# Ncert Solutions for Class 6 Mathematics Decimals Exercise 8.4,8.5,8.6

In this page we have Ncert Solutions for Class 6 Mathematics Decimals Exercise 8.4,8.5,8.6. Hope you like them and do not forget to like , social share and comment at the end of the page.

## Exercise 8.4

Question 1

Express as rupees using decimals.

(a) 5 paise

(b) 75 paise

(c) 20 paise

(d) 50 rupees 90 paise

(e) 725 paise

We know that 100 paise = Rs 1

Therefore, 1 paise = Rs 1/100

a) 5 p = 5/100=Rs .05

b) 75 p = 75/100= Rs .75

c) 20 p = 20/100= Rs .2

d) 50 rupees 90 paise = 50 + 90/100= Rs 50.9
e) 725 paise= 725/100 = Rs 7.25

Question 2

Express as metres using decimals.

(a) 15 cm

(b) 6 cm

(c) 2 m 45 cm

(d) 9 m 7 cm

(e) 419 cm

1 m= 100 cm so 1 cm =1/100 m

a) 15 cm= 15/100 m =.15 m

b) 6 cm= 6/100 m =.06m

c) 2 m 45 cm = (2+ 45/100) m= 2.45 m

d) 9 m 7 cm = (9+ 7/100) m= 9.07 m

e) 419 cm= 4.19 m

Question 3

Express as km using decimals.

(a) 8 m

(b) 88 m

(c) 8888 m

(d) 70 km 5 m

1km =1000m

1m =1/1000 km

a) 8 m = 8/1000 km=.008 km

b) 88 m = 88/1000 km=.088 km

c) 8888 m = 8888/1000 km=8.888 km

d) 70 km 5m = (70 + 5/1000) km=70.005 km

Question 4

Express as kg using decimals.

(a) 2 g

(b) 100 g

(c) 3750 g

(d) 5 kg 8 g

(e) 26 kg 50 g

1kg =1000g

1g =1/1000 kg

a) 2 g = 2/1000 kg=.002 kg

b) 100 g = 100/1000 kg=.1 kg

c) 3750 g = 3750/1000 kg=3.75 kg

d) 5kg 8g = (5+ 8/1000) kg=5.008 kg

e) 26kg 50 g = (26+ 50/1000) kg=26.50 kg

## Exercise 8.5

Question 1

Find the sum in each of the following:

(a) $0.007 + 8.5 + 30.08$

(b) $15 + 0.632 + 13.8$

(c) $27.076 + 0.55 + 0.004$

(d) $25.65 + 9.005 + 3.7$

(e) $0.75 + 10.425 + 2$

(f) $280.69 + 25.2 + 38$

(a) $0.007 + 8.5 + 30.08$
 .0007  8.500   + 30.080 38.587

(b) $15 + 0.632 + 13.8$
 15 .000    0.632   + 13.800 29.432

Similarly

(c) $27.076 + 0.55 + 0.004$

=27.630

(d) $25.65 + 9.005 + 3.7$

=38.355

(e) $0.75 + 10.425 + 2$

=13.175

(f) $280.69 + 25.2 + 38$

=343.890

Question 2

Rashid spent Rs 35.75 for Math’s book and Rs 32.60 for Science book. Find the total amount spent by Rashid.

Amount spent for Math’s book = Rs. 35.75

Amount spent for Science book = Rs. 32.60

Total amount spent for the books by Rashid = 35.75 + 32.60
 35 .75 32. 60 + 68.35

So, Rashid spent Rs. 68.35 for the books.

Question 3

Radhika’s mother gave her Rs 10.50 and her father gave her Rs 15.80, find the total amount given to Radhika by the parents?

Money given by mother to Radhika = Rs. 10.50

Money given by father to Radhika = Rs. 15.80

Doing the addition similarly as given above

Total amount=26.30

Question 4

Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.

We know that 1 m=100 cm and 1 cm = 1/100 m

Length of the cloth purchased for shirt = 3 m 20 cm
=3m + 20/100 m= 3.2 m

Length of the cloth purchased for trouser = 2 m 5 cm

=2m + 5/100m = 2.05 m

Total length of the cloth purchased

=3.20 + 2.05

Total length of the cloth purchased = 5.25 m

Question 5

Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?

We know that 1 km=1000 m and 1 m = 1/1000 km

Distance walked by Naresh in the morning = 2 km 35 m

= 2 km + 35/1000 km= 2.035 km

Distance covered by Naresh in the evening = 1 km 7 m

= 1 km + 7/1000 km= 1.007 km

Distance Naresh walked in all = $(2.035 + 1.007)$ km

=3.042 km

Question 6

Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to reach her school. How far is her school from her residence?

We know that 1 km=1000 m and 1 m = 1/1000 km

Distance travelled by Sunita in bus = 15 km 268 m

= 15 km  + 268/1000 km= 15.268 km

Distance travelled by Sunita in car = 7 km 7 m

=7 km + 7/1000 km= 7.007 km

Distance travelled by Sunita on foot = 500 m = 0.5 km

Total distance of school from residence =$15.268 + 7.007 +0.5 =22.775$ km

Question 7

Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.

Amount of rice = 5 kg 400 g = 5.400 kg

Amount of sugar = 2 kg 20 g = 2.020 kg

Amount of flour = 10 kg 850 g = 10.850 kg

Total weight of the purchases =5.400 kg + 2.020 kg + 10.850 kg

=18.270 kg

Total amount of purchase = 18.270 kg

## Exercise 8.6

Question 1

Subtract:

(a) Rs 18.25 from Rs 20.75

(b) 202.54 m from 250 m

(c) Rs 5.36 from Rs 8.40

(d) 2.051 km from 5.206 km

(e) 0.314 kg from 2.107 kg

a)
 20.75 18.25 - 02.50

b)
 250.00 202.54 - 47.46

c)
 8.40 5.36 - 3.04

d)
 5.206 2.051 - 3.155

e)
 2.107  0.314 - 1.793

Question 2

Find the value of:

(a) $9.756 - 6.28$

(b) $21.05 - 15.27$

(c) $18.5 - 6.79$

(d) $11.6 - 9.847$

Solving similarly as above

(a) $9.756 - 6.28 =3.476$

(b) $21.05 - 15.27=5.78$

(c) $18.5 - 6.79=11.71$

(d) $11.6 - 9.847=1.753$

Question 3

Raju bought a book for Rs 35.65. He gave Rs 50 to the shopkeeper. How much money did he get back from the shopkeeper?

Cost of the book Raju purchased = Rs. 35.65

Money paid by Raju to the shopkeeper = Rs. 50

Remaining = Rs. 50 – Rs. 35.65

Solving the subtraction similarly as given above

= Rs 14.35

Question 4

Rani had Rs 18.50. She bought one ice-cream for Rs 11.75. How much money does she have now?

Money initially with Rani = Rs. 18.50

Amount Rani spent on an ice-cream = Rs. 11.75

Remaining Money with Rani = $18.50 - 11.75$

Solving the subtraction similarly as given above

= Rs 6.75

Question 5

Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?

Length of the cloth which Tina had = 20 m 5 cm = 20.05 m

Length of the cloth which Tina cuts = 4 m 50 cm = 4.50 m

Length of the cloth left with her = 20.05 m – 4.50 m

=15.55 m

Question 6

Namita travels 20 km 50 m every day. Out of this, she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?

1 Km =1000m and 1 m=1/1000 km
Total distance Namita travelled every day is 20 km 50 m = 20.050 km

Distance travelled in bus is 10 km 200 m = 10.200 km

Distance travelled in auto= Total distance travelled - distance travelled in Bus

$=20.050 - 10.200 =9.850 km$

Question 7

Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes?

We know that 1 kg=1000g and 1 g= 1/1000 kg
Given

Total weight of the vegetables purchased by Aakash = 10 kg

Weight of onions purchased = 3 kg 500 g = 3.500 kg

Weight of tomatoes of Purchased = 2 kg 75 g = 2.075 kg

Total Weight of onions and tomatoes = 3.500 + 2.075 kg

=5.575 kg

Weight of potatoes = Total Weight of the vegetables – weight of onions and tomatoes

$=10- 5.575 =4.425$ kg

### Practice Question

Question 1 What is $\frac {1}{2} + \frac {3}{4}$ ?
A)$\frac {5}{4}$
B)$\frac {1}{4}$
C)$1$
D)$\frac {4}{5}$
Question 2 Pinhole camera produces an ?
A)An erect and small image
B)an Inverted and small image
C)An inverted and enlarged image
D)None of the above