physicscatalyst.com logo




Magnetic field of a toroid





Magnetic Field of a toroid

  • We will now apply Ampere circuital law to calculate magnetic field of a toroid
  • A toroidal solenoid is a hollow circular ring with a large number of turns of a wire carrying current wound around the ring
  • Suppose we have to find the magnetic field B at a point P inside the toroid as shown below in figure


     Magnetic Field of a toriod

  • In this case amperion loop would be a circle through point P and concentric inside the toroid
  • By symmetry field will have equal magnitude at all points of this circle and this field is tangential to every point in the circle
    Thus


  • If there are total N number of turns ,net current crossing the area bounded by the circle is NI where I is the current in the toroid
  • using Ampere law


    Thus we see that field B varies with r i.e. field B is not uniform over the cross-section of the core because the path l=2πr is longer at the outer side of the section then at the inner side
  • Imagine a concentric circle through point P' outside the toroid
  • The net current passing through this circular disc is zero ,since the current NI passes in and same current passes out. Thus using Ampere's circuital law, the field B=0 outside the toroid



Join PhysicsCatalyst WhatsApp Channel











Latest Updates
Classification of Elements JEE MCQ

Chemical Equilibrium Class 11 MCQ

Redox Reactions JEE Main MCQ

Chemical Equilibrium Class 11 MCQ

Chemical Thermodynamics JEE Advanced MCQ