**Dimensional Formula of Momentum**

**Dimensional Formula of Momentum**

**with its Derivation**

In this article, we will find the dimension of Momentum

Dimensional formula for Momentum is

$[M^1L^2T^{-1}]$

Where**M** -> Mass

**L** -> Length

**T** -> Time

We would now derive this dimensional formula.

### Derivation for expression of Dimension of Momentum

Momentum is defined as the product for mass and Velocity

$p= mv$

Where

m -> mass

v-> Velocity

p->Momentum

So,

Now the dimension of Mass= $[M^1]$

Lets derive the dimension of Velocity

$v= \frac {dx}{dt}$

or

$v = \frac {d}{t}$

Now

Where

d-> displacement

t -> Time

Now Dimension of Displacement = $[L^1]$

Hence dimension of Velocity= $\frac {[L^1]}{[T^1]}=[M^0 L^1T^{-1}]$

So, Dimension of Momentum is given by

$\text {Dimension of Momentum} =[M^1] \times [M^0 L^1T^{-1}] = [M^1L^1T^{-1}]$

Unit of Momentum is Kg m/s and it is denoted by letter $p$

Try the free Quiz given below to check your knowledge of Dimension Analysis:-

**Quiz on Dimensional Analysis**

**Related Articles**

- Dimensional Analysis:- a very good website for physics concepts
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- New Simplified Physics by SL Arora(Set of 2 Volumes) Set of two books for class 11 physics. Its language is easy to follow. I personally use it for making notes and study material.

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