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In this page we have Important questions for Factorization Class 8 Maths Chapter 14 . Hope you like them and do not forget to like , social share
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Question 1
User the below expression to solve the below problems
a
2 –b
2 = (a - b )(a + b)
a. x
2 - 81
b. 49a
2 - 36
c. 121 – 49z
2
d. 4x
2 - 9y
2
e. 16x
2 - 225y
2
f. 9x
2y
2 - 25
g. 16x
2 - 81
h. (a + b)
2 - 9c
2
i. a
2 - (x – y )
2
j. 4(x + y)
2 - x
2
k. 36(a + b)
2 - 16(a - b)
2
l. 20x
2 – 45y
2
m. z
3 – 81z
n. 12p
2 - 27
o. 3z
5 – 27z
3
p. 36a
2b
2 - 8
q. z
2 - x
2 – 2x - 1
r. 9x
2 - y
2 + 4y - 4
s. p
2 – 2pq + q
2 - r
2
Solution
a) x2 - 81 = x2 - 92= (x-9)(x+9)
b) 49a2 - 36 =(7a)2 - 62= (7a-6)(7a+6)
c) 121 – 49z2=(11-7z)(11+7z)
d) 4x2 - 9y2=(2x)2-(3y)2=(2x-3y)(2x+3y)
e) 16x2 - 225y2=(4x-15y)(4x+15y)
f) 9x2y2 - 25=(3x-5)(3x+5)
g) 16x2 - 81=(4x-9)(4x+9)
h) (a + b)2 - 9c2=(a + b)2 - (3c)2 =(a+b-3c)(a+b+3c)
i) a2 - (x – y )2=(a-x+y)(a+x-y)
j) 4(x + y)2 - x2= [2(x+y)]2 - x2=[2(x+y) -x][2(x+y)+x]=(x+2y)(3x+2y)
k) 36(a + b)2 - 16(a - b)2 =[6(a+b)]2 - [4(a-b)]2 =[6(a+b) -4(a-b)][6(a+b) +4(a-b)]=(2a+10b)(10a+2b)=4(a+5b)(5a+b)
l) 20x2 – 45y2= 5(4x2 - 9y2) =5(2x-3y)(2x+3y)
m) z3 – 81z=z(z2 - 81)=z(z-9)(z+9)
n) 12p2 - 27= 3(4p2 - 9)=3(2p-3)(2p+3)
o) 3z5 – 27z3=3z3(z2 -9) =3z3(z-3)(z+3)
p) 36a2b2 - 8= 8( 4a2b2 -1) =8(2ab+1)(2ab-1)
q) z2 - x2 – 2x - 1= z2 -( x2 +2x + 1)=z2 -(x+1)2=(z-x-1)(z+x+1)
r) 9x2 - y2 + 4y - 4 =9x2 -(y2 - 4y + 4)=9x2 -(y-2)2= (3x-y+2)(3x+y-2)
s) p2 – 2pq + q2 - r2=(p-q)2 - r2=(p-q-r)(p-q+r)
Question 2
User the below expression to solve the below problems
(a+b)
2 = (a
2 + b
2 +2ab)
(a-b)
2 = (a
2 + b
2 -2ab)
a. p
2 + 4p + 4
b. x
2 + 18x + 81
c. 9 + 6z + z
2
d. 9 + 6x + x
2
e. z
2 + 6xz + 9x
2
f. 9x
2 + 30x +25
g. 36z
2 + 12z + 1
h. 9x
2 + 30x + 25
i. z
2 + z + 1/4
j. 4z
2 – 6z + 9
k. 4p
2 – 20p + 25
l. 9x
2 - 30x + 25
m. 1 – 2y + y
2
n. 4 – 12y+ 9y
2
o. x
2y
2 - 6xyz + 9z
2
p. p
2 – 6pq + 9p
2
Solution
a) p2 + 4p + 4 =(p+2)2
b) x2 + 18x + 81= x2 + 2*9*x + 92= (x+9)2
c) 9 + 6z + z2=(z+3)2
d) 9 + 6x + x2=(x+3)2
e) z2 + 6xz + 9x2=(z+3x)2
f) 9x2 + 30x +25=(3x+5)2
g) 36z2 + 12z + 1=(6z+1)2
h) 9x2 + 30x + 25= (3x+5)2
i) z2 + z + 1/4= (z+1/2)2
j) 4z2 – 6z + 9= (2z-3)2
k) 4p2 – 20p + 25= (2p+5)2
l) 9x2 - 30x + 25=(3x-5)2
m) 1 – 2y + y2= (y-1)2
n) 4 – 12y+ 9y2= (3y-2)2
o) x2y2 - 6xyz + 9z2=(xy-3z)2
p) p2 – 6pq + 9p2=(p-3q)2
Question 3
Find and correct the errors in the statement: (3
x)
2 + 5
x = 9
x + 5
x = 14x
Solution
LHS = (2x)2 + 5x =4x2+5x
RHS = 9x + 5x = 14x
Third = 14x
LHS≠ RHS =third part
Correct statement would be
(3x)2 + 5x = 9x2+5x
Question 4
Find and correct the errors in the statement: (4
x + 2)
2 = 2
x2 + 16x + 4
Solution
LHS = (4x + 2)2 =16x2 +16x+4
RHS = 2x2 + 16x + 4
LHS≠ RHS
Correct statement would be
(4x + 2)2 =16x2 +16x+4
Question 5
Find and correct the errors in the statement: (
z - 1)
2 =
z2 - 1
Solution
LHS = (z - 1)2 =z2 -2z+1
RHS = z2 - 1
LHS≠ RHS
Correct statement would be
(z - 1)2 =z2 -2z+1
Question 6
Find and correct the errors in the statement: (
y + 6)
2 =
y2 + 36
Solution
LHS=( y + 6)2 =y2 +12z+36
RHS = y2 + 36
LHS≠ RHS
Correct statement would be
( y + 6)2 =y2 +12z+36
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Class 8 Maths
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