- Square Number
- How to find the square of Number easily
- |
- Pythagorean triplets
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- Square Root
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- How to Find Square root
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- Estimating Digits in the Square Root

In this page we have *NCERT book Solutions for Class 8th Maths:Square roots Chapter 6 * for
EXERCISE 2 . Hope you like them and do not forget to like , social share
and comment at the end of the page.

Find the square of the following numbers.

(i) 32

(ii) 35

(iii) 86

(iv) 93

(v) 71

(vi) 46

1) 32

We can find the square using direct multiplication

= 32 x 32 = 1024

But above method can be cumbersome to calculate. We can calculate such values in the another better way f

Since, 32 can be written as (30+2)

So, 32

Now we know the identity

(a+b)

= 30

= 900 + 120 + 4 = 1024

2) (35)

Solving on similar lines as above

= 30

= 900 + 300 + 25 = 1225

3) 86

= 80

= 6400 + 960 + 36 = 7396

4) 93

= 90

= 8100 + 540 + 9 = 8649

5) 71

= 70

= 4900 + 140 + 1 = 5040 + 1 = 5041

6) 46

= 40

= 1600 + 480 + 36 = 2080 + 36 = 2116

Write a Pythagorean triplet whose one member is:

(i) 6

(ii) 14

(iii) 16

(iv) 18

As we know 2n, n

1) If we take n

So we can 2n = 6

Therefore, n = 3

And, n

And,n

Test: 6

Hence, the triplet is 6, 8, and 10 Answer

2) If we take n

So we can take 2n= 14, therefore, n = 7

Now, n

And, n

Test: 14

Hence, the triplet is 14, 48, and 50 Answer

3) If we take n

Let us assume 2n = 16, then n = 8

Now, n

And, n

Test: 16

Hence, the triplet is 16, 63, and 65 Answer

4) If we take n

Let us assume 2n = 18, therefore, n = 9

Now, n

And, n

Test: 18

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