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Ncert Solutions for comparing quantities Class 8 maths Chapter 8 CBSE Part 2



In this page we have NCERT book Solutions for Class 8th Maths:comparing quantities Chapter 8 for EXERCISE 1 . Hope you like them and do not forget to like , social share and comment at the end of the page.
Question 1
 A man got a 10% increase in his salary. If his new salary is Rs 1,54,000, find his original salary.
Answer:
In these questions, there are two parts, First is the original quantity and second part is the % increase in the quantity. The final quantity will be the sum of original quantity and % increase quantity
Let us assume the original salary is y, then
y + 10% of y   = New salary= 154000
y+ 10y/100=154000
11y/10=154000
y=1540000/11= Rs 140000
Question 2
 On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the per cent decrease in the people visiting the Zoo on Monday?
Answer: Actual decrease in number of visits
= 845-169=676
So % decrease
=(676/845)×100=80%
Question 3
 A shopkeeper buys 80 articles for Rs 2,400 and sells them for a profit of 16%. Find the selling price of one article.
Answer:
Cost price of one article= 2400/80=30
Now we know that Profit = CP x % profit
= 30 × (16/100) = 4.80
Now Selling price = Cost Price + Profit
=30 + 4.8 = 34.8
Question 4
 The cost of an article was Rs 15,500. Rs 450 were spent on its repairs. If it is sold for a profit of 15%, find the selling price of the article.
Answer
Final cost price of the article after the repairs will be
CP = Cost + Overheads
= 15500 + 450 = 15950
Profit = CP x % profit
= 15950 × (15/100)= 2392.50
Now Selling price = Cost Price + Profit
= 15950 + 2392.50 = 18342.50
Question 5
 A VCR and TV were bought for Rs 8,000 each. The shopkeeper made a loss of 4% on the VCR and a profit of 8% on the TV. Find the gain or loss percent on the whole transaction.
Answer
Cost price of each article=8000
Now Profile on  TV = Cost price × profit %
=8000 ×(8/100)= 640
Now loss on VCR = Cost price × Loss %
=8000 ×(4/100)= 320
Since profile is more than loss, it gains net profile
Net Profit= 640 -320= 320
Now
Total cost Price of product=16000
So Profit %= (320/16000) ×100
=2%
Question 6
During a sale, a shop offered a discount of 10% on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at Rs 1450 and two shirts marked at Rs 850 each?
Answer:
Total Price of a pair of jeans and two shirts
= 1450 + 2 x 850 = 3150
Discount = Marked Price x % Discount
=3150 × (10/100)=315
Effective Price After Discount = 3150 - 315 = 2835
Question 7
 A milkman sold two of his buffaloes for Rs 20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss.
Answer: Suppose the CP of buffaloes are a and b respectively
After 5% profit, SP = a+ 5a/100 =105a/100
After 10% loss SP = b- 10b/100 =90b/100
Now
105a/100= 20,000
a=20,000×(100/105)
Profit on One buffalo=  SP -  CP =20,000 -20,000×(100/105)
=20000/21=952.385
Now
90b/100= 20,000
b=20,000×(100/90)
Loss on another buffalo=  CP-SP =20,000×(100/90 )- 20,000 =20000/9=2222.222
As Loss is greater than profit, he get net loss
Net loss = 1269.84
Question 8
 The price of a TV is Rs 13,000. The sales tax charged on it is at the rate of 12%. Find the amount that Vinod will have to pay if he buys it.
Answer: Sales Tax = Price x Tax Rate
=13000 × (12/100)=1560
Final Price = 13000 + 1560 = 14560
Question 9
 Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is Rs 1,600, find the marked price.
Answer
Let the marked price be a
So final selling price after discount
=a  - a×(20/100)
=.8a
Now .8a =1600
a=2000
Question 10
 I purchased a hair-dryer for Rs 5,400 including 8% VAT. Find the price before VAT was added.
Answer
Let a be the price before VAT
So selling price = a + a×(8/100)
=1.08a
Now 1.08a=5400
a=5000

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