- distance and displacement
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- Velocity and speed
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- Instantaneous velocity and speed
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- Acceleration
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- Kinematic equations for uniformly accelerated Motion
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- Free fall acceleration
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- Relative velocity
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- Kinematics Sample Problems and Solutions
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- One dimensional motion problems with solution
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- Motion graphs worksheet with Answer

- Important Questions on Kinematics
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- Projectile motion problems
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- Kinematics and Projectile motion worksheet
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- Motion in one dimension (obj)
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- Motion in one dimension (sub)
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- Motion in one dimension Practice Paper
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- Acceleration worksheet with answers

In this page we have *Motion Graphs Worksheet with Answers* . Hope you like them and do not forget to like , social share
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. Before hitting the ground ,the velocity v is given by v

a. C

b. D

c. E

d. B

. The instantaneous velocity is given by the slope of the displacement time graph.

Since slope is negative at point B, instantaneous velocity is negative at B

Hence (d) is correct

a. 60m

b. 40m

c. 50m

d. 30m

. Acceleration is given by the slope of the velocity time graph

Non zero acceleration happened in the time interval 20 to 40 sec as the slope of the graph is non zero in that time interval

Now displacement in that interval is given by the area enclosed the v-t curve during that interval

So area=(1/2)20*3 +20*1=50m

Hence (c) is correct

a. It first increases and then decreases

b. It is a non zero constant

c. it is zero

d. none of the above

. The instantaneous velocity is given by the slope of the displacement time graph.

As slope of both the particle displacement time graph is constant.That means there individual velocities are constant.

So relative velocity is also constants

so it is a non zero constant as they have different velocity

Hence (b) is correct

Four position -time graph are shown below.

a.

b.

c.

d.

a. a and c only

b. all the four

c. b and D only

d. b only

. The instantaneous velocity is given by the slope of the displacement time graph.

Since slope is positive in graph a and c.Positive velocity is there in a and c curve

Hence (a) and (c) are correct

a. a and b only

b. all the four

c. a and c only

d. c only

. The instantaneous velocity is given by the slope of the displacement time graph.

Since slope is negative in graph b and d.Negative velocity is there in b and d curve

Hence (b) and (d) are correct

a.

b.

c.

d.

.

The velocity will increase with time so b is the correct answer

Hence (b) is correct

a.

b.

c.

d.

. The equation for the given graph is

v=-(v

Differentiating both sides we get

dv/dx=-v

Now

a=v(dv/dx)

or

a=(-v

or

a=mx+c

where m=v

and c=-v

So that means slope is positive and intercept is negative

So (d) is correct

Class 11 Maths Class 11 Physics Class 11 Chemistry