$I= F \times t$

Where

I -> Impulse

F -> Force acting on it

t -> time during which force is being applied

Impulse is also calculated as the difference from Final momentum and initial Momentum

$I= p_2 - p_1 = mv_2 - mv_1$ Where m -> mass

$v_2$ -> Final velocity

$v_1$ -> Initial velocity

- Enter the values of the mass , initial velocity and final velocity in the text boxes

- Click on the calculate button.

$I =p_2 - p_1$

$I=mv_2 - mv_1$

Where m -> mass

$v_2$ -> Final velocity

$v_1$ -> Initial velocity

Calculate the Initial Momentum,Final Momentum and Impulse on the object have mass 10 kg and initial and final velocites as 10m/s and 20 m/s

Given , m= 10 kg, $v_1 = 10 \ m/s$, $v_2 = 20 \ m/s$

$p_1 =m v_1$ = 10 \times 10 = 100 \ Kg m/s$

$p_2 =m v_2= 10 \times 20 = 200 \ kg m/s$

$I= p_2 - p_1= 200 - 100 = 100 N-s$

Calculate the Impulse for the both of Mass (m) = 25 kg and initial velocity and final velocity as 20 and 40 m/s

Given , m= 10 kg, $v_1 = 10 \ m/s$, $v_2 = 20 \ m/s$

$I= mv_2 - mv_1= 25 \times 40 - 25 \times 20 = = 500 N-s$

- Initial Momentum ($p_1$) is calculated as

$p_1 =m v_1$

- final Momentum ($p_2$) is calculated as

$p_2 =m v_2$

- Impulse is calculated using change in momentum

$I= p_2 - p_1$

- Enter the values of the two known variables in the text boxes

- Leave the text box empty for the variable you want to solve for

- Click on the calculate button.

$I =Ft$

Where F -> Force applied

t -> time period during which force is applied

Calculate the Impulse on the object have force applied 10 N for 3 sec

Given , F=10N, t=3 sec, I=?

Impulse is given as

$I= F \times t = 10 \times 3 = 30 \ N-s$

Calculate the force on the object when Impulse applied 100 N-s for 20 sec

Given , F=?, t=3 sec, I=100 N-s

Impulse is given as

$I= F \times t $

Rearranging this for force

$F= \frac {I}{t} = \frac {100}{20} = 5 \ N$

The Impulse due to force of 20 N on the object is 1000 N-s . Find the time duration for which force is applied?

Given , F=20 N, t=?, I=1000 N-s

Impulse is given as

$I= F \times t $

Rearranging this for time

$F= \frac {I}{F} = \frac {1000}{20} = 50 \ sec$

- When time and force is given,Impulse is calculated as

$I =F \times t$

- When time and Impulse is given,Force is calculated as

$F =\frac {I}{t}$

- When Force and Impulse is given,time is calculated as

$t =\frac {I}{F}$

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