{"id":7755,"date":"2023-03-25T12:10:00","date_gmt":"2023-03-25T06:40:00","guid":{"rendered":"https:\/\/physicscatalyst.com\/article\/?p=7755"},"modified":"2024-04-06T15:06:16","modified_gmt":"2024-04-06T09:36:16","slug":"activity-1-4-class-10-science","status":"publish","type":"post","link":"https:\/\/physicscatalyst.com\/article\/activity-1-4-class-10-science\/","title":{"rendered":"Activity 1.4 class 10 science"},"content":{"rendered":"\n

Activity 1.4: Ncert book Science class 10<\/h2>\n\n\n\n

Activity 1.4 of Class 10 Science<\/a>\u00a0NCERT book chapter demonstrates an exothermic reaction involving calcium oxide and water, resulting in the formation of slaked lime. This article will help you understand the reaction and answering the question posed in the activity.<\/p>\n\n\n\n

Activity 1.4 in Class 10 Science NCERT Book: Experimenting with Calcium Oxide<\/h2>\n\n\n\n

Materials Required for Activity 1.4 class 10 science<\/h3>\n\n\n\n

To perform Activity 1.4, you will need the following materials:<\/p>\n\n\n\n

    \n
  1. A small amount of calcium oxide (quicklime)<\/li>\n\n\n\n
  2. Water<\/li>\n\n\n\n
  3. A beaker<\/li>\n\n\n\n
  4. Safety goggles and gloves<\/li>\n<\/ol>\n\n\n\n

    Procedure<\/h3>\n\n\n\n

    Follow these steps to perform Activity 1.4:<\/p>\n\n\n\n

      \n
    1. Place a small amount of calcium oxide (quicklime) in the beaker.<\/li>\n\n\n\n
    2. Slowly add water to the quicklime in the beaker. Observe the reaction carefully.<\/li>\n\n\n\n
    3. Touch the beaker gently to feel any change in temperature.<\/li>\n<\/ol>\n\n\n\n
      \"Activity<\/a>
      Formation of slaked lime by the reaction of calcium oxide with water (Figure Source NCERT Book<\/a>)<\/figcaption><\/figure>\n\n\n\n

      Observations<\/h3>\n\n\n\n

      As you add water to the calcium oxide in the beaker, you will witness a chemical reaction between the two substances. This reaction produces calcium hydroxide, commonly known as slaked lime, and releases heat. The equation for this reaction is as follows:<\/p>\n\n\n\n

      $CaO (s) + H_2O (l) \\rightarrow Ca(OH)_2 (aq)+Heat$<\/p>\n\n\n\n

      Since heat is released during the reaction, you will feel the beaker getting warmer when you touch it. This indicates an exothermic reaction, where heat is released as a byproduct.<\/p>\n\n\n\n

      Answering the Question<\/h3>\n\n\n\n

      The question in the activity asks <\/p>\n\n\n\n

      Whether you feel any change in temperature when you touch the beaker.?<\/strong><\/p>\n\n\n\n

      The answer is yes; you will feel the beaker getting warmer due to the exothermic nature of the reaction. The heat released during the reaction causes the temperature change.<\/p>\n\n\n\n

      Conclusion<\/h3>\n\n\n\n

      This demonstrates the formation of slaked lime by the reaction of calcium oxide with water. This exothermic reaction releases heat, causing a temperature change that can be felt when touching the beaker. <\/p>\n\n\n\n

      Related Study Material<\/h4>\n\n\n\n
      Chemical Reactions and Equations Class 10 NCERT Solutions<\/a><\/td>Chemical reactions and equations Class 10 Notes<\/a><\/td><\/tr>
      Important Questions for chemical reactions and equations Class 10 science<\/a><\/td>chemical reactions and equations class 10 questions answers<\/a><\/td><\/tr>
      Chemical Reactions and Equations Online Test<\/a><\/td>chemical reactions and equations class 10 mcq<\/a><\/td><\/tr>
      Activity 1.1 class 10 science<\/a><\/td>Activity 1.2 class 10 science<\/a><\/td><\/tr>
      Activity 1.3 class 10 science<\/a><\/td>Activity 1.4 class 10 science<\/a><\/td><\/tr>
      Activity 1.5 for class 10 science<\/a><\/td>Activity 1.6 Class 10 Science<\/a><\/td><\/tr>
      Activity 1.7 Class 10 Science<\/a><\/td>Activity 1.8 class 10 science<\/a><\/td><\/tr>
      Activity 1.9 for class 10 science<\/a><\/td>Activity 1.10 Class 10 Science<\/a><\/td><\/tr>
      Activity 1.11 Class 10 science<\/a><\/td>Chemical reactions and equations online quiz<\/a><\/td><\/tr><\/tbody><\/table><\/figure>\n","protected":false},"excerpt":{"rendered":"

      Activity 1.4: Ncert book Science class 10 Activity 1.4 of Class 10 Science\u00a0NCERT book chapter demonstrates an exothermic reaction involving calcium oxide and water, resulting in the formation of slaked lime. This article will help you understand the reaction and answering the question posed in the activity. Activity 1.4 in Class 10 Science NCERT Book: […]<\/p>\n","protected":false},"author":8,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_uag_custom_page_level_css":"","site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[491],"tags":[],"class_list":["post-7755","post","type-post","status-publish","format-standard","hentry","category-class-10-science"],"yoast_head":"\nActivity 1.4 class 10 science - 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This article will help you understand the reaction and answering the question posed in the activity. Activity 1.4 in Class 10 Science NCERT Book:…","_links":{"self":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts\/7755","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/users\/8"}],"replies":[{"embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/comments?post=7755"}],"version-history":[{"count":7,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts\/7755\/revisions"}],"predecessor-version":[{"id":9096,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts\/7755\/revisions\/9096"}],"wp:attachment":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/media?parent=7755"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/categories?post=7755"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/tags?post=7755"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}