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Ncert Solutions for Class 6 Maths Integers Exercise 6.2 and 6.3

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In this page we have Ncert Solutions for Class 6 Maths Integers Exercise 6.2 and 6.3. Hope you like them and do not forget to like , social share and comment at the end of the page.

 

Exercise 6.2

Question 1

Using the number line write the integer which is:

(a) 3 more than 5

(b) 5 more than −5

(c) 6 less than 2

(d) 3 less than −2

Answer

More means moving right on the number line and less mean moving left on the Number line

a)

So answer would be 8

b)

So answer would be 0

c)

So answer is -4

d)

So answer is -5

Question 2

Use number line and add the following integers:

(a) 9 + (− 6)

(b) 5 + (− 11)

(c) (− 1) + (− 7)

(d) (− 5) + 10

(e) (− 1) + (− 2) + (− 3)

(f) (− 2) + 8 + (− 4)

Answer

Two important things to remember

When we add positive integer, we move to the right

When we add negative integer, we move to the right

a) 9 + (− 6)

We start with number 9 and move to left six steps and we reach the number 3

 

b) 5 + (− 11)

We start with number 5 and move to left 11 steps and we reach the number -6

 

c) (− 1) + (− 7)

We start with number -1 and move to left 7 steps and we reach the number -8

d) (− 5) + 10

We start with number -5 and move to right 10 steps and we reach the number 5

 

e) (− 1) + (− 2) + (− 3)

We start with number -1 and move to left 2 steps and we reach the number -3. Then again we move to left 3 steps and we reach finally -6

f) (− 2) + 8 + (− 4)

We start with number -2 and move to right 8 steps and we reach the number 6. Then again we move to left 4 steps and we reach finally 2

 

Question 3

Add without using number line:

(a) 11 + (− 7)

(b) (− 13) + (+18)

(c) (− 10) + (+19)

(d) (− 250) + (+ 150)

(e) (− 380) + (− 270)

(f) (− 217) + (− 100)

Answer

We have to take important note of this principle

1) When one positive and one negative integers are added, we subtract the smaller number from bigger number and put the sign of the bigger integer. The bigger integer is decided by ignoring the signs of the integers

For example, (+11) + (–5) = + 6 and (–12) + (+ 1) = – 11

2) When two negative integers are added, we add both the number and put the negative sign on the number=

For example, (-11) + (–5) = -16 and (–12) + (- 1) = – 13

With this in mind, lets solve all the questions given above

a)

11 + (− 7)

Subtracting 7 from 11= 4

+4

b)

(− 13) + (+18)

 

Subtracting 13 from 18= 5

+5

c)

(− 10) + (+19)

 

Subtracting 10 from 19= 9

+9

d)

(− 250) + (+ 150)

 

Subtracting 150 from 250= 100

-100

e)

(− 380) + (− 270)

Adding 380 and 270=650

-650

f)

(− 217) + (− 100)

Adding 217 and 100=317

-317

 

Question 4

Find the sum

(a) 137 and −354

 (b) − 52 and 52

(c) − 312, 39 and 192

 (d) − 50, − 200 and 300

Answer

We have to take important note of this principle

1) When one positive and one negative integers are added, we subtract the smaller number from bigger number and put the sign of the bigger integer. The bigger integer is decided by ignoring the signs of the integers

For example, (+11) + (–5) = + 6 and (–12) + (+ 1) = – 11

2) When two negative integers are added, we add both the number and put the negative sign on the number=

For example, (-11) + (–5) = -16 and (–12) + (- 1) = – 13

Also when three or more numbers are present, we start with first pair of 2 number, the answer from first pair is added to the third Number and it goes on.

a)

137 and −354

Subtracting 137 from 354= 217

-217

b)

− 52 and 52

 

Subtracting 52 from 52= 0

0

c)

− 312, 39 and 192

 

1) Taking number -312 and 39 first

Subtracting 39 from 312= 273

-273

2) Taking the number -273 and 192

Subtracting 192 from 273= 81

-81

d)

− 50, − 200 and 300

 

1) Taking number -50 and -200 first

Adding 50 and 200= 250

-250

2) Taking the number -250 and 300

Subtracting 250 from 300=50

50

 

Question 5

Find the sum:

(a) (− 7) + (− 9) + 4 + 16

(b) (37) + (− 2) + (− 65) + (− 8)

Answer

a. (– 7) + (– 9) + 4 + 16 = (-16) + (20) =4

b.  (37) + (– 2) + (– 65) + (– 8) = (37) + (-75) = (-38)

Exercise 6.3

Question 1

Find:

(a) 35 − (20)

(b) 72 − (90)

(c) (− 15) − (− 18)

(d) (− 20) − (13)

(e) 23 − (− 12)

(f) (− 32) − (− 40)

 

Answer

To subtract two integers, we add the additive inverse of the integer that is being subtracted.

So 2 -5 = 2+ (-5) as -5 is additive inverse of 5

Now we have already learned the addition of integers before

a)

35 − (20)

= 35+ (-20)

Subtract 35 and 20 and put the sign of the bigger number 35, which is positive

15

b)

72 − (90)

72+(-90)

 

Subtract 72 and 90 and put the sign of the bigger number 90, which is negative

-18

c)

(− 15) − (− 18)

= (-15) + (18)

As additive inverse of -18 is 18

Subtract 15 and 18 and put the sign of the bigger number 18, which is negative

3

d)

(− 20) − (13)

= (-20) + (13)

Subtract 20 and 13 and put the sign of the bigger number 20, which is negative

-7

e)

23 − (− 12)

=23+12

Adding the numbers 23 and 12= 35

f)

(− 32) − (− 40)

= (-32) + (40)

Subtract 32 and 40 and put the sign of the bigger number 40, which is negative

8

 

Question 2

Fill in the blanks with >, < or = sign.

(a) (− 3) + (− 6) _____ (− 3) − (− 6)

(b) (− 21) − (− 10) _____ (− 31) + (− 11)

(c) 45 − (− 11) _____ 57 + (− 4)

(d) (− 25) − (− 42) _____ (− 42) − (−25)

Answer

We need to use the same addition and subtraction rules on both sides and then perform comparison

S.no

Question

LHS

RHS

Answer

a)

(− 3) + (− 6) _____ (− 3) − (− 6)

-9

3

b)

(− 21) − (− 10) _____ (− 31) + (− 11)

-11

-32

c)

45 − (− 11) _____ 57 + (− 4)

55

53

d)

(− 25) − (− 42) _____ (− 42) − (−25)

 

17

-17

 

Question 3

Fill in the blanks.

(a) (− 8) + _____ = 0

(b) 13 + _____ = 0

(c) 12 + (− 12) = _____

(d) (− 4) + _____ = − 12

(e) _____ − 15 = − 10

Answer

a)

(− 8) + _____ = 0

 

8

b)

13 + _____ = 0

 

-13

c)

12 + (− 12) = ___

0

d)

(− 4) + _____ = − 12

 

-8

e)

_____ − 15 = − 10

 

5

 

Question 4

Find:

(a) (− 7) − 8 − (− 25)

(b) (− 13) + 32 − 8 − 1

(c) (− 7) + (− 8) + (− 90)

(d) 50 − (− 40) − (− 2)

Answer

(a) (– 7) – 8 – (– 25) = (-15) – (-25) = (-15) + 25 = 10

(b) (– 13) + 32 – 8 – 1 = 19 - 8 – 1 = 11 – 1 = 10

(c) (– 7) + (– 8) + (– 90) = (-15) + (-90) = (-105)

(d) 50 – (– 40) – (– 2) = 50 + 40 – (-2) = 90 – (-2) = 90 + 2 = 92

 


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