Given below are the Class 10 Maths Problems for Linear equation
a. Concepts questions
b. Calculation problems
c. Multiple choice questions
d. Long answer questions
e. Fill in the blank's
Question 1. In a cyclic quadrilateral ABCD,Find the four angles.
a. $\angle A = (2x + 4)$, $\angle B = (y + 3)$, $\angle C = (2y + 10)$, $\angle D = (4x -5)$.
b. $\angle A = (2x - 1)$, $\angle B = (y + 5)$, $\angle C = (2y + 15)$ and $\angle D = (4x -7)$ Solution
a. $\angle A = (2x + 4)$, $\angle B = (y + 3)$, $\angle C = (2y + 10)$, $\angle D = (4x -5)$
In a cyclic quadrilateral, Opposite angles are supplementary.
$\angle A + \angle C = 180^0$ and $\angle B + \angle D = 180^0$
So $2x+4+2y+10=180$ or $x+y=83$
$y+3+4x-5=180$ or $y+4x=182$
Solving the above equation by Substitution method
x=33 and y=50
So Angles are
70^{0},53^{0},110^{0},127 ^{0}
b) $\angle A = (2x - 1)$, $\angle B = (y + 5)$, $\angle C = (2y + 15)$ and $\angle D = (4x -7)$
Solving similarly, we get
65^{0}, 55^{0}, 115^{0}, 125^{0}
Question 2. Given below are three equations. Two of them have infinite solutions and two have a unique solution. State the two pairs:
$3x - 2y = 4$
$6x + 2y = 4$
$9x -6y = 12$ Solution
For Infinite solution:
We have $\frac{a_1}{a_2} = \frac {b_1}{b_2} = \frac {c_1}{c_2}$ is the equation for infinite solution.
Equation 1 and 3 is satisfying the condition
$3x-2y=4$; $9x-6y=12$
3/9 = -2/-6 = 4/12
This also means equation 1 and equation 3 are same
Unique solution:
We have a1/a2 is not equal to b1/b2 is the equation for the unique solution.
Equation 1 and 2 and Equation 2 and 3 is satisfying the condition
3x-2y=4; 6x+2y=4 & 6x+2y=4; 9x-6y=1
3/6 is not equal to -2/2 & 6/9 is not equal to 2/-6.
Question 3 Find the values of a and b for which the following system of linear equations has infinite number of solutions:
$2x + 3y = 7$
$2ax + (a + b)y = 28$ Solution
We have
$\frac{a_1}{a_2} = \frac {b_1}{b_2} = \frac {c_1}{c_2}$
$\frac{2}{2a} = \frac {3}{a+b} = \frac {7}{28}$
Solving this , we get a=4 and b=8
Question 4 Find the values of a and b for which the following system of linear equations has infinite number of solutions:
$2x -3y = 7$
$(a + b)x - (a + b- 3)y = 4a + b$ Solution
We have
$\frac{a_1}{a_2} = \frac {b_1}{b_2} = \frac {c_1}{c_2}$
$\frac{2}{a+b} = \frac {-3}{a+b-3} = \frac {7}{4a+b}$
$\frac{2}{a+b} = \frac {-3}{a+b-3}$
a+b+6=0 -(1)
$\frac {-3}{a+b-3} = \frac {7}{4a+b}$
5a-4b+21=0 -(2)
Solving (1) and (2) by substitution method we get
a=-5,b=-1
Question 5. In a ABC, $\angle A = x$, $\angle B = (3x -2)$, $\angle C = y$ Also $\angle C - \angle B = 9$. Find the three angles. Solution
In a triangle,sum of angles is equal to 360^{0}
So
$x+ (3x-2) + y=180$ or $4x+y=182$ -(1)
Also given
$\angle C - \angle B = 9$ or $y-(3x-2)=9$ or $y-3x=7$ or $y=7+3x$
Substituting this in (1)
$4x+ 7+3x=182$
$7x=175$
$x=25$
So angles are
25,73, 82
Question 6. Find the value of k for which the system of equations x + 2y -3 = 0 and ky + 5x + 7 = 0 has a unique solution. Solution
For unique solution
$\frac {a_1}{a_2} \neq \frac {b_1}{b_2}$
Subsituting the values
$\frac {1}{5} \neq \frac {2}{k}$
$k\neq10$
Question 7 For what value of a the system of linear equations $2x + 3y = 7$ and $(a -1)x + (a + 1)y = 3a - 1$ represent parallel lines. Solution
For parallel lines
$\frac{a_1}{a_2} = \frac {b_1}{b_2} = \frac {c_1}{c_2}$
$\frac{2}{a-1} = \frac {3}{a+1} = \frac {7}{3a-1}$
or a=5
Question 8 If the lines $x + 2y + 7 = 0$ and $2x + ky + 18 = 0$ intersect at a point, then find the value of k. Solution
For unique solution
$\frac {a_1}{a_2} \neq \frac {b_1}{b_2}$
Subsituting the values
$\frac {1}{2} \neq \frac {2}{k}$
$k\neq4$
Question 9 Is $x = 5, y = -5$ a solution of the linear equation $3x + 2y - 5 = 0$? Solution
3(5) +2(-5) -5=0
So x=5 and y=-5 is solution of the equation
Question 10. The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. Find the present ages of the son and the father. Solution
let Father age is y and son age is x
First condition
$y=6x$
Second condition
$y+4=4(x+4)$
So we have
$6x+4=4x+16$
x=6 and y=36
Question 11. Replace p by an appropriate number so that the following system of equations has a unique solution.
$2x + 3y = 5$
$px +9y = 12$
Question 12. For what value of k, the following pair of linear equations has infinitely many solutions?
i. $kx + 4y - (k + 8) = 0$
$4x + ky + 4 = 0$
ii. $2x + 3y = 4$
$(k + 2)x + 6y = 3k + 2$ Solution
For infinite many solutions
$\frac{a_1}{a_2} = \frac {b_1}{b_2} = \frac {c_1}{c_2}$
i)
$\frac{k}{4} = \frac {4}{k} = \frac {-(k+8)}{4}$
Taking first two
k^{2}=16
or k=+4 or -4
for k=4, the condition becomes
$\frac{4}{4} = \frac {4}{4} \neq \frac {-12}{4}$
So it is not correct
For k=-4, the condition becomes
$\frac{-4}{4} = \frac {4}{-4} = \frac {-4}{4}$
So k=-4 is the solution
ii)
$\frac{2}{k+2} = \frac {3}{6} = \frac {4}{3k+2}$
Taking First two
k+2=4
or k=2
So condition becomes
$\frac{2}{4} = \frac {3}{6} = \frac {4}{8}$
So it is the correct solution
Question 13 For what value of k, will the following system of equations have no solutions?
i. $(3k + 1) x + 3y = 2$
$(k^2 + 1) x + (k - 2) y = 5$
ii. $3x + y = 1$
$(2k - 1) x + (k - 1) y = 2k + 1$
iii.
$2x + ky = 11$
$5x -7y = 5$
Question 14. For what value of k, does the pair of equations given below has a unique solution?
$2x + ky = 6$
$4x + 6y = 0$
Question 15. Find the value of k for which the following system of linear equations has infinite solutions:
i. $x + (k + 1) y = 5$
$(k + 1) x + 9y = 8k - 1$
ii.
$8x + 5y = 9$
$kx + 10y = 18$
iii. $2x + 3y = k$
$(k - 1) x + (k + 2) y = 3k$
Question 16 For what value of α, the system of equations
$ \alpha x + 3y = \alpha - 3$
$12x + \alpha y = \alpha $
will have no solution? Answer
-6
Question 17. Find the value of k for which the system
$kx + 2y = 5$
$3x + y = 1$
has (i) a unique solution, and (ii) no solution. Answer
k ≠6 , k=6
Question 18. Find the value of k for which the system
$2x + ky = 1$
$3x - 5y = 7$
has (i) a unique solution, and (ii) no solution. Answer
k ≠ -10/3 , k=10/3
Question 19 find the value of a and b for which the following system of equations has infinitely many solutions:
$2x - (2a + 5) y = 5$
$(2b + 1) x - 9y = 15$ Answer
(-1, 5/2) Question 20. Find the value of a for which the following system of equations has infinitely many solutions:
$2x + 3y - 7 = 0$
$(a - 1) x + (a + 1) y = (3a - 1)$ Answer
a=5
link to this page by copying the following text Also Read
Thanks for visiting our website. DISCLOSURE: THIS PAGE MAY CONTAIN AFFILIATE LINKS, MEANING I GET A COMMISSION IF YOU DECIDE TO MAKE A PURCHASE THROUGH MY LINKS, AT NO COST TO YOU. PLEASE READ MY DISCLOSURE FOR MORE INFO.