# Projectile Motion calculator

Note
• Enter the values of the two known variables in the text boxes
• Leave the text box empty for the variable you want to solve for
• Click on the calculate button.
The formula used for solving the question is
$H= \frac {u^2 sin^2 \theta}{2g}$
$R =\frac {u^2 sin 2 \theta}{g}$
Where $u$ is the velocity of launch
$\theta$ is the angle of launch
H and R is the Maximum Height and Range
Value of g is assumed at 10m/s2

### Projectile Motion Calculator

Example of Few questions where you can use this Projectile Motion calculator
• A object is projected with velocity 2 m/s at an angle 45°.Find the Range and Maximum Height attained by the object in Projectile Motion
• if u =40 m/s and H=25 m , Find the angle and range of the Projectile .

## How the Projectile Motion calculator works

1. If initial velocity and angle are given
Maximum Height And Range is calculated as below ( $g=10 \ m/s^2$) $H= \frac {u^2 sin^2 \theta}{2g}$
$R =\frac {u^2 sin 2 \theta}{g}$
2. If initial velocity and Maximum height are given
Angle And Range is calculated as below ( $g=10 \ m/s^2$) $\theta=sin^{-1} \sqrt {\frac {2gH}{u^2}}$
$R =\frac {u^2 sin 2 \theta}{g}$
3. If initial velocity and Range are given
Angle And Maximum Height is calculated as below ( $g=10 \ m/s^2$) $\theta=\frac {sin^{-1} \frac {gR}{u^2}}{2}$
$H= \frac {u^2 sin^2 \theta}{2g}$
4. if Maximum Height and Range are given
Angle And initial velocity is calculated as below ( $g=10 \ m/s^2$) $\theta= tan^{-1} \frac {4H}{R}$
$u= \sqrt { \frac {gR}{sin 2 \theta}}$
5. if Angle and Range are given
initial velocity And Maximum Height is calculated as below ( $g=10 \ m/s^2$) $u= \sqrt { \frac {gR}{sin 2 \theta}}$
$H= \frac {u^2 sin^2 \theta}{2g}$
6. if Angle and Maximum Height are given
initial velocity And Range is calculated as below ( $g=10 \ m/s^2$) $u= \sqrt { \frac {2gH}{sin^2 \theta}}$
$R =\frac {u^2 sin 2 \theta}{g}$

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