{"id":5772,"date":"2019-11-17T23:55:16","date_gmt":"2019-11-17T18:25:16","guid":{"rendered":"https:\/\/physicscatalyst.com\/article\/?p=5772"},"modified":"2022-11-04T12:06:29","modified_gmt":"2022-11-04T06:36:29","slug":"what-is-the-dimension-of-momentum","status":"publish","type":"post","link":"https:\/\/physicscatalyst.com\/article\/what-is-the-dimension-of-momentum\/","title":{"rendered":"What is the Dimension of Momentum"},"content":{"rendered":"\n
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\"Dimension<\/figure><\/div>\n\n\n\n

Dimensional Formula of Momentum<\/strong><\/span><\/center><\/h2>\n

with its Derivation<\/strong><\/span><\/center><\/p>\n
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In this article, we will find the dimension of Momentum<\/p>\n\n\n\n

Dimensional formula for Momentum is<\/p>\n\n\n\n

$[M^1L^2T^{-1}]$<\/p>\n\n\n\n

Where
M<\/strong> -> Mass<\/p>\n\n\n\n

L<\/strong> -> Length<\/p>\n\n\n\n

T<\/strong> -> Time
We would now derive this dimensional formula.<\/p>\n\n\n\n

Derivation for expression of Dimension of Momentum<\/h3>\n\n\n\n

Momentum is defined as the product for mass  and Velocity
$p= mv$
Where
m -> mass
v-> Velocity
p->Momentum <\/p>\n\n\n\n

So,
Now the dimension of Mass= $[M^1]$
Lets derive the dimension of Velocity
$v= \\frac {dx}{dt}$
or
$v = \\frac {d}{t}$
Now
Where
d-> displacement
t -> Time<\/p>\n\n\n\n

Now Dimension of Displacement = $[L^1]$<\/p>\n\n\n\n

Hence dimension of Velocity= $\\frac {[L^1]}{[T^1]}=[M^0 L^1T^{-1}]$

So, Dimension of Momentum is given by<\/p>\n\n\n\n

$\\text {Dimension of Momentum} =[M^1] \\times [M^0 L^1T^{-1}] = [M^1L^1T^{-1}]$<\/p>\n\n\n\n

Unit of Momentum is Kg m\/s and it is denoted by letter $p$<\/p>\n\n\n\n

Try the free Quiz given below to check your knowledge of Dimension Analysis:-<\/p>\n\n\n\n

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Quiz on Dimensional Analysis<\/strong><\/span><\/h4>\n
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