Articles related to class 9, 10, 11, 12 and B.Sc.
On this page find all the formulas you need to remember for motion in a straight line. These are the important formulas if you are in class 11 or preparing for NEET, JEE-Mains or JEE-Advanced.I will attach a downloadable PDF file of this article so that you can print it out for your preparation and […]
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In this article, you will get revision notes for topic motion in a straight-line class 11 notes for physics NCERT book chapter 2. It is important to note here that motion in a straight line is nothing but motion in one dimension. Such a type of motion is also called linear motion or rectilinear motion.
Motion in a Straight Line Class 11 Physics Notes CBSE NCERT Chapter 2 Read More »
We already know the statement of Ohm’s Law which is
“If the physical state of the conductor (Temperature and mechanical strain etc.) remains unchanged, then current flowing through a conductor is always directly proportional to the potential difference across the two ends of the conductor”
Ohm’s Law Verification Read More »
This article will teach you how to find the x and y components of a vector. We already know what vectors and scalars are and how important they are when we study physics. Finding vector components is the opposite of vector addition, where we find vector addition of two or more vectors. Here, a vector
x and y components of a vector Read More »
Download free concise physics formula book containing class 11 and class 12 physics formulas
Download Physics formulas and concepts pdf Read More »
Choose your frame of refrence.KE will differ in each refrence frame while PE will remains constant. Define your system, which may include two or more interacting particles, as well as springs or other systems in which elastic potential energy can bestored. Choose the initial and final points.
How to solve Work And Energy/kinetic energy problems Read More »
Draw a neat diagram of the system.
Firstly consider the origin of the forces acting on the each object.To do this find out the field forces acting on the each object.Wherever contact in available account the contact force carefully
Isolate the body whose motion is to be analyzed. Draw a free-body diagram for this body. For systems containing more than one objects, draw separate free-body diagrams for each objects
How to solve Newton’s Law problems Read More »
TL;DRThe escape velocity formula does not depend on the escaping object’s properties. The only thing that counts is the celestial body’s mass and radius. It is given by the relation$v_e = \sqrt{\frac{2GM}{R}}$ You’ve probably seen rockets launch into space. These rockets need a huge kick or push to leave the earth’s surface. This push is
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