- Statistics
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- Presentation of Data
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- Bar Graph
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- Histogram
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- Measures of Central Tendency
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- How to Solve Mean,Median and Mode problem's
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- Solved exmaples

Given below are the **Class 9 Maths** Important Questions for statistics

a) Concepts questions

b) Calculation problems

c) Multiple choice questions

d) Long answer questions

e) Fill in the blank's

a) Concepts questions

b) Calculation problems

c) Multiple choice questions

d) Long answer questions

e) Fill in the blank's

(56/39/40)

5-5.2 |
5.2-5.4 |
5.4-5.6 |
5.6-5.8 |
5.8-6.0 |

34 |
4 |
4 |
4 |
6 |

Sum of five number=5Xmean=200

Sum of four number=4Xmean=112

Subtracting, we get the number=88

Two sections of Class XII having 30 students each appeared for Science Olympiad. The marks obtained by them are shown below:

46 31 74 68 42 54 14 61 83 48 37 26 8 64 57

93 72 53 59 38 16 88 75 56 46 66 45 61 54 27

27 44 63 58 43 81 64 67 36 49 50 76 38 47 55

77 62 53 40 71 60 58 45 42 34 46 40 59 42 29

Student having Marks above 80 are exceptional

Student obtaining below 30 marks are failed

Class |
Frequency |

0-9 |
1 |

10-19 |
2 |

20-29 |
4 |

30-39 |
6 |

40-49 |
15 |

50-59 |
12 |

60-69 |
10 |

70-79 |
6 |

80-89 |
3 |

90-99 |
1 |

- False. Its value is 1
- True
- True.
- True. Lowest value is 8 and highest is 93
- True.
- True

Find x and y so that the ordered data set has a mean of 42 and a median of 35.

17, 22, 26, 29, 34, x, 42, 67, 70, y

(a) X=34, y=77

(b) X=36, y=77

(c) X=77, y=34

(d) X=77, y=36

For what value of n, the mode of the following data is 18?

2, 5, 3, 18, 5, 18, 6, 5, n, 7, 18

(a) 18

(b) 5

(c) It can be any value

(d) None of these

There are three 5 and three 18.

For mode to be 18, n=18

For drawing a frequency polygon of a continuous frequency distribution, we plot the Points whose ordinates are the frequencies of the respective classes and abscissae are respectively:

(a) Class marks of the classes

(b) Upper limits of preceding classes

(c) Lower limits of the classes

(d) Upper limits of the classes

There are 150 numbers. Each number is subtracted from 60 and the mean of the numbers so obtained is found to be –4.5. The mean of the given numbers is

a) 400

b) 34.5

c) 64.5

d) 55.5

Mean of number -60=-4.5

So mean of number is 55.5

The median and mean of the first 10 natural numbers are,

a) 5.5,5.5

b) 5.5,6

c) 5,6

d) None of these

Mean =5.5

Median is mean of 5 and 6 th term, So 5

Anand says that the median of 3, 14, 19, 20, 11 is 19. What doesn’t the Anand understand about finding the median?

a) The dataset should be ascending order

b) Highest no in the dataset is the median

c) Average of lowest and highest is the median

d) None of these

The following observations are arranged in ascending order :

20, 23, 42, 53, x, x + 2, 70, 75, 82, 96

If the median is 63, find the value of

a) 62

b) 64

c) 60

d) None of these

Median is mean of 5 and 6 term

So x+1=63

X=62

The mean of 20 observations was 60. It was detected on rechecking that the value of 125 was wrongly copied as 25 for computation of mean. Find the correct mean

a) 67

b) 66

c) 65

d) None of the above

Let x be the sum of observation of 19 numbers leaving 125,

Then

X+25=20*60=1200

Now

X+125=20*y=20y

Subtracting

125-25=20y-1200

20y=1300

y=65

A histogram |
is the diagram showing a system of connections or interrelations between two or more things by using bars |

Discontinuous Frequency Distribution. |
A frequency distribution in which the upper limit of one class coincides from the lower limit of the succeeding class |

Continuous Frequency Distribution. |
Is the bar graph such that the area over each class interval is proportional to the relative frequency of data within this interval. |

A bar graph |
Is a set of adjacent rectangles whose areas are proportional to the frequencies of a given continuous frequency distribution? |

A frequency distribution in which the upper limit of one class differs from the lower limit of the succeeding class |

Class 9 Maths Class 9 Science

- NCERT Exemplar Problems: Solutions Mathematics Class 9
- IIT Foundation & Olympiad Explorer - Class 9 (Maths)
- Mathematics - Class 9 RD Sharma
- NCERT Solutions - Mathematics for Class IX
- Olympiad Excellence Guide for Mathematics (Class-9)
- MTG Foundation Course for JEE/Olympiads - Class 9 Maths
- Mathematics foundation course for Boards /JEE/PETs/ NTSE

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