
Inverse Trigonometric Function Formulas
Inverse Trigonometric Functions are important topic in Trigonometry. Here is detailed list of Inverse Trigonometric Function Formulas
Domain and Range Of Inverse Trigonometric Functions
The value of an inverse trigonometric functions which lies in its principal value branch is called the principal value of that inverse trigonometric functions
Graph of Inverse Trigonometric Functions
$sin^{-1} x$
$cos^{-1} x$
$tan^{-1} x$
$cosec^{-1} x$$ sec^{-1} x$
$cot^{-1} x$
More Formulas
$sin (sin^{-1} x) = x$ and $sin^{-1} (sin \theta) = \theta$, if $- \frac {\pi}{2} \leq \theta \leq \frac {\pi}{2}$ and $- 1 \leq x \leq 1$.
$cos (cos^{-1} x) = x$ and $cos^{-1} (cos \theta) = \theta $, if $0 \leq \theta \leq \pi$ and $- 1 \leq x \leq 1$
$tan (tan^{-1} x) = x$ and $tan^{-1} (tan \theta) = \theta $ if $- \frac {\pi}{2} \leq \theta \leq \frac {\pi}{2}$ and $ – \infty < x < \infty$.
$cosec (cosec^{-1} x) = x$ and $cosec^{-1} (cosec \theta) = \theta$ if $- \frac {\pi}{2} \leq \theta < 0$ , $ 0 < \theta \leq \frac {\pi}{2}$ and $- \infty < x \leq -1$ or $1 \leq x < \infty$ .
$sec (sec^{-1} x) = x$ and $sec^{-1} (sec \theta) = \theta$ if $0 \leq \theta < \frac {\pi}{2}$ or $\frac {\pi}{2} < \theta \leq \pi $ and $- \infty < x \leq -1$ or $1 \leq x < \infty$.
$cot (cot^{-1} x) = x$ and $cot^{-1} (cot \theta) = \theta$, if $0 < \theta < \pi$ and $ – \infty < x < \infty$
Inverse of Negative x
$sin^{-1} (-x) = -sin^{-1} (x)$
$cos^{-1} (-x) = \pi – cos^{-1} (x)$
$tan^{-1} (-x) = -tan^{-1} (x)$
$sec^{-1} (-x) = \pi – sec^{-1} (x)$
$cosec^{-1} (-x) = -cosec^{-1} (x)$
$cot^{-1} (-x) = \pi – cot^{-1} (x)$
Other Formulas
$sin^{-1} (\frac {1}{x}) = cosec^{-1} (x)$
$cos^{-1} (\frac {1}{x}) = sec^{-1} (x)$
$tan^{-1} (\frac {1}{x}) = cot^{-1} (x)$
$sin^{-1} (x) + cos^ {-1} (x) = \frac {\pi}{2}$
$sec^{-1} (x) + cosec^ {-1} (x) = \frac {\pi}{2}$
$tan^{-1} (x) + cot^ {-1} (x) = \frac {\pi}{2}$
$sin^{-1} (x) + sin^ {-1} (y) = sin ^{-1} (x \sqrt {1-y^2} + y \sqrt {1-x^2})$ if $x,y \geq 0 $, $x^2 + y^2 \leq 1$
$sin^{-1} (x) + sin^ {-1} (y) = \pi – sin ^{-1} (x \sqrt {1-y^2} + y \sqrt {1-x^2})$ if $x,y \geq 0 $, $x^2 + y^2 > 1$
$sin^{-1} (x) – sin^ {-1} (y) = sin ^{-1} (x \sqrt {1-y^2} – y \sqrt {1-x^2)}$ if $x,y \geq 0 $, $x^2 + y^2 \leq 1$
$sin^{-1} (x) – sin^ {-1} (y) = \pi – sin ^{-1} (x \sqrt {1-y^2} – y \sqrt {1-x^2})$ if $x,y \geq 0 $, $x^2 + y^2 > 1$
$cos^{-1} (x) + cos^ {-1} (y) = cos ^{-1} (x y – \sqrt {1-y^2} \sqrt {1-x^2})$ if $x,y \geq 0 $, $x^2 + y^2 \leq 1$
$cos^{-1} (x) + cos^ {-1} (y) = \pi – cos ^{-1} ((x y – \sqrt {1-y^2} \sqrt {1-x^2})$ if $x,y \geq 0 $, $x^2 + y^2 > 1$
$cos^{-1} (x) – cos^ {-1} (y) = cos ^{-1} (x y + \sqrt {1-y^2} \sqrt {1-x^2})$ if $x,y \geq 0 $, $x^2 + y^2 \leq 1$
$cos^{-1} (x) – cos^ {-1} (y) = \pi – cos ^{-1} (x y + \sqrt {1-y^2} \sqrt {1-x^2})$ if $x,y \geq 0 $, $x^2 + y^2 > 1$
$tan^{-1} (x) + tan^ {-1} (y)= tan^{-1} (\frac {x+y}{1-xy})$ , if $x,y > 0 $, $xy < 1$
$tan^{-1} (x) + tan^ {-1} (y)= \pi + tan^{-1} (\frac {x+y}{1-xy})$ , if $x,y > 0 $, $xy > 1$
$tan^{-1} (x) + tan^ {-1} (y)= tan^{-1} (\frac {x+y}{1-xy}) – \pi$ , if $x < 0, y > 0 $, $xy > 1$
$tan^{-1} (x) – tan^ {-1} (y)= tan^{-1} (\frac {x-y}{1+xy}) – \pi$ , if $xy > -1$
$tan^{-1} (x) + tan^ {-1} (y) + tan^ {-1} (z) = tan^{-1} (\frac {x+y+z – xyz}{1-xy-yz-xz})$
$ 2 sin^{-1} (x) = sin^{-1} (2x \sqrt {1-x^2})$ if $ -\frac {1}{\sqrt {2}} \leq x \frac {1}{\sqrt {2}} $
$ 2 cos^{-1} (x) = cos^{-1} (2x^2 -1)$
$2 tan^{-1} (x) = tan^{-1} (\frac {2x}{1-x^2})$ if $ -1 <x < 1$
$2 tan^{-1} (x) = sin^{-1} (\frac {2x}{1+x^2})$ if $ |x| \leq 1$
$2 tan^{-1} (x) = cos^{-1} (\frac {1 -x^2}{1+x^2})$ if $ x \geq 0$
$3 sin^{-1} (x) = sin^{-1} (3x -4x^3)$
$3 cos^{-1} (x) = cos^{-1} (4x^3 – 3x)$
$3 tan^{-1} (x) = tan^{-1} (\frac {3x -x^3}{1-3x^2})$
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This article is amazing. You cover all the formulas which helps me to solve the equations in lesser time. You can also do that by using the trigonomatry graphing calculator.