In this page we have ** NCERT book Solutions for Class 8th Maths:Linear equations** for
EXERCISE 5 . Hope you like them and do not forget to like , social share
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**Question 1 **Solve the linear equation

**Answer **

L.C.M. of the denominators, 2, 3, 4, and 5, is 60.

So Multiplying both sides by 60, we obtain

30*x *− 12 = 20*x *+ 15

Transposing 20x to R.H.S and 12 to L.H.S, we obtain

30*x *− 20*x* = 15 + 12

10*x* = 27

X=27/10=2.7

**Question 2 **Solve the linear equation

**Answer **

L.C.M. of the denominators, 2, 4, and 6, is 12.

Multiplying both sides by 12, we obtain

6*n* − 9*n* + 10*n* = 252

7*n* = 252

Dividing by 7 on both the sides

n=36

**Question 3- **Solve the linear equation

**Answer **

L.C.M. of the denominators, 2, 3, and 6, is 6.

Multiplying both sides by 6, we obtain

6*x* + 42 − 16*x *= 17 − 15*x*

*Transposing 15x to RHS and 42 to LHS*

6*x* − 16*x *+ 15*x *= 17 − 42

5*x* = −25

Dividing by 5 on both the sides

x=-5

**Question 4- **Solve the linear equation

**Answer **

L.C.M. of the denominators, 3 and 5, is 15.

Multiplying both sides by 15, we obtain

5(*x* − 5) = 3(*x* − 3)

5*x* − 25 = 3*x* − 9

*Transposing 3x to RHS and 25 to LHS*

5*x* − 3*x* = 25 − 9

2*x* = 16

Dividing both the sides by 2

x=8

**Question 5- **Solve the linear equation

**Answer **

L.C.M. of the denominators, 3 and 4, is 12.

Multiplying both sides by 12, we obtain

3(3*t* − 2) − 4(2*t* + 3) = 8 − 12*t*

9*t *− 6 − 8*t* − 12 = 8 − 12*t*

*Transposing 12t to RHS and 6 and 12 to LHS*

9*t *− 8*t* + 12*t* = 8 + 6 + 12

13*t* = 26

Dividing by 13 on both the sides

t=2

**Question 6 **Solve the linear equation

**Answer **

L.C.M. of the denominators, 2 and 3, is 6.

Multiplying both sides by 6, we obtain

6*m* − 3(*m* − 1) = 6 − 2(*m* − 2)

6*m* − 3*m* + 3 = 6 − 2*m* + 4

*Transposing 2m to RHS and 3 to LHS*

6*m* − 3*m* + 2*m* = 6 + 4 − 3

5*m* = 7

Dividing by 5 on both the sides

m=7/5

**Question 7- **Simplify and solve the linear equation

3(*t* − 3) = 5(2*t* + 1)

**Answer **

3(*t* − 3) = 5(2*t* + 1)

3*t* − 9 = 10*t* + 5

−9 − 5 = 10*t* − 3*t*

−14 = 7t

t=-2

**Question 8- **Simplify and solve the linear equation

15(*y* − 4) − 2(*y* − 9) + 5(*y* + 6) = 0

**Answer **

15(*y* − 4) − 2(*y* − 9) + 5(*y* + 6) = 0

15*y *− 60 − 2*y* + 18 + 5*y* + 30 = 0

18*y *− 12 = 0

18*y *= 12

y=12/18=2/3

**Question 9- **Simplify and solve the linear equation

3(5*z* − 7) − 2(9*z* − 11) = 4(8*z* − 13)−17

**Answer **

3(5*z* − 7) − 2(9*z* − 11) = 4(8*z* − 13)−17

15*z* − 21 − 18*z* + 22 = 32*z* − 52 − 17

−3*z* + 1 = 32*z* − 69

−3*z* − 32*z* = −69 − 1

−35*z* = −70

z=2

**Question 10- **Simplify and solve the linear equation

0.25(4*f* − 3) = 0.05(10*f* − 9)

**Answer **

0.25(4*f* − 3) = 0.05(10*f* − 9)

Multiplying both sides by 20, we obtain

5(4*f* − 3) = 10*f* − 9

20*f *− 15 = 10*f* − 9

20*f *− 10*f* = − 9 + 15

10*f* = 6

f==6/10=3/5

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