# Class 10 Maths Assignments for Surface Area and Volume

Given below are the Class 10 Maths Assignments for Surface Area and Volume
a) Concepts questions
b) Calculation problems
c) Multiple choice questions
e) Fill in the blank's
1) A solid metallic hemisphere of radius 8 cm is melted and recasted into a right circular cone of base radius 6 cm. Determine the height of the cone.
a) 20 cm
b) 28.44 cm
c) 26.44 cm
d) None of the above
2) Find the volume of the largest right circular cone that can be cut out of a cube whose edge is 9cm.
3) A cone, a hemi-sphere and a cylinder stand on equal bases and have the same height. Find the ratio of their volumes as well
a) 3:2:1
b) 2:4:8
c) 1:2:3
d) 3:9:27
4) Find the ratio of their total surface areas
a) (√2+1):3:4
b) 2:4:8
c) 1:2:3
d) 3:9:27
5) A solid toy is in the form of a hemisphere surmounted by a right circular cone. Height of the one is 2cm and diameter of the base is 4cm. If a right circular cylinder circumscribes the toy, find how much more space it will cover.
6) A hemispherical tank full of water is emptied by a pipe at the rate of 3  litres per second. How much time will it take to make the tank half empty, if the tank is 3m in diameter?
7) A toy is in the shape of a right circular cylinder with a hemisphere at one end and a cone on the other. The radius and height of the cylindrical part are 5cm and 13cm respectively. The radii of the hemispherical and conical parts are the same as that of the cylindrical part. Find the surface area of the toy if the total height of the toy is 30cm
770cm2
8)  True and False
i) Two identical solid hemispheres of equal base radius r cm are stuck together along their bases. The total surface area of the combination is 4πr2.
ii) A solid cylinder of radius r and height h is placed over other cylinder of same height and radius. The total surface area of the shape so formed is 4πrh + 3πr2
iii)  A solid cone of radius r and height h is placed over a solid cylinder having same base radius and height as that of a cone. The total surface area of the combined solid is πr(√(h2 +r2) + r + 2h)
iv). A solid ball is exactly fitted inside the cubical box of side a. The volume of the ball is (4/3)πa3