{"id":8648,"date":"2024-01-06T20:05:26","date_gmt":"2024-01-06T14:35:26","guid":{"rendered":"https:\/\/physicscatalyst.com\/article\/?p=8648"},"modified":"2024-01-06T20:05:37","modified_gmt":"2024-01-06T14:35:37","slug":"derivatives-of-hyperbolic-functions","status":"publish","type":"post","link":"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/","title":{"rendered":"Derivatives of hyperbolic functions"},"content":{"rendered":"\n<p>The derivatives of the hyperbolic functions are quite straightforward and somewhat analogous to the derivatives of their trigonometric counterparts. Here are the derivatives for the six primary hyperbolic functions:<\/p>\n\n\n\n<p><strong>(1) Hyperbolic Sine $sinh$:<\/strong><br>$$<br>\\frac{d}{dx} \\sinh(x) = \\cosh(x)<br>$$<br>The derivative of hyperbolic sine is hyperbolic cosine.<\/p>\n\n\n\n<p><strong>Proof<\/strong><br>The hyperbolic sine and cosine functions are defined as follows:<\/p>\n\n\n\n<p>$$<br>\\sinh(x) = \\frac{e^x &#8211; e^{-x}}{2}<br>$$<br>$$<br>\\cosh(x) = \\frac{e^x + e^{-x}}{2}<br>$$<\/p>\n\n\n\n<p>Now,<\/p>\n\n\n\n<p>$$<br>\\frac{d}{dx} \\sinh(x) = \\frac{d}{dx} \\left(  \\frac{e^x &#8211; e^{-x}}{2} \\right)<br>$$<\/p>\n\n\n\n<p>$$<br>= \\frac{1}{2}\\left(  \\frac{d}{dx}(e^x) &#8211; \\frac{d}{dx}(e^{-x})\\right)<br>$$<\/p>\n\n\n\n<p>$$<br>= \\frac{1}{2}(e^x + e^{-x})<br>$$<\/p>\n\n\n\n<p>This is the definition of $\\cosh(x)$:<\/p>\n\n\n\n<p>$$<br>= \\cosh(x)<br>$$<\/p>\n\n\n\n<p><strong>(2) Hyperbolic Cosine $cosh$:<\/strong><br>$$<br>\\frac{d}{dx} \\cosh(x) = \\sinh(x)<br>$$<br>The derivative of hyperbolic cosine is hyperbolic sine.<\/p>\n\n\n\n<p><strong>Proof<\/strong><br>The hyperbolic sine and cosine functions are defined as follows:<\/p>\n\n\n\n<p>$$<br>\\sinh(x) = \\frac{e^x &#8211; e^{-x}}{2}<br>$$<br>$$<br>\\cosh(x) = \\frac{e^x + e^{-x}}{2}<br>$$<\/p>\n\n\n\n<p>Now,<\/p>\n\n\n\n<p>$$<br>\\frac{d}{dx}\\cosh(x) = \\frac{d}{dx}\\left(  \\frac{e^x + e^{-x}}{2}\\right)<br>$$<\/p>\n\n\n\n<p>$$<br>= \\frac{1}{2}\\left(  \\frac{d}{dx}(e^x) + \\frac{d}{dx}(e^{-x})\\right)<br>$$<\/p>\n\n\n\n<p>$$<br>= \\frac{1}{2}(e^x &#8211; e^{-x})<br>$$<\/p>\n\n\n\n<p>This is the definition of $\\sinh(x)$:<\/p>\n\n\n\n<p>$$<br>= \\sinh(x)<br>$$<\/p>\n\n\n\n<p><strong>(3) Hyperbolic Tangent $tanh$:<\/strong><br>$$<br>\\frac{d}{dx} \\tanh(x))= sech^2(x)<br>$$<br>The derivative of hyperbolic tangent is the square of hyperbolic secant.<\/p>\n\n\n\n<p><strong>Proof<\/strong><br>$$<br>\\frac{d}{dx}\\tanh(x) = \\frac{d}{dx}\\left( \\frac{\\sinh(x)}{\\cosh(x)}\\right) = \\frac{\\cosh(x) \\frac{d}{dx} \\sinh(x)) &#8211; \\sinh(x)\\frac{d}{dx} \\cosh(x))}{\\cosh^2(x)}<br>$$<\/p>\n\n\n\n<p>We know that  $\\frac{d}{dx} \\sinh(x) = \\cosh(x)$ and $\\frac{d}{dx} \\cosh(x) = \\sinh(x)$, so substituting these in gives:<\/p>\n\n\n\n<p>$$<br>= \\frac{\\cosh(x)\\cosh(x) &#8211; \\sinh(x)\\sinh(x)}{\\cosh^2(x)}<br>$$<\/p>\n\n\n\n<p>Simplifying the numerator:<\/p>\n\n\n\n<p>$$<br>= \\frac{\\cosh^2(x) &#8211; \\sinh^2(x)}{\\cosh^2(x)}<br>$$<\/p>\n\n\n\n<p>Using the identity \\$cosh^2(x) &#8211; \\sinh^2(x) = 1$, we get:<\/p>\n\n\n\n<p>$$<br>= \\frac{1}{\\cosh^2(x)}<br>$$<\/p>\n\n\n\n<p>$$<br>\\frac{d}{dx} \\tanh(x)) = sech^2(x)<br>$$<\/p>\n\n\n\n<p><strong>(4) Hyperbolic Cotangent $coth$:<\/strong><br>$$<br>\\frac{d}{dx} \\coth(x) = -csch^2(x)<br>$$<br>The derivative of hyperbolic cotangent is the negative square of hyperbolic cosecant.<br><strong>Proof<\/strong><\/p>\n\n\n\n<p>$$<br>\\frac{d}{dx} \\coth(x)= \\frac{d}{dx}\\left( \\frac{\\cosh(x)}{\\sinh(x)}\\right) = \\frac{\\sinh(x)\\frac{d}{dx} \\cosh(x)) &#8211; \\cosh(x)\\frac{d}{dx} \\sinh(x))}{\\sinh^2(x)}<br>$$<\/p>\n\n\n\n<p>We know that $\\frac{d}{dx} \\cosh(x)) = \\sinh(x)$ and $\\frac{d}{dx}\\sinh(x)) = \\cosh(x)$, so substituting these in gives:<\/p>\n\n\n\n<p>$$<br>= \\frac{\\sinh(x)\\sinh(x) &#8211; \\cosh(x)\\cosh(x)}{\\sinh^2(x)}<br>$$<\/p>\n\n\n\n<p>$$<br>= \\frac{\\sinh^2(x) &#8211; \\cosh^2(x)}{\\sinh^2(x)}<br>$$<\/p>\n\n\n\n<p>Using the identity $\\cosh^2(x) &#8211; \\sinh^2(x) = 1$, we can rewrite the numerator as -1<\/p>\n\n\n\n<p>$$<br>= \\frac{-1}{\\sinh^2(x)}<br>$$<\/p>\n\n\n\n<p>$$<br>\\frac{d}{dx}$coth(x)) = -csch^2(x)<br>$$<\/p>\n\n\n\n<p>This completes the proof.<\/p>\n\n\n\n<p><strong>(5) Hyperbolic Secant $sech$:<\/strong><br>$$<br>\\frac{d}{dx}(sech(x) = -sech(x)\\tanh(x)<br>$$<br>The derivative of hyperbolic secant involves both hyperbolic secant and hyperbolic tangent.<\/p>\n\n\n\n<p><strong>Proof<\/strong><\/p>\n\n\n\n<p>$$<br>\\frac{d}{dx} sech(x) = \\frac{d}{dx}\\left( \\frac{1}{\\cosh(x)}\\right) = \\frac{\\cosh(x)(0) &#8211; 1 \\sinh(x))}{\\cosh^2(x)}<br>$$<\/p>\n\n\n\n<p>$$<br>= \\frac{-\\sinh(x)}{\\cosh^2(x)}<br>$$<\/p>\n\n\n\n<p>Now, we can express $\\sinh(x)$ in terms of $\\tanh(x)$ and $\\cosh(x)$. <\/p>\n\n\n\n<p>Recall that $\\tanh(x) = \\frac{\\sinh(x)}{\\cosh(x)}$, so $\\sinh(x) = \\tanh(x) \\cdot \\cosh(x)$. <\/p>\n\n\n\n<p>Substituting this into our equation:<\/p>\n\n\n\n<p>$$<br>= \\frac{-\\tanh(x) \\cdot \\cosh(x)}{\\cosh^2(x)}<br>$$<\/p>\n\n\n\n<p>$$<br>= -\\tanh(x) \\cdot \\frac{1}{\\cosh(x)}<br>$$<\/p>\n\n\n\n<p>Since $\\frac{1}{\\cosh(x)}$ is  $sech(x)$, we finally have:<\/p>\n\n\n\n<p>$$<br>\\frac{d}{dx}(sech(x)) = -sech(x)\\tanh(x)<br>$$<\/p>\n\n\n\n<p><strong>(6) Hyperbolic Cosecant $csch$:<\/strong><br>$$<br>\\frac{d}{dx}(csch(x) = -csch(x)\\coth(x)<br>$$<br>The derivative of hyperbolic cosecant involves both hyperbolic cosecant and hyperbolic cotangent.<\/p>\n\n\n\n<p><strong>Proof<\/strong><\/p>\n\n\n\n<p>$$<br>\\frac{d}{dx} csch(x) = \\frac{d}{dx}\\left(  \\frac{1}{\\sinh(x)}\\right) = \\frac{\\sinh(x)(0) &#8211; 1 \\cosh(x))}{\\sinh^2(x)}<br>$$<\/p>\n\n\n\n<p>$$<br>= \\frac{-\\cosh(x)}{\\sinh^2(x)}<br>$$<\/p>\n\n\n\n<p>Now, we can express $\\cosh(x)$ in terms of $\\coth(x)$ and $\\sinh(x)$. <\/p>\n\n\n\n<p>Recall that $\\coth(x) = \\frac{\\cosh(x)}{\\sinh(x)}$, so $\\cosh(x) = \\coth(x) \\cdot \\sinh(x)$. <\/p>\n\n\n\n<p>Substituting this into our equation:<\/p>\n\n\n\n<p>$$<br>= \\frac{-\\coth(x) \\cdot \\sinh(x)}{\\sinh^2(x)}<br>$$<\/p>\n\n\n\n<p>$$<br>= -\\coth(x) \\cdot \\frac{1}{\\sinh(x)}<br>$$<\/p>\n\n\n\n<p>Since $\\frac{1}{\\sinh(x)}$ is $csch(x)$, we finally have:<\/p>\n\n\n\n<p>$$<br>\\frac{d}{dx}(csch(x)) = -csch(x)\\coth(x)<br>$$<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The derivatives of the hyperbolic functions are quite straightforward and somewhat analogous to the derivatives of their trigonometric counterparts. Here are the derivatives for the six primary hyperbolic functions: (1) Hyperbolic Sine $sinh$:$$\\frac{d}{dx} \\sinh(x) = \\cosh(x)$$The derivative of hyperbolic sine is hyperbolic cosine. ProofThe hyperbolic sine and cosine functions are defined as follows: $$\\sinh(x) = [&hellip;]<\/p>\n","protected":false},"author":8,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_uag_custom_page_level_css":"","site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"set","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[498],"tags":[],"class_list":["post-8648","post","type-post","status-publish","format-standard","hentry","category-maths"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.3 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Derivatives of hyperbolic functions - physicscatalyst&#039;s Blog<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Derivatives of hyperbolic functions - physicscatalyst&#039;s Blog\" \/>\n<meta property=\"og:description\" content=\"The derivatives of the hyperbolic functions are quite straightforward and somewhat analogous to the derivatives of their trigonometric counterparts. Here are the derivatives for the six primary hyperbolic functions: (1) Hyperbolic Sine $sinh$:$$frac{d}{dx} sinh(x) = cosh(x)$$The derivative of hyperbolic sine is hyperbolic cosine. ProofThe hyperbolic sine and cosine functions are defined as follows: $$sinh(x) = [&hellip;]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/\" \/>\n<meta property=\"og:site_name\" content=\"physicscatalyst&#039;s Blog\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/PhysicsCatalyst\" \/>\n<meta property=\"article:author\" content=\"https:\/\/www.facebook.com\/PhysicsCatalyst\" \/>\n<meta property=\"article:published_time\" content=\"2024-01-06T14:35:26+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2024-01-06T14:35:37+00:00\" \/>\n<meta name=\"author\" content=\"physicscatalyst\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"physicscatalyst\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 minutes\" \/>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Derivatives of hyperbolic functions - physicscatalyst&#039;s Blog","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/","og_locale":"en_US","og_type":"article","og_title":"Derivatives of hyperbolic functions - physicscatalyst&#039;s Blog","og_description":"The derivatives of the hyperbolic functions are quite straightforward and somewhat analogous to the derivatives of their trigonometric counterparts. Here are the derivatives for the six primary hyperbolic functions: (1) Hyperbolic Sine $sinh$:$$frac{d}{dx} sinh(x) = cosh(x)$$The derivative of hyperbolic sine is hyperbolic cosine. ProofThe hyperbolic sine and cosine functions are defined as follows: $$sinh(x) = [&hellip;]","og_url":"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/","og_site_name":"physicscatalyst&#039;s Blog","article_publisher":"https:\/\/www.facebook.com\/PhysicsCatalyst","article_author":"https:\/\/www.facebook.com\/PhysicsCatalyst","article_published_time":"2024-01-06T14:35:26+00:00","article_modified_time":"2024-01-06T14:35:37+00:00","author":"physicscatalyst","twitter_misc":{"Written by":"physicscatalyst","Est. reading time":"3 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/#article","isPartOf":{"@id":"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/"},"author":{"name":"physicscatalyst","@id":"https:\/\/physicscatalyst.com\/article\/#\/schema\/person\/9b302efdc9b32e459cb1e61ab7506d3f"},"headline":"Derivatives of hyperbolic functions","datePublished":"2024-01-06T14:35:26+00:00","dateModified":"2024-01-06T14:35:37+00:00","mainEntityOfPage":{"@id":"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/"},"wordCount":706,"commentCount":0,"publisher":{"@id":"https:\/\/physicscatalyst.com\/article\/#organization"},"articleSection":["Maths"],"inLanguage":"en-US","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/","url":"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/","name":"Derivatives of hyperbolic functions - physicscatalyst&#039;s Blog","isPartOf":{"@id":"https:\/\/physicscatalyst.com\/article\/#website"},"datePublished":"2024-01-06T14:35:26+00:00","dateModified":"2024-01-06T14:35:37+00:00","breadcrumb":{"@id":"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/physicscatalyst.com\/article\/derivatives-of-hyperbolic-functions\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/physicscatalyst.com\/article\/"},{"@type":"ListItem","position":2,"name":"Maths","item":"https:\/\/physicscatalyst.com\/article\/maths\/"},{"@type":"ListItem","position":3,"name":"Derivatives of hyperbolic functions"}]},{"@type":"WebSite","@id":"https:\/\/physicscatalyst.com\/article\/#website","url":"https:\/\/physicscatalyst.com\/article\/","name":"physicscatalyst's Blog","description":"Learn free for class 9th, 10th science\/maths , 12th and IIT-JEE Physics and maths.","publisher":{"@id":"https:\/\/physicscatalyst.com\/article\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/physicscatalyst.com\/article\/?s={search_term_string}"},"query-input":{"@type":"PropertyValueSpecification","valueRequired":true,"valueName":"search_term_string"}}],"inLanguage":"en-US"},{"@type":"Organization","@id":"https:\/\/physicscatalyst.com\/article\/#organization","name":"physicscatalyst","url":"https:\/\/physicscatalyst.com\/article\/","logo":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/physicscatalyst.com\/article\/#\/schema\/logo\/image\/","url":"https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2024\/08\/cropped-logo-1.jpg","contentUrl":"https:\/\/physicscatalyst.com\/article\/wp-content\/uploads\/2024\/08\/cropped-logo-1.jpg","width":96,"height":96,"caption":"physicscatalyst"},"image":{"@id":"https:\/\/physicscatalyst.com\/article\/#\/schema\/logo\/image\/"},"sameAs":["https:\/\/www.facebook.com\/PhysicsCatalyst","https:\/\/x.com\/physicscatalyst","https:\/\/www.youtube.com\/user\/thephysicscatalyst","https:\/\/www.instagram.com\/physicscatalyst\/"]},{"@type":"Person","@id":"https:\/\/physicscatalyst.com\/article\/#\/schema\/person\/9b302efdc9b32e459cb1e61ab7506d3f","name":"physicscatalyst","sameAs":["https:\/\/physicscatalyst.com","https:\/\/www.facebook.com\/PhysicsCatalyst","https:\/\/x.com\/physicscatalyst"]}]}},"uagb_featured_image_src":{"full":false,"thumbnail":false,"medium":false,"medium_large":false,"large":false,"1536x1536":false,"2048x2048":false,"shareaholic-thumbnail":false},"uagb_author_info":{"display_name":"physicscatalyst","author_link":"https:\/\/physicscatalyst.com\/article\/author\/physicscatalyst\/"},"uagb_comment_info":0,"uagb_excerpt":"The derivatives of the hyperbolic functions are quite straightforward and somewhat analogous to the derivatives of their trigonometric counterparts. Here are the derivatives for the six primary hyperbolic functions: (1) Hyperbolic Sine $sinh$:$$\\frac{d}{dx} \\sinh(x) = \\cosh(x)$$The derivative of hyperbolic sine is hyperbolic cosine. ProofThe hyperbolic sine and cosine functions are defined as follows: $$\\sinh(x) =&hellip;","_links":{"self":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts\/8648","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/users\/8"}],"replies":[{"embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/comments?post=8648"}],"version-history":[{"count":6,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts\/8648\/revisions"}],"predecessor-version":[{"id":8654,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/posts\/8648\/revisions\/8654"}],"wp:attachment":[{"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/media?parent=8648"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/categories?post=8648"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physicscatalyst.com\/article\/wp-json\/wp\/v2\/tags?post=8648"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}