# Ncert Solutions for quadilaterals Class 8 CBSE Part 2

Ncert Solutions

In this page we have NCERT book Solutions for Class 8th Maths:quadilaterals for EXERCISE 2 . Hope you like them and do not forget to like , social share and comment at the end of the page.

Question 1   Find x in the following figures

a)

b)

Answer - We know that the sum of all exterior angles of any polygon is 360º.

(a) 125° + 125° + x = 360°

250° + x = 360°

x = 110°

b)

60° + 90° + 70° + x + 90° = 360°

310° + x = 360°

x = 50°

Question 2

Find the measure of each exterior angle of a regular polygon of

(i) 9 sides

(ii) 15 sides

(i) Sum of all exterior angles of the given polygon = 360º

Each exterior angle of a regular polygon has the same measure.

Thus, measure of each exterior angle of a regular polygon of 9 sides

=360/9= 400

ii) Sum of all exterior angles of the given polygon = 360º

Each exterior angle of a regular polygon has the same measure.

Thus, measure of each exterior angle of a regular polygon of 15 sides

=360/15=240

Question 3

How many sides does a regular polygon have if the measure of an exterior angle is 24°?

Sum of all exterior angles of the given polygon = 360º

Measure of each exterior angle = 24º

Thus, number of sides of the regular polygon

=360/24=15

Question 4

How many sides does a regular polygon have if each of its interior angles is 165°?

Answer - Measure of each interior angle = 165°

Measure of each exterior angle = 180° − 165° = 15°

The sum of all exterior angles of any polygon is 360º.

Thus, number of sides of the polygon

=360/15=24

Question 5

(a) Is it possible to have a regular polygon with measure of each exterior angle as 22°?

(b) Can it be an interior angle of a regular polygon? Why?

The sum of all exterior angles of all polygons is 360º. Also, in a regular polygon, each exterior angle is of the same measure. Hence, if 360º is a perfect multiple of the given exterior angle, then the given polygon will be possible.

(a) Exterior angle = 22°

360º is not a perfect multiple of 22º. Hence, such polygon is not possible.

(b) Interior angle = 22°

Exterior angle = 180° − 22° = 158°

Such a polygon is not possible as 360° is not a perfect multiple of 158°.

Question 6

(a) What is the minimum interior angle possible for a regular polygon?

(b) What is the maximum exterior angel possible for a regular polygon?