In this page we have *NCERT book Solutions for Class 8th Maths:Linear equations* for
EXERCISE 5 . Hope you like them and do not forget to like , social share
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L.C.M. of the denominators, 2, 3, 4, and 5, is 60.

So Multiplying both sides by 60, we obtain

30

Transposing 20x to R.H.S and 12 to L.H.S, we obtain

30

10

X=27/10=2.7

L.C.M. of the denominators, 2, 4, and 6, is 12.

Multiplying both sides by 12, we obtain

6

7

Dividing by 7 on both the sides

n=36

L.C.M. of the denominators, 2, 3, and 6, is 6.

Multiplying both sides by 6, we obtain

6

6

5

Dividing by 5 on both the sides

x=-5

L.C.M. of the denominators, 3 and 5, is 15.

Multiplying both sides by 15, we obtain

5(

5

5

2

Dividing both the sides by 2

x=8

L.C.M. of the denominators, 3 and 4, is 12.

Multiplying both sides by 12, we obtain

3(3

9

9

13

Dividing by 13 on both the sides

t=2

L.C.M. of the denominators, 2 and 3, is 6.

Multiplying both sides by 6, we obtain

6

6

6

5

Dividing by 5 on both the sides

m=7/5

3(

3

−9 − 5 = 10

−14 = 7t

t=-2

15(

15

18

18

3(5

3(5

15

−3

−3

−35

z=2

0.25(4

Multiplying both sides by 20, we obtain

5(4

20

20

10

f==6/10=3/5

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