![\"Dimension](\"https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2019\/11\/Dimension-Of-Momentum.png\")
<\/figure><\/div>\n\n\n\nDimensional Formula of Momentum<\/strong><\/span><\/center><\/h2>\nwith its Derivation<\/strong><\/span><\/center><\/p>\n
\n\n\n\nIn this article, we will find the dimension of Momentum<\/p>\n\n\n\n
Dimensional formula for Momentum is<\/p>\n\n\n\n
$[M^1L^2T^{-1}]$<\/p>\n\n\n\n
Where
M<\/strong> -> Mass<\/p>\n\n\n\nL<\/strong> -> Length<\/p>\n\n\n\nT<\/strong> -> Time
We would now derive this dimensional formula.<\/p>\n\n\n\nDerivation for expression of Dimension of Momentum<\/h3>\n\n\n\n
Momentum is defined as the product for mass and Velocity
$p= mv$
Where
m -> mass
v-> Velocity
p->Momentum <\/p>\n\n\n\n
So,
Now the dimension of Mass= $[M^1]$
Lets derive the dimension of Velocity
$v= \\frac {dx}{dt}$
or
$v = \\frac {d}{t}$
Now
Where
d-> displacement
t -> Time<\/p>\n\n\n\n
Now Dimension of Displacement = $[L^1]$<\/p>\n\n\n\n
Hence dimension of Velocity= $\\frac {[L^1]}{[T^1]}=[M^0 L^1T^{-1}]$
So, Dimension of Momentum is given by<\/p>\n\n\n\n
$\\text {Dimension of Momentum} =[M^1] \\times [M^0 L^1T^{-1}] = [M^1L^1T^{-1}]$<\/p>\n\n\n\n
Unit of Momentum is Kg m\/s and it is denoted by letter $p$<\/p>\n\n\n\n
Try the free Quiz given below to check your knowledge of Dimension Analysis:-<\/p>\n\n\n\n
\nQuiz on Dimensional Analysis<\/strong><\/span><\/h4>\n
\n
\n\n\n\n
In this article, we will find the dimension of Momentum<\/p>\n\n\n\n
Dimensional formula for Momentum is<\/p>\n\n\n\n
$[M^1L^2T^{-1}]$<\/p>\n\n\n\n
Where L<\/strong> -> Length<\/p>\n\n\n\n T<\/strong> -> Time Momentum is defined as the product for mass and Velocity So, Now Dimension of Displacement = $[L^1]$<\/p>\n\n\n\n Hence dimension of Velocity= $\\frac {[L^1]}{[T^1]}=[M^0 L^1T^{-1}]$ $\\text {Dimension of Momentum} =[M^1] \\times [M^0 L^1T^{-1}] = [M^1L^1T^{-1}]$<\/p>\n\n\n\n Unit of Momentum is Kg m\/s and it is denoted by letter $p$<\/p>\n\n\n\n Try the free Quiz given below to check your knowledge of Dimension Analysis:-<\/p>\n\n\n\n
M<\/strong> -> Mass<\/p>\n\n\n\n
We would now derive this dimensional formula.<\/p>\n\n\n\nDerivation for expression of Dimension of Momentum<\/h3>\n\n\n\n
$p= mv$
Where
m -> mass
v-> Velocity
p->Momentum <\/p>\n\n\n\n
Now the dimension of Mass= $[M^1]$
Lets derive the dimension of Velocity
$v= \\frac {dx}{dt}$
or
$v = \\frac {d}{t}$
Now
Where
d-> displacement
t -> Time<\/p>\n\n\n\n
So, Dimension of Momentum is given by<\/p>\n\n\n\n
\nQuiz on Dimensional Analysis<\/strong><\/span><\/h4>\n
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