In this page we have Class 9 maths Statistics  NCERT Solutions Chapter 14 for
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Question 1
A survey conducted by an organization for the cause of illness and death among the women between the ages 15  44 (in years) worldwide, found the following figures (in %):
S.no

Causes

Female fatality rate (%)

1

Reproductive health conditions

31.8

2

Neuropsychiatric conditions

25.4

3

Injuries

12.4

4

Cardiovascular conditions

4.3

5

Respiratory conditions

4.1

6

Other causes

22.0

(i)Represent the information given above graphically.
(ii) Which condition is the major cause of women’s ill health and death worldwide?
(iii) Try to find out, with the help of your teacher, any two factors which play a major role in the cause in (ii) above being the major cause.
Solution
 Bar graph
 Reproductive health conditions
Question 2
The following data on the number of girls (to the nearest ten) per thousand boys in different sections of Indian society is given below
Section

No Of girls per thousand boys

Scheduled Caste(SC)

940

Scheduled Tribe(ST)

970

Non SC/ST

920

Backward districts

950

Nonbackward districts

920

Rural

930

Urban

910

i) Represent the information above by a bar graph.
ii) In the classroom discuss what conclusions can be arrived at from the graph
Solution:
It can be observed that maximum number of girls per thousand boys (i.e., 970) is for ST and minimum number of girls per thousand boys (i.e., 910) is for urban.
Also, the number of girls per thousand boys is greater in rural areas than that in urban areas, backward districts than that in nonbackward districts, SC and ST than that in nonSC/ST.
Question 3:
Given below are the seats won by different political parties in the polling outcome of a state assembly elections
Political Party

A

B

C

D

E

F

Seats Won

75

55

37

29

10

37

i) Draw a bar graph to represent the polling results.
ii) Which political party won the maximum number of seats?
Solution:
We may find that political party 'A' won maximum number of seats.
Question 4:
The length of 40 leaves of a plant are measured correct to one millimeter, and theObtained data is represented in the following table
Length( in mm)

Number of Leaves

118126

3

127135

5

136144

9

145153

12

154162

5

163171

4

172180

2

i) Draw a histogram to represent the given data. [Hint: First make the class intervals Continuous]
(ii) Is there any other suitable graphical representation for the same data?
(iii) Is it correct to conclude that the maximum number of leaves are 153 mm long? Why?
Solution:
It can be observed that the length of leaves is represented in a discontinuous class interval having a difference of 1 in between them. Therefore, ½=.5 has to be added to each upper class limit and also have to subtract 0.5 from the lower class limits so as to make the class intervals continuous.
Taking the length of leaves on xaxis and the number of leaves on yaxis, the histogram of this information can be drawn as above.
Here, 1 unit on yaxis represents 2 leaves.
(ii) Other suitable graphical representation of this data is frequency polygon.
(iii) No, as maximum number of leaves (i.e., 12) has their length in between 144.5 mm and 153.5 mm. It is not necessary that all have their lengths as 153 mm
Question 5
The following table gives the life times of neon lamps:
Life time (in Hours)

Number of Lamps

300400

14

400500

56

500600

60

600700

86

700800

74

800900

62

9001000

48

i) Represent the given information with the help of a histogram.
(ii) How many lamps have a life time of more than 700 hours?
Solution:
i)
ii) Number of lamps having lifetime of more than 700 hours =74+62+48=184
Question 6
The following table gives the distribution of students of two sections according to the marks obtained by them:
Section A

Section B

Marks

Frequency

Marks

Frequency

010

3

010

5

1020

9

1020

19

2030

17

2030

15

3040

12

3040

10

4050

9

4050

1

Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons compare the performance of the two sections.
Solution
Class Marks can calculated as = (Lower Limit+ Upper limit)/2
Section A

Section B

Marks

Class Marks

Frequency

Marks

Class Marks

Frequency

010

5

3

010

5

5

1020

15

9

1020

15

19

2030

25

17

2030

25

15

3040

35

12

3040

35

10

4050

45

9

4050

45

1

Red line Represent Section B
Blue line represent Section A
From the graph we can see performance of students of section 'A' is better than the students of section 'B' as for good marks.
Question 7:
The runs scored by two teams A and B on the first 60 balls in a cricket match are given below
Number Of balls

Team A

Team B

16

2

5

712

1

6

1318

8

2

1924

9

10

2530

4

5

3136

5

6

3742

6

3

4348

10

4

4954

6

8

5560

2

10

Represent the data of both the teams on the same graph by frequency polygons.
[Hint: First make the class intervals continuous.]
Solution:
Number Of balls

Class Marks

Team A

Team B

.56.5

3.5

2

5

6.512.5

9.5

1

6

12.518.5

15.5

8

2

18.524.5

21.5

9

10

24.530.5

27.5

4

5

30.536.5

33.5

5

6

36.542.5

39.5

6

3

42.548.5

45.5

10

4

48.554.5

51.5

6

8

54.560.5

57.5

2

10

Question 8:
A random survey of the number of children of various age groups playing in a park was found as follows:
Age( in Years)

Number of Children

12

5

23

3

35

6

57

12

710

9

1015

10

1517

4

Draw a histogram to represent the data above.
Question 9:
100 surnames were randomly picked up from a local telephone directory and a frequency distribution of the number of letters in the English alphabet in the surnames was found as follows:
Number of letters

Number of Surnames

14

6

46

30

68

44

812

16

1220

4

 Draw a histogram to depict the given information.
(ii) Write the class interval in which the maximum number of surnames lies
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