{"id":2421,"date":"2020-06-03T07:56:00","date_gmt":"2020-06-03T02:26:00","guid":{"rendered":"http:\/\/physicscatalyst.com\/article\/?p=2421"},"modified":"2022-11-04T12:06:28","modified_gmt":"2022-11-04T06:36:28","slug":"how-to-solve-inequalities-in-mathematics","status":"publish","type":"post","link":"https:\/\/physicscatalyst.com\/article\/how-to-solve-inequalities-in-mathematics\/","title":{"rendered":"how to solve inequalities questions quickly and easily"},"content":{"rendered":"\n<blockquote class=\"wp-block-quote is-layout-flow wp-block-quote-is-layout-flow\"><p>This article,i am explaining Inequalities Rules&nbsp; and how to solve inequalities<\/p><\/blockquote>\n\n\n\n<h2 class=\"wp-block-heading\"><span style=\"text-decoration: underline;\">What is inequalities<\/span><\/h2>\n\n\n\n<p>In mathematics, an inequality is a relation that holds between two values when they are different<br>Solving linear inequalities is very similar to solving linear equations, except for one small but important detail: you flip the inequality sign whenever you multiply or divide the inequality by a negative<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span style=\"text-decoration: underline;\">Symbols used in inequalities or Inequalities Signs<\/span><\/h2>\n\n\n\n<p>The symbol <strong>&lt;<\/strong> means less than. The symbol > means greater than.<br>The symbol <strong>&lt;<\/strong> with a bar underneath means less than or equal to. Usually, this is written as\u00a0$\\leq$<br>The symbol > with a bar underneath means greater than or equal to. Usually, this is written as $\\geq\u00a0$<\/p>\n\n\n\n<p>The symbol $\\ne $ means the quantities on the left and right sides are not equal<br>Examples<br>a &lt; b means a is less than b or b is greater a<\/p>\n\n\n\n<p>a\u00a0\u00a0$\\leq$ b means a is less than or equal to b<\/p>\n\n\n\n<p>a &gt; b means a is greater than b<br>a&nbsp;$\\geq $ b means a is greater or equal to b<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Inequalities Rules<\/h2>\n\n\n\n<p>It can be divided into part<\/p>\n\n\n\n<p>a. Things which can be done in inequality and it does change the sign<\/p>\n\n\n\n<p>b. Things which change the sign of the inequality<\/p>\n\n\n\n<p><span style=\"text-decoration: underline;\">Things are which are safe to do in inequality which does not change in direction<\/span><\/p>\n\n\n\n<p>1. addition of same number on both sides<\/p>\n\n\n\n<p>$a &gt; b$<\/p>\n\n\n\n<p>$a+c &gt; b +c$<\/p>\n\n\n\n<p>2. Subtraction of same number on both sides<\/p>\n\n\n\n<p>$a &gt; b$<\/p>\n\n\n\n<p>$a-c &gt; b-c$<br>3. Multiplication\/Division by same positive number on both sides<br>$a &gt; b$<br>if c is positive number then<br>$ac &gt; bc$<br>or<br>$ \\frac {a}{c} &gt; \\frac {b}{c}$<\/p>\n\n\n\n<p><span style=\"text-decoration: underline;\">Things which changes the direction of the inequality<\/span><\/p>\n\n\n\n<p>1. swapping the left and right sides<\/p>\n\n\n\n<p>$a &gt;&nbsp; b$<\/p>\n\n\n\n<p>$b &lt; a$<\/p>\n\n\n\n<p>2. Multiplication\/Division by negative number on both sides<\/p>\n\n\n\n<p>$a &gt; b $<\/p>\n\n\n\n<p>$ -a &lt; -b $<\/p>\n\n\n\n<p>3. Don&#8217;t multiple by a variable whose values you don&#8217;t know as you don&#8217;t know the nature of the variable<\/p>\n\n\n\n<p>Another Important Concept which we must keep in mind while work on inequalities is a Number line<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span style=\"text-decoration: underline;\">Concept Of Number line<\/span><\/h2>\n\n\n\n<p>A number line is a horizontal line that has points that correspond to numbers. The points are spaced according to the value of the number they correspond to; in a number line containing only whole numbers or integers, the points are equally spaced.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter\"><a href=\"https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2014\/10\/numberline.png\"><img loading=\"lazy\" decoding=\"async\" width=\"452\" height=\"132\" src=\"https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2014\/10\/numberline.png\" alt=\"how to solve inequalities\" class=\"wp-image-2423\" srcset=\"https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2014\/10\/numberline.png 452w, https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2014\/10\/numberline-300x88.png 300w, https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2014\/10\/numberline-150x44.png 150w\" sizes=\"auto, (max-width: 452px) 100vw, 452px\" \/><\/a><\/figure><\/div>\n\n\n\n<p>It is very useful in solving problems related to inequalities and also representing it<\/p>\n\n\n\n<p>Suppose x >2(1\/ 3), this can represent this on a number line like that<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter\"><a href=\"https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2014\/10\/graph_numberline.png\"><img loading=\"lazy\" decoding=\"async\" width=\"381\" height=\"162\" src=\"https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2014\/10\/graph_numberline.png\" alt=\"graph_numberline\" class=\"wp-image-2422\" srcset=\"https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2014\/10\/graph_numberline.png 381w, https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2014\/10\/graph_numberline-300x127.png 300w\" sizes=\"auto, (max-width: 381px) 100vw, 381px\" \/><\/a><figcaption>how to solve inequalities<\/figcaption><\/figure><\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><span style=\"text-decoration: underline;\">How to solve inequalities questions in one variable<\/span><\/h2>\n\n\n\n<p>We will check out how to solve inequalities for both Linear, Quadratic and Rational Fraction <\/p>\n\n\n\n<p>(1)<strong>Simplify the Linear inequality&nbsp;<\/strong><\/p>\n\n\n\n<p>$x- 2 &gt; 2x+15$<br>$-15 -2 &gt; 2x -x $<br>$ -17 &gt; x$<br>$ x &lt; -17$<\/p>\n\n\n\n<p>(<strong>2) Simplify the quadratic inequalities<\/strong><\/p>\n\n\n\n<p>x<sup>2<\/sup>-5x+6 &gt; 0<br>Which can be simplified as<br>(x-2)(x-3) &gt; 0<\/p>\n\n\n\n<p>or this can be done using the equal sign in inequalities and solve it to find endpoints i,e 2, and 3 in the above case.<\/p>\n\n\n\n<p>Now plot those points on the Number line clearly<\/p>\n\n\n\n<p>Now start from the left of most left point on the Number line and look out the if inequalities look good or not. Check for greater,less than, and inequalities at all the endpoints<\/p>\n\n\n\n<p>So in the above case of<br>x<sup>2<\/sup>-5x+6 > 0<\/p>\n\n\n\n<p>We have two ends points 2,3<\/p>\n\n\n\n<p><em><span style=\"text-decoration: underline;\">Case 1<\/span><\/em><\/p>\n\n\n\n<p>So for x &lt; 2 ,Let take x=1,then (1-2)(1-3) &gt; 0<br>2 &gt; 0<\/p>\n\n\n\n<p>So it is good<br>So This inequalities is good for x &lt; 2<\/p>\n\n\n\n<p><em><span style=\"text-decoration: underline;\">Case 2<\/span><\/em><\/p>\n\n\n\n<p>Now for x =2,it makes it zero,so not true. Now takes the case of x &gt; 2 but less 3.Lets takes 2.5<br>(2.5-2)(2.5-3) &gt; 0<br>-.25 &gt; 0<\/p>\n\n\n\n<p>This is not true so this solution is not good<\/p>\n\n\n\n<p><em><span style=\"text-decoration: underline;\">Case 3<\/span><\/em><\/p>\n\n\n\n<p>Now lets take the right most part i.e x &gt; 3<br>Lets take x=4<br>(4-2)(4-3) &gt; 0<br>2&gt; 0<\/p>\n\n\n\n<p>So it is good.<\/p>\n\n\n\n<p>Now the solution can either be represented on a number line or we can say like this<br>$(-\\infty,2)\\cup (3,\\infty)$<\/p>\n\n\n\n<p>(<strong>3)&nbsp; Simplify the rational or fractional inequality<\/strong><\/p>\n\n\n\n<p>$ \\frac {(x &#8211; 3)}{(x + 5)} &gt; 0$<\/p>\n\n\n\n<p><strong>Solution<\/strong><\/p>\n\n\n\n<p><em><span style=\"text-decoration: underline;\">Method A<\/span><\/em><\/p>\n\n\n\n<p>(1) Let&#8217;s find the endpoints of the equation<\/p>\n\n\n\n<p>Here it is clearly<br>x=3 and x=-5<\/p>\n\n\n\n<p>(2) Now plots them on the Number line<\/p>\n\n\n\n<p>(3) Now let&#8217;s start from the left part of the most left number<br>i.e<\/p>\n\n\n\n<p>case 1<br>x &lt; -5 ,Let takes x=-6 (-6-3)\/(-6+5) &gt; 0<br>3 &gt; 0<\/p>\n\n\n\n<p>So it is good<\/p>\n\n\n\n<p>Case 2<br>Now take x=-5<\/p>\n\n\n\n<p>as x+5 becomes zero and we cannot have zero in denominator,it is not the solution<\/p>\n\n\n\n<p>Case 3<br>Now x &gt; -5 and x &lt; 3, lets take x=1 (1-3)\/(1+5) &gt; 0<br>-1\/6 &gt; 0<\/p>\n\n\n\n<p>Which is not true<\/p>\n\n\n\n<p>Case 4<br>Now take x =3,then<br>0&gt; 0 ,So this is also not true<\/p>\n\n\n\n<p>case 5<br>x&gt; 3 ,Lets x=4<br>(4-3)(4+5) &gt; 0<br>1\/9 &gt; 0<\/p>\n\n\n\n<p>So this is good<\/p>\n\n\n\n<p>So the solution is<br>x &lt; -5 or x &gt; 3<br>or<\/p>\n\n\n\n<p>$(-\\infty,-5)\\cup (3,\\infty)$<\/p>\n\n\n\n<p><span style=\"text-decoration: underline;\">Method B<\/span><\/p>\n\n\n\n<p>(1) the numerator and denominator must have the same sign. Therefore, either<\/p>\n\n\n\n<p>x &#8211; 3 &gt; 0 and x + 5 &gt; 0,<\/p>\n\n\n\n<p>or<\/p>\n\n\n\n<p>(2) x &#8211; 3 &lt; 0 and x + 5 &lt; 0. <br><br>Now, (1) implies x &gt; 3 and x &gt; -5.<\/p>\n\n\n\n<p>Which numbers are these that are both greater than 3 and greater than -5?<\/p>\n\n\n\n<p>Clearly, any number greater than 3 will also be greater than -5. Therefore, 1) has the solution<\/p>\n\n\n\n<p>x &gt; 3.<\/p>\n\n\n\n<p>Next, (2) implies<\/p>\n\n\n\n<p>x &lt; 3 and x &lt; -5.<\/p>\n\n\n\n<p>Which numbers are these that are both less than 3 and less than -5?<\/p>\n\n\n\n<p>Clearly, any number less than -5 will also be less than 3. Therefore, (2) has the solution<\/p>\n\n\n\n<p>x &lt; -5.<\/p>\n\n\n\n<p>The solution, therefore, is<\/p>\n\n\n\n<p>x &lt; -5 or x &gt; 3<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span style=\"text-decoration: underline;\">Some Important points to note<\/span><\/h2>\n\n\n\n<p>1) We cannot have zero in denominator<br>2) We should be checking for inequalities at all the end points<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span style=\"text-decoration: underline;\">Some Problems to practice<\/span><\/h2>\n\n\n\n<p>1. $2x &gt; 9$<br>2. $x + 5 &gt; 111$<br>3. $3x &lt; 4$<br>4.&nbsp; $2(x + 3) &lt; x+ 1$<br>5. $x^2 -1 &lt; 0$<br>6. $\\frac {x-1}{x+5} &lt; 0$<br>7. $x^2 -5x + 6 &gt; 0$<br>8. $\\frac {x-5}{x+1} &lt; 0$<\/p>\n\n\n\n<p><strong>Related Articles<\/strong><br><a rel=\"noopener noreferrer\" href=\"https:\/\/physicscatalyst.com\/article\/functions-important-solved-problems-jee-maths\/\" >IIT jee questions on relations and functions<\/a><br><a rel=\"noopener noreferrer\" href=\"https:\/\/physicscatalyst.com\/article\/super-quick-maths-calculation-vedic-method\/\" >Vedic maths tricks<\/a><br><a rel=\"noopener noreferrer\" href=\"https:\/\/physicscatalyst.com\/article\/how-to-tame-mathematics\/\" >how to study maths<\/a><br><a rel=\"noopener noreferrer\" href=\"https:\/\/physicscatalyst.com\/article\/how-to-solve-assertion-reason-questions\/\" >how to solve assertion reason questions<\/a><br><a href=\"https:\/\/physicscatalyst.com\/article\/trigonometric-table-from-0-to-360-cos-sin-cot-tan-sec-cosec\/\">sin cos tan table<\/a><br><a href=\"https:\/\/en.wikipedia.org\/wiki\/Inequality_(mathematics)\">https:\/\/en.wikipedia.org\/wiki\/Inequality_(mathematics)<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is inequalities<br \/>\n In mathematics, an inequality is a relation that holds between two values when they are different<br \/>\n Solving linear inequalities is very similar to solving linear equations, except for one small but important detail: you flip the inequality sign whenever you multiply or divide the inequality by a negative<\/p>\n<p>Symbols used in inequalities<\/p>\n<p>The symbol < means less than. The symbol > means greater than.<br \/>\n The symbol < with a bar underneath means less than or equal to. Usually this is written as ?\n\nThe symbol > with a bar underneath means greater than or equal to. Usually this is written as ?<br \/>\n The symbol ? means the quatities on left and right side are not equal<\/p>\n","protected":false},"author":8,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_uag_custom_page_level_css":"","site-sidebar-layout":"default","site-content-layout":"default","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center 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center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[37],"tags":[],"class_list":["post-2421","post","type-post","status-publish","format-standard","hentry","category-tips-and-tricks"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.5 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>How to solve inequalities in Mathematics - physicscatalyst&#039;s Blog<\/title>\n<meta name=\"description\" content=\"How to Solve inequalities questions in mathematics, Solving quadratic inequalities,solving inequalities in one variable, Tricks to solve it\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/physicscatalyst.com\/article\/how-to-solve-inequalities-in-mathematics\/\" \/>\n<meta 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is inequalities In mathematics, an inequality is a relation that holds between two values when they are different Solving linear inequalities is very similar to solving linear equations, except for one small but important detail: you flip the inequality sign whenever you multiply or divide the inequality by a negative Symbols used in inequalities&hellip;","_links":{"self":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts\/2421","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/users\/8"}],"replies":[{"embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/comments?post=2421"}],"version-history":[{"count":2,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts\/2421\/revisions"}],"predecessor-version":[{"id":6801,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts\/2421\/revisions\/6801"}],"wp:attachment":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/media?parent=2421"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/categories?post=2421"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/tags?post=2421"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}