Enter the values of the one known variable in the text boxes
Leave the text box empty for the variable you want to solve for
Click on the calculate button.
The formula used for solving the question is
$\deg C= K -273 $
$F -32 =\frac{9}{5}C $
Temperature Conversion Calculator
What is temperature and Temperature Scale
Temperature is the measurement of how hot or cold the body is. Temperature is measured using thermometer.Construction of thermometers generally requires a measurable property of a substance which monotonically changes with temperature.
We have three common scale of temperature
(a) Celsius Scale: Temperature in Celsius is measured in degree.It is denoted by ° C.Melting point of ice and boiling point of water have values 0 ° C and 100° C
(b) Fahrenheit Scale : Temperature in Celsius is measured in degree but it is smaller than celsius.It is denoted by ° F.Melting point of ice and boiling point of water have values 32 ° F and 132° F
(b) kelvin Scale : Size of a degree in Celsius and kelvin scale are sam.It is denoted by K.Melting point of ice and boiling point of water have values 273.15 K and 373.15 K Relation Between Celsius ,Fahrenheit and Kelvin
$\frac {C -0}{100} = \frac {F -32}{180} =\frac {K - 273}{180}$
Example of Few questions where you can use this formula Question 1
Convert 45 ° C to Kelvin and Fahrenhiet Scale Solution
We have the relation
$\frac {C -0}{100} = \frac {F -32}{180} =\frac {K - 273}{180}$
Taking $\frac {C -0}{100} = \frac {F -32}{180}$
$F= \frac {9}{5}C + 32= \frac {9}{5} \times 45 + 32= 113$ ° F
Taking $\frac {C -0}{100} =\frac {K - 273}{180}$
$K= C + 273 = 45 + 273 = 318 \ K$
Question 2
Convert 23 K to ° C and Fahrenhiet Scale. Solution
We have the relation
$\frac {C -0}{100} = \frac {F -32}{180} =\frac {K - 273}{180}$
Taking $\frac {C -0}{100} =\frac {K - 273}{180}$
$C= K - 273= 23 - 273= -250$ ° C
Taking $\frac {C -0}{100} = \frac {F -32}{180}$
$F= \frac {9}{5}C + 32= \frac {9}{5} \times (-250) + 32= -418$ ° F
How the Temperature Conversion calculator works
1. If Temperature in Celsius is given, Temperature in Kelvin and Fahrenhiet can be found using
$K= C + 273$
$F= \frac {9}{5}C + 32$
2. If Temperature in Kelvin is given, Temperature in Celsius and Fahrenhiet can be found using
$C= K - 273$
$F= \frac {9}{5}C + 32$
3. If Temperature in Fahrenhiet is given, Temperature in Celsius and Kelvin can be found using
$C = \frac {5(F-32)}{9}$
$K= C + 273$
