Class 8 Maths Exercise 8.3 Solutions : Algebraic Expressions and Identities
In this page we have Class 8 Maths Exercise 8.3 Solutions for
Algebraic Expressions and Identities. This exercise has questions about multiplication of polynomials like mononial to binomial and mononial to Trinomial. Hope you like them and do not forget to like , social share
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Class 8 Maths Exercise 8.3 Solutions
Question 1
Carry out the multiplication of the expressions in each of the following pairs.
(i) 4p, q + r
(ii) ab, a - b
(iii) a + b, 7a²b²
(iv) a2- 9, 4a
(v) pq + qr + rp, 0 Answer:
4p(q + r) = 4pq + 4pr
ab(a - b) = a2b - ab2
(a + b) (7a2b2) = 7a3b2 + 7a2b3
(a2 - 9)(4a) = 4a3 - 36a2
(pq + qr + rp) x 0 = 0
Question 2
Complete the table.
Answer:
(i) a(b + c + d) = ab + ac + ad
(ii) (x + y – 5) 5xy= 5x2y + 5xy2 -25xy
(iii)p(6p2– 7p + 5)=6p3 -7p2 +5p
(iv) 4p2q2(p2 - q2)=4p4q2 -4p2q4
(v) (a + b + c)abc= a2bc + ab2c + abc2
Question 2
Find the product.
(i) a2 x (2a22) x (4a26)
(ii) (2xy/3) ×(-9x2y2/10)
(iii) (-10pq3/3) ×(6p3q/5)
(iv) x (x2) x (x3) x (x8) Answer:We will use the below property extensively in above questions am x an x ao = am+n+o
(i) As you know
So, we get a2 x (2a22) x (4a26) = 8a48
(ii) (2xy/3) ×(-9x2y2/10) =(-3x3y3/5)
(iii) (-10pq3/3) ×(6p3q/5) =(-4p4q4)
(iv)( x) x (x2) x (x3) x (x8)
= x14
Question 3
(a) Simplify 3x (4x - 5) + 3 and find its values for (i) x = 3 (ii) x =1/2
(b) Simplify a (a2+ a + 1) + 5 and find its value for (i) a = 0, (ii) a = 1 (iii) a = - 1. Answer
(a)
(i) Putting x=3 in the equation we get
12x2 - 15x + 3
=108-45+3 = 66
(ii) putting x=1/2 in the equation we get
$12 \times \frac {1}{2} - \frac {15}{2} + 3 =3 - \frac {15}{2} -3=\frac {-3}{2}$
(b)
a(a2a+1)
=a3+a2+a
(i) putting a= 0 in the equation we get
03+02+0=0
(ii) putting a=1 in the equation we get
13 + 12 + 1 = 1 + 1 + 1 = 3
(iii) Putting a = -1 in the equation we get
-13+12 -1 = -1 + 1 + 1 = 1
Question 5
(a) Add: p ( p - q), q ( q - r) and r ( r - p)
(b) Add: 2x (z - x - y) and 2y (z - y - x)
(c) Subtract: 3l (l - 4 m + 5 n) from 4l ( 10 n - 3 m + 2 l )
(d) Subtract: 3a (a + b + c ) - 2 b (a - b + c) from 4c ( - a + b + c ) Answer:
(a) (p2 - pq) + (q2 - qr) + (r2 - pr)
= p2 + q2 + r2 - pq - qr - pr
(b) (2xz - 2x2 - 2xy) + (2yz - 2y2 - 2xy)
= 2xz - 4xy + 2yz - 2x2 - 2y2
(c) (40ln - 12lm + 8l2) - (3l2 - 12lm + 15ln)
= 40ln - 12lm + 8l2 - 3l2 - 12lm + 15ln
= 55ln - 24lm + 5l2
(d) = (-4ac + 4bc + 4c2) - (3a2 + 3ab + 3ac)
= -4ac + 4bc + 4c2 - 3a2 - 3ab - 3ac
= -7ac + 4bc + 4c2 - 3a2 - 3ab
Summary
Class 8 Maths Exercise 8.3 Solutions has been prepared by Expert with utmost care. If you find any mistake.Please do provide feedback on mail. You can download the solutions as PDF in the below Link also Download Class 8 Maths Exercise 8.3 as pdf
This chapter 8 has total 4 Exercise 8.1 ,8.2 ,8.3 ,8.4 as per latest syllabus. Exercise 8.5 is deleted as per latest syllabus. This is the Third exercise in the chapter.You can explore previous exercise of this chapter by clicking the link below
