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Ncert Solutions for Linear equations Class 8 CBSE Part 1


In this page we have NCERT book Solutions for Class 8th Maths:Linear equations for EXERCISE 1 . Hope you like them and do not forget to like , social share and comment at the end of the page.

Question 1:  

Solve:  x-2=7

Answer:

x - 2 = 7

Transposing 2 to R.H.S, we obtain

x = 7 + 2 = 9

Question 2:  

Solve:  y+3=10

Answer :

y + 3 = 10

Transposing 3 to R.H.S, we obtain

y = 10 - 3 = 7

Question 3:

Solve:  6=z+2

Answer

6=z+2

Or

z+2=6

Transposing 2 to R.H.S, we obtain

z=6 -2=4

Question 4  

Solve:


Answer :

Multiplying 7 on both sides

3+7x=17

Transposing 3 to R.H.S, we obtain

7x=17-3=14

7x=14

Dividing both the sides by 7

x=2

Question 5:  

Solve:

6x=12


Answer:

6x=12

Dividing both the sides by 6

x=2

Question 6: 

Solve:


Answer:

Multiplying 5 on both sides

t=50

Question 7:  

Solve

 
Answer:

Multiplying both the sides by 3

2x=54

Dividing both the sides by 2

x=27

Question 8:  

Solve:


Answer:

Multiplying both the sides by 1.5

1.6 × 1.5=y

y=2.4

Question 9:  

Solve:

 7x-9=16

Answer:

7x-9=16

Transposing 9 to R.H.S, we obtain

7x=16+9

7x=25

Dividing by 7 on both the sides

x=25/7

 

Question 10:  

Solve:

14y-8=13


Answer:

14y-8=13

Transposing 8 to R.H.S, we obtain

14y=13+8

14y=21

Dividing 14 on both the sides

y=21/14=3/2

 

Question 11:  

Solve:

17+6p=9

Answer:

17+6p=9

Transposing 17 to R.H.S, we obtain

6p=9-17

6p=-8

Dividing 6 on both the sides

p=-8/6=-4/3

 

Question 12:  

Solve:


Answer:

The LCM of denominator is 15, So multiplying both sides by 15

5x +15=7

Transposing 15 to R.H.S, we obtain

5x=-8

Dividing 5 on both the sides

x=-8/5

 


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