- Quick Revision of previous class Maths concepts
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- Finding Discounts
- |
- Profit and Loss
- |
- Sales Tax and VAT
- |
- Simple Interest and Compound Interest

In this page we have *NCERT book Solutions for Class 8 Maths Chapter 8:comparing quantities * for
EXERCISE 1 . Hope you like them and do not forget to like , social share
and comment at the end of the page.

Find the ratio of the following.

(a) Speed of a cycle 15 km per hour to the speed of scooter 30 km per hour.

(b) 5 m to 10 km

(c) 50 paise to Rs 5

a)

Required ratio =15/30 =1/2 =1:2

b) Require ratio =5m/10 km

=5m/10×1000m= 1/2000 = 1:2000

c)

Require ratio =50paise/Rs 5

=50paise/500 paise= 1/10 = 1:10

Convert the following ratios to percentages.

(a) 3 : 4

(b) 2 : 3

1) 3:4 =3/4

% can be find by multiplying 100

So %= (¾)× 100= 75%

2) 2:3 =2/3

% can be find by multiplying 100

So %= (2/3)× 100= (200/3)%

72% of 25 students are good in mathematics. How many are not good in mathematics?

Percentage of Students not good in math = 100 - 72 = 28

So No of students not good in Mathematics

=28% of 25 = 28×(25/100)= 7

A football team won 10 matches out of the total number of matches they played. If their win percentage was 40, then how many matches did they play in all?

Let us assume total number of matches = y

Then % of matches win= (10/y)× 100

Now it is given % of matches win=40

So

40=(10/y)× 100

y=(10/40) ×100 =25

If Chameli had Rs 600 left after spending 75% of her money, how much did she have in the beginning?

Let us assume total money = y

Then 25% of y =600

25 ×(y/100)=600

y=2400

Chameli had Rs. 2,400 in the beginning

% of Cricket Fans = 60%

% of Football Fans = 30%

So, Other Sports’ Fans = 100 - (60 + 30) = 10% people like other games.

Now it is given total number of population is 50 Lakh= 50,00,000

So Number of cricket fan

=50,00,000 ×( 60/100) =30,00,000= 30 Lakh

So Number of Football fan

=50,00,000 ×( 30/100) =15,00,000= 15 Lakh

So Number of other games fan

=50,00,000 ×( 10/100) =5,00,000= 5 Lakh

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