequency table
Number of hours 
Frequency 
05 
10 
510 
13 
1015 
5 
1520 
2 
(ii) 2 children watched television for 15 or more hours per week.
Question 9:
A company manufactures car batteries of a particular type. The lives (in years) of 40 such batteries were recorded as follows:
2.6 
3 
3.7 
3.2 
2.2 
4.1 
3.5 
4.5 
3.5 
2.3 
3.2 
3.4 
3.8 
3.2 
4.6 
3.7 
2.5 
4.4 
3.4 
3.3 
2.9 
3 
4.3 
2.8 
3.5 
3.2 
3.9 
3.2 
3.2 
3.1 
3.7 
3.4 
4.6 
3.8 
3.2 
2.6 
3.5 
4.2 
2.9 
3.6 
Construct a grouped frequency distribution table for this data, using class intervals of size 0.5 starting from the intervals 2 − 2.5.
Solution:
Frequency distribution
Lives of battery 
Number of batteries 
22.5 
2 
2.5 3.0 
6 
3.0 – 3.5 
14 
3.54.0 
11 
4.0 4.5 
4 
4.5 – 5.0 
3 
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