Dimensional Formula of Voltage
with its Derivation
In this article, we will find the dimension of Voltage
Dimensional formula for Voltage is
Where
M -> Mass
L -> Length
T -> Time
I -> Current
We would now derive this dimensional formula.
Derivation for expression of Dimension of Voltage
Derivation of Voltage can be done with any formula which contains voltage
A. Voltage is defined as Work done per unit Charge
$V= \frac {W}{q} $
Now $W = f \times d$
Dimension of Force = $[M^1 L^1 T^{-2}]$
Dimension of distance = $[L^1]$
So, Dimension of Work done is =$[M^1 L^1 T^{-2}] \times [L^1]=[M^1 L^2 T^{-2}]$
Now charge is given as
$q = I \times t$
Hence Dimension of charge is $[I^1 T^1]$
Now that we know the dimension of work done and charge, dimension of Voltage will be given by
$=\frac {[M^1 L^2 T^{-2}]}{ [I^1 T^1]} = [M^1 L^2 T^{-3} I^{-1}]$
B. Voltage is also defined as
$V= E \times d$
Where E is the electric Field
Now Electric Field is defined as
$E= \frac {F}{q}$
Dimension of Force= $[M^1 L^1 T^{-2}]$
Dimension of charge is $[I^1 T^1]$
So dimension of E = $\frac {[M^1 L^1 T^{-2}]}{[I^1 T^1]}= [M^1 L^1 T^{-3} I^{-1}]$
Hence Dimension of Voltage is given by
$=[M^1 L^1 T^{-3} I^{-1}] \times [L^1]=[M^1 L^2 T^{-3} I^{-1}]$
Unit of Voltage is Volt
Try the free Quiz given below to check your knowledge of Dimension Analysis:-
Quiz on Dimensional Analysis
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