(i) Terms xyz2, 3xy coefficients 1,3Answer
(ii)Terms 1,-x,-2x2 Coefficients 1, -1,-2
(iii)Terms 4p2q2,-4p2q2r2,r2 Coefficients 4,-4,1
(iv) Terms 4,-xy,yz,-xz Coefficients 4,-1,1,-1
(v) Terms x/4, -y/5 ,-y Coefficients 1/4,-1/5,-1
(vi) Terms 1.3a,-2.6ab,1.5b Coefficients 1.3,-2.6 ,1.5
(a)x2 + y2: BinomialAnswer
(b)1000-x:Binomial
(c)x + x2+ x3 + x4 + x5:polynomial
(d)8 - y -5x:Trinomial
(e) 2y -3y2:Binomial
(f) 2y - 3y+ 4y3:Trinomial
(g) 5x -8y + 3xy:Trinomial
(h) 4 -15z2:Binomial
(i) ab + bc + cd + da+ 2ab:polynomial
(j) pqr+2pq+5pqr:Binomial
(k) p2q + pq2:Binomial
(l) 2p + 2q+1:Trinomial
(i) ab - bc+ ac + bc - ca+ ab +ca - ab-2bc=ab-2bc+acAnswer
(ii)p - q + pq + q - r + qr + r - p + pr + p+q+r=p+q+pq+r+qr+pr
(iii)2p2q2- 3pq + 4 + 5 + 7pq - 3p2q2 + 4p2q2 + 10pq=3p2q2+14pq+9
(iv) a2+ b2+ b2+ c2+ c2+ a2+ 2ab + 2bc + 2ac=2(a2+ b2+c2+ab+bc+ac)
While subtracting, we need to remember signs are reversed after sign once bracket is opened
ie. + becomes - and - becomes +
Let solve the below question keeping that in mind
(a) 20a - 9ab + 5b - 20 -(8a - 7ab + 3b - 20)=20a - 9ab + 5b - 20-8a +7ab-3b+20 =12a+2b -2abAnswer
(b) -4pq +2qr - 2pr + 5pqr+1 -( 3pq + 5qr - 7pr+1 )=-4pq +2qr - 2pr + 5pqr+1 -3pq-5qr+7pr-1=-7pq -3qr+5pr+5pqr
(c) 18 - 3p - 11q + 5pq - 2pq2+ 5p2q -(4p2q - 4pq - 5pq2 - 8p + 7q - 18)= 18 - 3p - 11q + 5pq - 2pq2+ 5p2q -4p2q+4pq +5pq2+8p-7q+18=36-3p-18q+9pq+3pq2+5p2q -4p2q
Answer is (a)
Answer
Answer is (b)
Answer
Answer is (d)
Answer
Answer is (a) as it sums to 3pqr
Answer
Answer is (a) as it sums to 2c + ab ac bc
Answer
Answer is (c) as $(a + b)^2 + (a - b)^2=a^2 + b^2 + 2ab +a^2 + b^2 - 2ab=2a^2 + 2b^2$ Answer
(p) -> (iii)
(q) -> (iv)
(r) -> (ii)
(s) -> (i)
Answer
This algebraic expressions and identities class 8 important questions is prepared keeping in mind the latest syllabus of CBSE . This has been designed in a way to improve the academic performance of the students. If you find mistakes , please do provide the feedback on the mail.