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Activity 1.2 class 10 science – Exploring Chemical Reactions

Class 10 Science Activity 1.2 – Exploring Chemical Reactions


In this article learn about Activity 1.2 class 10 science NCERT book. Chemical reactions are an essential part of our everyday lives. From the food we eat to the air we breathe, everything around us involves chemical reactions.

In Class 10 Science, NCERT Book Chapter 1, “Chemical Reactions and Equations,” students are introduced to various types of chemical reactions and their applications. One such interesting activity that demonstrates the concept of a double displacement reaction is Activity 1.2.

In this article, we will delve into the details of this activity and explore the observations and results of this intriguing experiment.

Activity 1.2 Ncert book Science class 10: Exploring Double Displacement Reactions

Class 10 science activity 1.2 is about chemical reactions and equations. It involves performing experiments with an aqueous solution of lead nitrate and potassium iodide to see what occurs. When these two solutions are mixed together, a yellow precipitate of lead iodide is produced.

The objective of Class 10 Science Activity 1.2

The primary objective of Activity 1.2 is to observe and understand a double displacement reaction. This experiment will demonstrate how the exchange of ions between two compounds results in the formation of a new compound.

Materials Required

  • Lead nitrate solution $(Pb(NO3)_2)$
  • Potassium iodide solution $(KI)$
  • Test tube
  • Test tube holder
  • Dropper


  1. Take a test tube and add a small amount of lead nitrate solution using a dropper.
  2. Now, add potassium iodide solution to the test tube containing lead nitrate solution.
  3. Observe the changes that occur in the test tube.

Observations and Results

Upon adding potassium iodide solution to the lead nitrate solution, a yellow precipitate is formed. This precipitate is lead iodide $(PbI_2)$. The color change is a clear indication of a chemical reaction taking place between the two solutions.


The reaction that takes place in this activity is a double displacement reaction. In a double displacement reaction, the ions of two compounds exchange places to form two new compounds. In this case, lead nitrate $(Pb(NO_3)_2)$ reacts with potassium iodide $(KI)$ to form lead iodide $(PbI_2)$ and potassium nitrate (KNO3).

The balanced chemical equation for this reaction is:

$Pb(NO_3)_2 (aq) + 2 KI (aq) \rightarrow PbI_2 (s) + 2 KNO_3 (aq)$


Activity 1.2 from Class 10 Science NCERT Book Chapter 1 effectively demonstrates a double displacement reaction. The formation of the yellow precipitate, lead iodide, is a clear sign that a chemical reaction has taken place between lead nitrate and potassium iodide. By performing and understanding this activity, students can appreciate the concept of double displacement reactions and their role in various chemical processes.

As students progress through their science education, they will come across numerous examples of chemical reactions and equations. Activities like these not only provide hands-on experience but also enable them to develop a deeper understanding of the subject matter. Remember, the key to mastering chemistry is practice and curiosity, so continue exploring the fascinating world of chemical reactions!

Related Study Material

Activity 1.1 class 10 scienceChemical reactions and equations Class 10 Notes
chemical reactions and equations class 10 mcqChemical Reactions and Equations Class 10 NCERT Solutions

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