Maths

Number 27 is a composite number and we will find how to find the factors of 27. We will also see techniques to find out the Prime factorization of 27 easily Factors of 27 A factor of a number is an exact divisor of that number. So factors of 27 are the numbers which are […]

Number 28 is a composite number and we will find how to find the factors of 28. We will also see techniques to find out the Prime factorization of 28 easily Factors of 28 A factor of a number is an exact divisor of that number. So factors of 28 are the numbers which are

The integral of the cosec square function, $\csc ^2x$, can be found using basic calculus principles. The integral of ($\csc ^2x$) with respect to (x) is: \[\int \csc^2 x \, dx = -\cot x + C\] Here, (C) represents the constant of integration, which is added because the process of integration determines the antiderivative up

we can have three integration of 1 sinx cosx ( integration of 1 /sinx+ cosx , integration of 1 /sinx- cosx and integration of 1 /sinx cosx). Here are formula of these integrals (I) integration of 1 /sinx+ cosx $\int \frac {1}{sinx + cos x} \; dx = \frac {1}{\sqrt{2}} \log \left| \frac {\left(\tan\left(\frac{x}{2}\right) –

The integral of the root x, can be found using power rule. The integral of $\sqrt x $ with respect to (x) is: \[\int \sqrt x \, dx =\frac{2}{3} x^{3/2} + C\] Here, (C) represents the constant of integration, which is added because the process of integration determines the antiderivative up to an arbitrary constant.

This article is about surds questions and follow the link surds in math if you want to know about surds. Here in this article, you can find surds problem-solving questions. Surd Easy Questions Simplify the following Answers (1) $\sqrt{21} \times \sqrt{7}= \sqrt { 3 \times 7 \times 7} = 7 \sqrt 3$(2) $\sqrt{180} = \sqrt

Here are some good Integrals class 12 important questions for Mathematics. Solutions Related Articles find the range of a function

Integration of even function over a symmetric intervalcan be simplified as follows: $\int_{-a}^{a} f(x) \, dx = 2 \int_{0}^{a} f(x) \, dx$ This simplification is possible because the area under the curve from $-a$ to $0$ is the same as the area from $0$ to $a$ due to the symmetry of the function. Example 1$\int_{-a}^{a}