- Linear Momentum
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- Impulse and Momentum
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- Conservation of Linear momentum
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- Recoil of the Gun
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- Motion of the system with varying mass(Rocket)
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- Linear Momentum Problems with Solutions

- Law of conservation of linear momentum is a extremely important consequence of Newton's third law of motion in combination with the second law of motion

- Consider two particles of mass m
_{1}and m_{2}interacting with each other and forces acting on these particles are only the ones they exert on each other.

- Let
**F**_{12}be the force exerted by the particle 2 on particle 1 having mass m_{1}and velocity**v**_{1}and**F**_{21}=-**F**_{12}be the force exerted by the particle 1 on particle 2 having mass m_{2}and velocity**v**_{2}

- Applying newton second law of each particle on each particle

**F**_{12}=m_{1}(d**v**_{1}/dt)

and**F**_{21}=m_{2}(d**v**_{2}/dt)

- from newton's third law of motion

**F**_{21}=-**F**_{12}

or m_{1}(d**v**_{1}/dt) + m_{2}(d**v**_{2}/dt)=0

Since mass of the particles are not varying with time so we can write

(d/dt)(m_{1}v_{1}+m_{2}**v**_{2})=0

or m_{1}v_{1}+m_{2}**v**_{2}=constant --(13)

- we have already defined the quantity m
**v**as the momentum of the particle

- Thus we conclude that when two particles are subjected only to their mutual interactions ,the sum of the momentums of the bodies remains constant in time or we can say the total momentum of the two particles does not change because of the any mutual interactions between them

- For any kind of force between two particles then sum of the momentum ,both before and after the action of force should be equal i.e total momentum remains constant

- We thus arrive to the statement of principle of conservation of linear momentum

" when no resultant external force acts on system ,the total momentum of the system remains constant in magnitude and direction"

- In absence of external forces for a number of interacting particles,law of conservation of linear momentum can be expressed as

m_{1}v_{1}+m_{2}**v**_{2}+m_{3}**v**_{3}+m_{4}**v**_{4}+...=constant

- Law of conservation of linear momentum is one of the most fundamental and important principle of mechanics
- This principle also holds true even if the forces between the interacting particles is not conservative
- Once again ,the total momentum of two or any number of particles of interacting particles is constant if they are isolated

from outside influences (or no resultant external forces is acting on the particles)

a. find the velocity of the wooden + block system after the collision

b. Find The Kinetic energy of the wooden + block system after the collision

Initial velocity of bullet=u

Initial velocity of block=0

So net momentum before collision=$mu$

Let v be the velocity after collision

Then Net momentum after collision=$(M + m)v$

Now linear momentum is conserved in this collision

so

$mu=(M + m)v$

or $v=\frac {mu}{M+m}$

So kinetic energy after collision

=$\frac {1}{2}(M+m) v^2 = \frac {m^2u^2}{2(M+m)}$

Class 11 Maths Class 11 Physics Class 11 Chemistry

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