Case II: when the target particle is at rest i,e u_{2}=0
From equation (8) and (9)
Hence some part of the KE which is transformed into second particle would be
Therefore after collisom first particle moving with initial velocity u_{1} would come to rest and the second particle which was at rest would start moving with the velocity of first particle.Hence in this case when m_{1}=m_{2} transfer of energy is 100%.if m_{1} > m_{2} or
m_{1} < m_{2} ,then energy transformation is not 100%
Therefore when a heavy particle collide with a very light particle at rest ,then the heavy particle keeps on moving with the same velocity and the light particle come in motion with a velocity double that of heavy particle
Thanks for visiting our website.
DISCLOSURE: THIS PAGE MAY CONTAIN AFFILIATE LINKS, MEANING I GET A COMMISSION IF YOU DECIDE TO MAKE A PURCHASE THROUGH MY LINKS, AT NO COST TO YOU. PLEASE READ MY DISCLOSURE FOR MORE INFO.