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NCERT Solutions for Class 6 Maths Mensuration Chapter 10


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In this page we have NCERT Solutions for Class 6 Maths Mensuration Chapter 10 Exercise 10.2 and 10.3 . Hope you like them and do not forget to like , social share and comment at the end of the page.

Exercise 10.2

Question 1

Find the areas of the following figures by counting square:
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
(a)
(b)
(c)
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
(d)
(e)
(f)
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
(g)
(h)
(i)
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
(j)
(k)
(l)
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
 
(m)
(n)
 
Answer
Important points to consider before solving these questions
1) The area of one full square is taken as 1 sq. unit. If it is a centimetre square sheet, then area of one full square will be 1 sq. cm.
2) Ignore portions of the area that are less than half a square.
3) If more than half of a square is in a region, just count it as one square.
4) If exactly half the square is counted, take its area as ½ sq. unit.
Question
Full square
½ square
region less than half a square. They will be not counted in area
Region greater than half square. They will be counted as full squares
Total area by counting squares
a)
9
-
-
-
9
b)
5
-
-
-
5
c)
2
4
-
-
2+1/2+1/2+1/2+1/2= 4
d)
8
-
-
-
8
e)
10
-
-
-
10
f)
2
4
-
-
2+ 4×1/2= 4
g)
4
4
-
-
4+ 4×1/2= 6
h)
5
-
-
-
5
i)
9
-
-
-
9
j)
2
4
-
-
2+ 4×1/2= 4
k)
4
2
-
-
4+ 2×1/2= 5
l)
2
2
4
3
2+2×1/2+ 3=6
m)
5
-
5
9
5+9=14
n)
8
-
6
10
8+10=18

Exercise 10.3

Question 1
Find the areas of the rectangles whose sides are:
(a) 3 cm and 4 cm
 (b) 12 m and 21 m
(c) 2 km and 3 km
 (d) 2 m and 70 cm
Answer
Area of the rectangles is given by = L× B
a)
3cm, 4cm
12 cm2
b)
12cm,21cm
252 cm2
c)
2km,3km
6 km2
d)
2m,70cm (.7 m)
1.4 m2
Question 2
Find the areas of the squares whose sides are:
(a) 10 cm
(b) 14 cm
 (c) 5 m
Answer
Area of the square is given by = (side)2
a)
10 cm
100cm2
b)
14 cm
196 cm2
c)
5 cm
25 m2
Question 3
The length and breadth of three rectangles are as given below:
(a) 9 m and 6 m
(b) 17 m and 3 m
(c) 4 m and 14 m
Which one has the largest area and which one has the smallest?
Answer
Area of the rectangles is given by = L× B
a)
9m, 6m
54 m2
b)
17m,3m
51m2
c)
4m,14m
56 m2
c) has the largest area and b) has the smallest area.
Question 4
The area of a rectangular garden 50 m long is 300 sq. m. Find the width of the garden.
Answer
Length of the rectangular garden is 50 m
Area = 300 sq. m
Area of a rectangle = length × breadth
I.e. 300 = 50 × breadth
Breadth = 300 / 50 = 6 m
So, breadth (width) of the garden is 6 m.
Question 5
What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of Rs 8 per hundred sq. m?
Answer
To tile a rectangular plot, we need to find the area of the plot.
Given length of the plot = 500 m
Width of the plot = 200 m
So, area of the plot = 500 × 200 = 1,00,000 sq. m
The cost of tiling 100 sq. m = Rs 8.
So, the cost of tiling 1,00,000 sq. m is (8 × 1,00,000)/100 = Rs. 8,000
Question 6
A table-top measures 2 m by 1 m 50 cm. What is its area in square meters?
Answer
The important thing in these question is the Unit conversion. We need to either convert m into cm or cm into m. It is good to convert into lowest unit to make it easier
Length of the table-top = 2 m
Width of the table-top = 1 m 50 cm = 1.50 m
So, area of the table-top = length × breadth = 2 × 1.50 = 3 sq. m
Question 7
A room is 4 m long and 3 m 50 cm wide. How many square meters of carpet is needed to cover the floor of the room?
Answer
Length of the room = 4 m
Width of the room is 3 m 50 cm = 3.50 m
To carpet the room, we need to find the area of the floor.
So, Area of the room = length × breadth = 4 × 3.50 = 14 sq. m
Question 8
A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.
Answer
Given Length of the floor = 5 m
Width of the floor = 4 m
Total area of the floor = 5 × 4 = 20 sq. m
Area of the square carpet = 3 × 3 = 9 sq. m
So, 9 sq. m of the floor is covered with carpet.
So, area of the floor that is not carpeted = 20 – 9 = 11 sq. m
Question 9
Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?
Answer
Area of the piece of land = 5 × 4 = 20 m2
Area of each flower bed = 1 × 1 = 1 m2
Five square beds are dug on the land.
So, area of five such flower beds = 5 m2
Area of the remaining part = Area of the piece of land – area of the 5 flower beds.
                                           = 20 – 5 = 15 m2
Question 10
By splitting the following figures into rectangles, find their areas (The measures are given in centimeters).
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
Answer
a) The given figure can be divided into four rectangles
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
Area of first rectangle =4×2=8 cm2
Area of second rectangles= 6×1=6 cm2
Area of Third rectangles= 3×2=6 cm2
Area of four rectangles= 4×2=8 cm2
Total area =28 cm2
b) The given figure can be divided into three rectangles
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
Area of first rectangle =3×1=3 cm2
Area of second rectangles= 3×1=3 cm2
Area of Third rectangles= 3×1=3 cm2
Total area =9 cm2
Question 12
Split the following shapes into rectangles and find their areas. (The measures are given in centimeters)
NCERT Solutions for Class 6 Maths Mensuration Chapter 10
Answer
This question can be attempted in the same way as previous question
a) 40 cm2
b) 49 cm2
c) 9 cm2
Question 13
How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:
(a) 100 cm and 144 cm
(b) 70 cm and 36 cm
Answer
Length of the tile = 12 cm; Breadth of the tile = 5 cm
Area of one tile = 12 × 5 = 60 sq. cm
a) Length of the rectangular region = 100 cm
Breadth of the rectangular region = 144 cm
Area of the rectangular region = 100 × 144 = 14400 sq. cm
Therefore, number of tiles needed = 14400/60 = 240 tiles
b) Length of the rectangular region = 70 cm
Breadth of the rectangular region = 36 cm
Area of the rectangular region = 70 × 36 = 2520 sq. cm
Therefore, number of tiles needed = 2520/60 = 42 tiles

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