|
1 Meter |
10 Decimetre |
100 centimetre |
|
1 Decimetre |
10 centimetre |
100 millimetre |
|
1 Km |
10 Hectometre |
100 Decameter |
|
1 Decameter |
10 meter |
1000 centimetre |
|
1 square Meter |
100 square Decimetre |
10000 square centimetre |
|
1 square Decimetre |
100 square centimetre |
10000 square millimetre |
|
1 Hectare |
100 squareDecameter |
10000 square meter |
|
1 square myraimeter |
100 square kilometre |
108 square meter |
|
N |
Shape |
Perimeter/height |
Area |
|
1 |
Right angle triangle Base =b, Height =h Hypotenuse=d |
$P=b+h+d$ Height =h |
$A=\frac {1}{2}BH$ |
|
2 |
Isosceles right angled triangle Equal side =a |
Height=a |
$A=\frac {1}{2} \sqrt {a}$ |
|
3 |
Any triangle of sides a,b ,c |
$P=a+b+c$ |
$A=\sqrt {s(s-a)(s-b)(s-c)}$ $s=\frac {a+b+c}{2}$ This is called Heron's formula (sometimes called Hero's formula) is named after Hero of Alexandria |
|
4 |
Square Side =a |
|
$A=a^2$ |
|
5 |
Rectangle of Length and breath L and B respectively |
$P=2L +2B$ |
$A=L \times B$ |
|
6 |
Parallelograms Two sides are given as a and b |
$P=2a+2b$ |
$A= Base \times height$ When the diagonal is also given ,say d Then $A= \sqrt {s(s-a)(s-b)(s-d)}$ $s=\frac {a+b+d}{2}$ |
|
7 |
Rhombus Diagonal d1 and d2 are given |
$p=2 \sqrt {d_1^2+d_2^2}$ Each side=$ \frac {1}{2} \sqrt {d_1^2+d_2^2} $ |
$A=\frac {1}{2} d_1 d_2$ |
|
8 |
Quadrilateral a. All the sides are given a,b,c ,d b. Both the diagonal are perpendicular to each other c. When a diagonal and perpendicular to diagonal are given |
a. $P=a+b+c+d$ |
a. $A=\sqrt {s(s-a)(s-b)(s-c)(s-d)}$ $s=\frac {(a+b+c+d)}{2}$ b. $A=\frac {1}{2} d_1 d_2$ where d1 and d2 are the diagonal c. $A=\frac {1}{2} d(h_1+h_2)$ where d is diagonal and h1 and h2 are perpendicular to that |
|
If you know the altitude and Base |
Area =(1/2)BH |
| If you all the three sides |
A=[s(s-a)(s-b)(s-c)]1/2 s=(a+b+c)/2 |
| If it is isosceles triangle with equal side a | A=(1/2)a1/2 |
| If it is equilateral triangle with equal side a | A=[(3)1/2 a2]/4 |
| If it is right angle triangle with Base B and Height H | Area =(1/2)BH |
