## Introduction

A numerical expression can have multiple operations like addition, subtractions, power, Division, multiplication, Brackets.

Example

15 of 6-[18- { 14-(3+2) }]

Now this is easy to solve like multiple operations on two numbers. We can solve or simplify these types of Numerical expressions using the BODMAS rule.

## What is BODMAS Rule

**BODMAS** is an acronym and it stands for Bracket, Order, Division, Multiplication, Addition and Subtraction. In Canada , it is called as **BEDMAS**(Bracket, Exponents, Division, Multiplication, Addition and Subtraction In United states, it is called **PEMDAS** (Parentheses, Exponents, Multiplication, Division, Addition and Subtraction) These all are synonym of BODMAS.

-B stands for brackets

-O stands for of,orders,square, roots

-D stands for divisions (÷)

-M stands for multiplication (*)

-A stands for addition (+)

-S stands for subtraction (-)

Now let us how to apply the BODMAS rule to solve the numerical expressions

In order to simplify a numerical expression, we follow the conventions given ahead:

(i) we proceed from left to right.

(ii) The order of working is

brackets -> orders(Exponents or powers) -> division & multiplication -> addition & subtraction.

(iii) The order of brackets is:

Expressions inside the brackets are simplified in order to the letters of the word BODMAS.

(iv) Division and multiplication have same precedence,so after brackets and orders are over, we just need to move from left to right doing whichever operations comes first i.e if multiplication comes first,then do multiplication

(v)Similary Addition and subtraction have same precedence,so after brackets ,orders,division and Multiplication are over we just need to move from left to right doing whichever operations comes

## Examples

Lets us see now few Examples

(1) 15 of 6-[18- { 14-(3+2) }]

Applying First the bracket rule

=15 of 6-[18- { 14-5 }]

Applying Again the bracket rule

=15 of 6-[18- 9]

Applying Again the bracket rule

=15 of 6-9

Now Multiplication comes before Subtraction

=90 -9 = 81

(2) $2 \times 5 + 50 \div 2$

Here Multiplication and division have same ran, so we just need to move from left to right doing whichever operations comes first

$=10 + 25$

$=35$

(3) $50 \times 5 \div 10$

Here Multiplication and division have same ran, so we just need to move from left to right doing whichever operations comes first

$=250 \div 10$

=25

(4) $25 \div 5 \times 5$

Here Multiplication and division have same ran, so we just need to move from left to right doing whichever operations comes first

$=5 \times 5$

$=25$

## BODMAS Exercise

(5) 105+[19-{2 of 6+(3-2)}]

## Answer

= 105 + [19 -{2 of 6 + 1}]

=105 + [19 – {12 + 1}]

=105 + [19 -13]

=105 + 6=111

(6) $\frac{5}{9} \div (1\frac{1}{3}+\frac{4}{9})+\frac{3}{8}$

## Answer

$=\frac{5}{9} \div (\frac{4}{3}+\frac{4}{9})+\frac{3}{8}$

Applying the bracket rule

$=\frac{5}{9} \div \frac {16}{9} + \frac{3}{8}$

$=\frac {5}{9} \times \frac {9}{16} + \frac{3}{8}$

$=\frac {5}{16} + \frac{3}{8}$

$=\frac {11}{16}$

(7) $\frac{2}{7} – \frac {1}{6} \ of \ \frac {6}{7} \div \frac {4}{7} – 1\frac {1}{3} + 5$

## Answer

$=\frac{2}{7} – \frac {1}{7} \div \frac {4}{7} – 1\frac {1}{3} + 5$

$=\frac{2}{7} – \frac {1}{4} – \frac {4}{3} + 5$

$=\frac {24 – 21 – 112 + 420}{84}= \frac {311}{84}$

(8) $(105 + 206) – 550 \div 5^2 + 1$

## Answer

$= 311 – 550 \div 5^2 + 1$

$= 311 – 550 \div 25 + 1$

$=311 – 22 + 1$

=290

(9) 1.5{3.9-(4.5-3.2 × 0.5)}

## Answer

= 1.5 { 3.9 – (4.5 – 1.6)}

=1.5 {3.9 – 2.9}

=1.5

(10) 39-[23-{29- (17-9-3)}]

## Answer

=39 – [23 -{29 -5}]

=39 – [23 – 24]=39 + 1= 40

(11) $\frac{2}{3} of (\frac{1}{4}+ \frac {1}{2} + \frac {3}{8}) \div \frac {3}{2}$

## Answer

$=\frac{2}{3} of (\frac {2+ 4 +3}{8}) \div \frac {3}{2}$

$=\frac{2}{3} of (\frac {9}{8}) \div \frac {3}{2}$

$=\frac{2}{3} of \frac {9}{8} \div \frac {3}{2}$

$= \frac {3}{4} \div \frac {3}{2}$

$= \frac {1}{2}$

(12) $\frac {2}{3} – \frac {1}{2} – \frac {1}{3} \ of \frac {1}{2}$

## Answer

$=\frac {2}{3} – \frac {1}{2} -\frac {1}{6}$

=0

(13) $5+ 5 \ of \ 5 \div 5 \ of \ 5 \times 5$

## Answer

$=5+(5 \ of\ 5) \div 5 \ of \ 5 \times 5$

$=5 + 25 \div 5 \ of \ 5 \times 5$

$=5+ 5 \ of\ 5 \times 5$

$=5+ (5 \ of \ 5) \times 5$

$=5+ 25 \times 5$

$=5+125$

$=130$

(14) $\frac {5}{6} – \frac {2}{3} \ of \ \frac {1}{3} + \frac {1}{9}$

## Answer

$=\frac {5}{6} – \frac {2}{9} + \frac {1}{9}$

$=\frac {13}{18}$

**Further Reference**

https://en.wikipedia.org/wiki/Order_of_operations