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In this page we have *NCERT Solutions for Class 10 Maths Chapter 12 Areas Related to Circles* for
EXERCISE 1 . Hope you like them and do not forget to like , social share
and comment at the end of the page.

According to the question

Circumference of Ist circle = 2π(19) =38 π cm

Circumference of 2

Let r be the radius of the new circle

Circumference of New circle = 2π(r) =2 πr cm

Now

2πr=38π+18π

Or r =28 cm

According to the question

Area of Ist circle =πr

Area of 2

Let r the radius of new circle

Area of New circle=πr

Now as per question

πr

r=10cm

Diameter of Gold Circle is given as =21 cm

Radius of Gold circle=21/2=10.5 cm

Area of Gold region is given by

= πr

Now since each band is 10.5 cm wide

Radius of red ring= 10.5+ 10.5=21 cm

Now Radius of Red ring is given as

= π(21)

Radius of Blue ring =21 +10.5=31.5 cm

Now Radius of Blue ring is given as

= π(31.5)

Radius of Black ring =31.5 +10.5=42 cm

Now Radius of Black ering is given as

= π(42)

Radius of White ring =42 +10.5=52.5 cm

Now Radius of Black ering is given as

= π(52.5)

Diameter of wheel is given as =80 cm

So radius of the wheel=40 cm

So circumference of wheel =2πr= 2(22/7)(40)= (1760/7)cm

So in 1 revolution, Car travels the distance (1760/7)cm

Now Speed of the Car= 66Km/h

=(66X1000)/60 meter/minute

=1100 meter/minute

=110000 cm/minute

This mean in simple term

Distance travelled in 1 min = 110000 cm

Distance travelled in 10 min=1100000 cm

So Total number of revolutions =( 1100000)/(1760/7)

=4375

(A) 2 units

(B) π units

(C) 4 units

(D) 7 units

Area of Circle = πr

Circumference of Circle =2πr

According to the question

πr

r=2 units

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