NCERT solutions for class 8 maths chapter 9 exercise 9.2

In this page we have ncert solutions for class 8 maths chapter 9 exercise 9.2 for
Algebraic Expressions .This exercise has questions about multiplication of polynomials like mononial to monomials. Hope you like them and do not forget to like , social share
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NCERT solutions for class 8 maths chapter 9 EX 9.2

Question 1
Find the product of the following pairs of monomials.
(i) 4, 7p
(ii) - 4p, 7p
(iii) - 4p, 7pq
(iv)4p^{3}, - 3p
(v) 4p, 0 Answer:

4 x 7p = 28p

- 4p x 7p = -28p^{2}

- 4p x 7pq = -28p^{2}q

4p^{3} x - 3p = -12p^{4}

4p x 0 = 0

Question 2
Find the areas of rectangles with the following pairs of monomials as their lengths and breadths respectively.

(p, q)

(10m, 5n)

(20x^{2} 5y^{2})

(4x, 3x^{2})\

(3mn, 4np)

Answer
Now we know that
Area of rectangle = Length x breadth
So it is multiplication of monomials
(i) p x q = pq
(ii)10m x 5n = 50mn
(iii) 20x^{2} x 5y^{2}= 100x^{2}y^{2}
(iv) 4x x 3x^{2} = 12x^{3}
(v)3mn x 4np = 12mn^{2}p

Question 3.
Complete the following table of products:

Answer

Question 4
Obtain the volume of rectangular boxes with the following length, breadth and height respectively.

5a, 3a^{2}, 7a^{8}

(2p, 4q, 8r)

xy, 2x^{2}y, 2xy^{2}

(a, 2b, 3c

Answer
We know that volume of rectangular box is given by
Volume = length x breadth x height
(i)5a x 3a^{2} x 7a^{8} = 105a^{11}
(ii) 2p x 4q x 8r = 64pqr
(iii) xy x 2x^{2}y x 2xy^{2} = 4x^{4}y^{4}
(iv) a x 2b x 3c = 6abc

NCERT solutions for class 8 maths chapter 9 exercise 9.2 has been prepared by Expert with utmost care. If you find any mistake.Please do provide feedback on mail. You can download the solutions as PDF in the below Link also Download Algebraic Expressions Exercise 9.2 as pdf

This chapter 9 has total 5 Exercise 9.1 ,9.2 ,9.3 ,9.4 and 9.5. This is the Second exercise in the chapter.You can explore previous exercise of this chapter by clicking the link below