We already know that electric dipole is an arrangement which consists of two equal and opposite charges +q and -q separated by a small distance 2a.
Electric dipole moment is represented by a vector p of magnitude 2qa and this vector points in direction from -q to +q.
To find electric potential due to a dipole consider charge -q is placed at point P and charge +q is placed at point Q as shown below in the figure.
Since electric potential obeys superposition principle so potential due to electric dipole as a whole would be sum of potential due to both the charges +q and -q. Thus
where r1 and r2 respectively are distance of charge +q and -q from point R.
Now draw line PC perpandicular to RO and line QD perpandicular to RO as shown in figure. From triangle POC
cosθ=OC/OP = OC/a
therefore OC=acosθ similarly OD=acosθ
r1 = QR≅RD = OR-OD = r-acosθ
r2 = PR≅RC = OR+OC = r+acosθ
since magnitude of dipole is
|p| = 2qa
If we consider the case where r>>a then
again since pcosθ= p·rˆ where, rˆ is the unit vector along the vector OR then electric potential of dipole is
From above equation we can see that potential due to electric dipole is inversly proportional to r2 not ad 1/r which is the case for potential due to single charge.
Potential due to electric dipole does not only depends on r but also depends on angle between position vector r and dipole moment p.
8. Work done in rotating an electric dipole in an electric field
Consider a dipole placed in a uniform electric field and it is in equilibrium position. If we rotate this dipole from its equllibrium position , work has to be done.
Suppose electric dipole of moment p is rotated in uniform electric field E through an angle θ from its equilibrium position. Due to this rotation couple acting on dipole changes.
If at any instant dipole makes an angle φ with uniform electric field then torque acting on dipole is
again work done in rotating this dipole through an infitesimaly small angle dφ is
dW=torque x angular displacement
Total work done in rotating the dipole through an angle θfrom its equilibrium position is
This is the required formula for work done in rotating an electric dipole placed in uniform electric field through an angle θ from its equilibrium position.
9.Potential energy of dipole placed in uniform electric field
Again consider equation 20 which gives the work done in rotating electric dipole through an infinetesimly small angle dφ is
which is equal to the change in potential energy of the system
If angle dφ is changed from 900 to θ then in potential energy would be
We have choosen the value of φgoing from π/2 to θ because at π/2 we can take potential energy to be zero (axis of dipole is perpandicular to the field). Thus U(900)=0 and above equation becomes
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