Given below are the Class 9 Science CBSE Test Paper for Atoms and Molecules
a. Concepts questions
b. Calculation problems
Hope you like them and do not forget to like , social share and comment at the end of the page.
Law of mass conservation states that, mass can neither be created nor destroyed in a chemical reaction or a physical transformation.
According to the Law of constant proportion, a chemical compound always has its compounding elements in definite proportion by mass, irrespective of the source and the type of chemical reaction.
In modern science, John Dalton widely used it and he can be said to be responsible for coining it, but a more factually correct answer would be a Greek philosopher who goes by the name of Lucretius.
Atom is the smallest particle of matter which can take part in a chemical reaction.
A molecule is a group of atoms bonded together which represents the most fundamental unit of a chemical compound capable of taking part in a chemical reaction.
Atomicity is the number of atoms in a molecule.
The Atomic mass unit is the sum of the atomic masses of all the atoms in a molecule.
An ion is an atom or a molecule with an electric charge (+ve or -ve), caused by gain or loss of a single or multiple electrons.
Avogadro’s Constant (6.022 x 1023) is the number of atoms of an element present in one mole of that element.
(a) Atoms of most elements don’t exist independently they exist as molecules, for molecules are more stable. However, atoms of inert gasses are chemically unreactive and they exist independently. E.g. helium.
(b) Atomicity is the number of atoms in a molecule. E.g. The atomicity of H2O = 3.
(c) A polyatomic ion is an ion composed of multiple atoms acting as a single charged unit.
Atomic mass is the unit in which the mass of an atom is expressed, where one atomic mass unit is 1/12ththe mass of a carbon-12 atom.
Gram atomic mass is the atomic mass of an element expressed in grams.
The mass of an atom or a molecule is expressed in ‘u’, whereas, the molar mass is expressed in ‘gm’.
One mole of atoms, molecules, or particles is that amount of the particle(atoms, molecules and ions) whose mass is equal to that particle's atomic or molecular mass in grams. 1 mole = 6.022 x 1023 particles of that substance.
Importance of a mole: -
Dalton was the first scientist to use the symbol for the name of the elements a specific sense but it was difficult to memorize and in uses so Dalton's symbol are not used in chemistry
2O represents 2 atoms of oxygen, and it is not possible for it to exist independently.
O2represents an oxygen molecule which has two constituent oxygen atoms.
O3represents a single ozone molecule and it does exist independently.
we know that density of water is 1gm/ml.
Hence, 1 gm water will = 1 ml water.
Now, we have molecular mass of water $H_2O$ = 1x2 + 16 = 18 gm
18 gm of water contain $6.022 \times 10^{23}$ molecules
1 gm of water will contain = $\frac {6.022 \times 10^{23}}{18} = 0.33 \times 10^{23}$ molecules
So, the no. of molecules of water in 1ml of water = $3.3 \times 10^{22}$
Molecular mass of C6H12O6= (12 x 6) + 12 + (16 x 6)
= 180u.
Formula Unit Mass of NaCl = 23 + 35.5 = 58.5u
Formula Unit Mass of CaCl2= 40+(2 x 35.5)= 111u.
Mass of reactants: 10gm
Mass of product = 4.4 + 5.6 = 10g
Since Mass of reactants is equal to Mass of products , therefore these observations are in agreement with law of conservation of mass.
(1) Mass of a single oxygen atom
1 mole of oxygen atom = 16gm =6.022 x 1023atoms
Therefore, Mass of one oxygen atom = 16/6.022 x 1023= 2.65 x 10-23gm
(2) Mass of a single oxygen atom
1 molecule oxygen = O2=2 x 16 = 32u
(3) Mass of a mole of oxygen gas
1 mole of oxygen = O2= 2 x 16 =32u
(4) Mass of an oxygen ion = mass of an oxygen atom (since electrons have negligible mass)
(5) Number of atoms in a mole of oxygen molecule
We know, 1 mole of oxygen molecule, O2= 6.022 x 1023molecules.
1 molecule of O2= 2 atoms
Therefore in a mole of O2, there are =6.022 x 1023x 2 atoms
= 1.022 x 1024atoms.
Atomicity of oxygen, O2= 2 and atomicity of phosphorous, P4= 4.
mass of 3 moles of oxygen = 3 x 16 = 48g
Now, mass of $SO_2$ = 32 + 2 x 16 = 64g
As 64g of $SO_2$ = 1 mole
then 48 g of $SO_2$ = (1/64) x 48 =0.75 mole
This Class 9 Test Paper for Atoms and Molecules with answers is prepared keeping in mind the latest syllabus of CBSE . This has been designed in a way to improve the academic performance of the students. If you find mistakes , please do provide the feedback on the mail.