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Class 9 Maths NCERT Solution for Linear equation part 1




In this page we have NCERT book Solutions for Class 9th Maths:Linear equation for EXERCISE 1 . Hope you like them and do not forget to like , social share and comment at the end of the page.
Question1:
The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.
(Take the cost of a notebook to be Rs x and that of a pen to be Rs y.)
Solution:
Let cost of notebook and a pen be x and y respectively.
Cost of note book = 2  cost of pen
x = 2y
x - 2 y = 0

Question 2:
Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b, c in each case:
(i) 2x+3y=9.3555555555…
(ii) x-(y/5)-10=0      
(iii) − 2x + 3 y = 6
(iv) x = 3y     (v) 2x = − 5y (vi) 3x + 2 = 0
(vii)      y − 2 = 0        (viii) 5 = 2x
Solution:
( i) 2x+3y=9.3555555555….
=> 2x+3y-9.3555555555…. =0
Comparing this equation with ax + by + c = 0,
a=2 ,b=3  c=-9.355….
(ii)  x-(y/5)-10=0            
Comparing this equation with ax + by + c = 0,
a = 1, b =, -1/5, c = −10

 (iii) − 2x + 3 y = 6
=> − 2x + 3 y − 6 = 0
Comparing this equation with ax + by + c = 0,
a = −2, b = 3, c = −6
(iv)       x = 3y
=> x − 3y + 0 = 0
Comparing this equation with ax + by + c = 0,
a = 1, b = −3, c = 0
(v) 2x = −5y
=> 2x + 5y + 0 = 0
Comparing this equation with ax + by + c = 0,
a = 2, b = 5, c = 0
(vi) 3x + 2 = 0
=> 3x + 0.y + 2 = 0
Comparing this equation with ax + by + c = 0,
a = 3, b = 0, c = 2
(vii) y − 2 = 0
  => y − 2 = 0
Comparing this equation with ax + by + c = 0,
a = 0, b = 1, c = −2
(vii) 5 = 2x
=> − 2x  + 5 = 0
Comparing this equation with ax + by + c = 0,
a = −2, b = 0, c = 5

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