Dimensional Formula of Force with its Derivation
In this article, we will find the dimension of Force
Dimensional formula for is
$[M^1L^1T^{-2}]$
Where
M -> Mass
L -> Length
T -> Time
We would now derive this dimensional formula.
Derivation for expression of Dimension of
As per second laws of Newton law’s, Force is defined as the product of mass and acceleration
$F= ma$
Where m -> Mass of the body
a -> Acceleration of the body
Now the dimension of Mass = $[M^1]$
Lets derive the dimension of Acceleration
Now
$a = \frac {\Delta v}{t}$
Now dimension of Velocity= $[M^0 L^1T^{-1}]$
dimension of Time = $[M^0 T^1]$
So dimension of Acceleration = $ \frac {[M^0 L^1T^{-1}]}{ [M^0 T^1]}= [M^0 L^1T^{-2}]$
Hence Dimension of force is given by
$\text {Dimension of Force} =[M^1] \times [M^0 L^1T^{-2}] = [M^1L^1T^{-2}]$
Unit of Force is Newton
Try the free Quiz given below to check your knowledge of Dimension Analysis:-
Quiz on Dimensional Analysis
Related Articles and references
- Newton’s Law of Motion
- Newton’s Second Law of Motion
- Dimensional Analysis:- a very good website for physics concepts
- Dimensional Formula of Spring constant
- dimension of Density
- dimension of frequency
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