Definite integration formulas

Definite Integrals

if  $\int f(x)  dx= g(x)$
$\int_{a}^{b} f(x) dx =g(b) -g(a)$

Properties of Definite Integrals

(I) $\int_{a}^{b} f(x) dx= \int_{a}^{b} f(t) dt $

(II) $\int_{a}^{b} f(x) dx=- \int_{b}^{a} f(x) dx $

(III) $\int_{a}^{b} f(x) dx= \int_{a}^{c} f(x) dx + \int_{c}^{b} f(x) dx  $

where a<c <b

(IV) $\int_{a}^{b} f(x) dx=\int_{a}^{b} f((a+b-x)) dx$

(V) $\int_{0}^{a} f(x) dx=\int_{0}^{a} f((a-x)) dx$

(VI) $\int_{0}^{2a} f(x) dx=\int_{0}^{a} f((x)) dx + \int_{0}^{a} f((2a-x)) dx$

(VII) $\int_{0}^{2a} f(x) dx= \begin{cases}
2 \int_{0}^{a} f(x) dx & ,  f(2a-x) =f(x) \\
0 &, f(2a-x) =-f(x)
\end{cases} $

(VIII) $\int_{-a}^{a} f(x) dx= \begin{cases}
2 \int_{0}^{a} f(x) dx & ,  f(x) =f(-x) \\
0 &, f(x) =-f(x)
\end{cases} $

(IX) $f(x) \geq 0$, then $\int_{a}^{b} f(x) dx \geq 0$

(X) $f(x) \geq g(x) $, then $\int_{a}^{b} f(x) dx \geq \int_{a}^{b} g(x) dx $

(IX) $|\int_{a}^{b} f(x) dx| \leq \int_{a}^{b} |f(x)| dx$

Other formula’s

For any real number $n \neq -1$,
$$
\int_{a}^{b} x^n \, dx = \frac{b^{n+1} – a^{n+1}}{n+1}
$$

$$
\int_{a}^{b} e^x \, dx = e^b – e^a
$$

$$
\int_{1}^{b} \frac{1}{x} \, dx = \ln(b)
$$

$$
\int_{a}^{b} \sin(x) \, dx = -\cos(b) + \cos(a)
$$
$$
\int_{a}^{b} \cos(x) \, dx = \sin(b) – \sin(a)
$$
$$
\int_{a}^{b} \tan(x) \, dx = -\ln|\cos(b)| + \ln|\cos(a)|
$$

A special case using polar coordinates:
$$
\int_{0}^{2\pi} \frac{1}{2} r^2 \, d\theta = \pi r^2
$$

$$
\int_{a}^{\infty} \frac{1}{a^2 + x^2} \, dx = \frac {\pi}{2a}
$$

$$
\int_{a}^{\infty} \frac{1}{\sqrt {a^2 – x^2}} \, dx = \frac {\pi}{2}
$$

$$
\int_{a}^{\infty} \sqrt {a^2 – x^2} \, dx = \frac {\pia^2}{4}
$$