physicscatalyst.com logo





Practice questions for Mensurations




In this page we have Practice questions for Mensurations Class 8 maths Chapter 11 . Hope you like them and do not forget to like , social share and comment at the end of the page.
Question 1
There are two cuboidal whose dimensions are given below. Which box requires the higher amount of material to make?
Cuboid A: L=23, B=30, H=40
Cuboid B: L=30, B=12, H=44

Answer

Material will be measures by the surface area
Surface Area of Cuboid A= 2(LB + BH+ LH) = 2(23 *30 + 30*40 + 23 *40) =2*2810 cm2
Surface Area of Cuboid B= 2(LB + BH+ LH) = 2(30*12 + 12*44 + 30 *44) =2*2208 cm2
So Cuboid A will require the higher amount of material to make


Question 2
Three cubes, each of edge 2 cm. long are placed together. Find the total surface area of the cuboid so formed?
Practice questions for Mensurations Class 8 maths  Chapter 11

Answer

L = 2+ 2 + 2= 6 cm
B=2 cm
H=2 cm
Surface Area of Cuboid = 2(LB + BH+ LH) = 2(6 *2 + 2*2 + 6 *2) =56 cm2


Question 3
Find the side of a cube whose surface area is 2400 cm2.

Answer

Surface of cube= 6a2
So , 6a2=2400
a=20 cm


Question 4
Meghna painted the outside of the cabinet of measure 2 m × 3 m × 2.5 m. How much surface area did she cover if she painted all except the bottom of the cabinet and back side?

Answer

Here L=2 m, B=3 m and H=2.5 m
Total surface area of a cuboid =2LB+2BH+2LH Now is she left bottom and back side of box area covered is =2LB+2BH+2LH-LB-LH = LB+2BH+LH =(2*3)+2(3*2.5)+(2.5*2) = 26m2


Question 5
Ahmed is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 25 m, 12 m and 8 m respectively. From each can of paint 200 m² of area is painted. How many cans of paint will she need to paint the room?

Answer

Here L=25 m, B=12 m and H=8 m
Area to be painted= Area of lateral surface + Area of Ceiling
=2(LH) + 2(BH) + LB
=892 m2
Theerefore, no of cans required= 892/200
=4.5 cans


Question 6
A open cylindrical tank of radius 14 m and height 3 m is made from a sheet of metal. How much sheet of metal is required?

Answer

here r=14 m and h=3 m
Sheet of metal require = total surface area of Cylinder = 2 π rh + π r2
=880 m2


Question 7
The lateral surface area of a hollow cylinder is 4224 cm2. It is cut along its height and formed a rectangular sheet of width 33 cm. Find the perimeter of rectangular sheet?

Answer

Here B= 33 cm
Area of Rectangular Sheet formed = Surface Area of the Cylinder
Area of Rectangle = L × B
Therefore
L × B= 4224
Putting the value of B and solving
L=4224/33=128 cm
Now
Perimeter Of Rectangle=2(L+B) = 2(128+33)
=322cm




Question 8
A road roller takes 750 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 154 cm and length is 1 m.

Answer

Length of roller = 1m = 100cm , Diameter of road roller = 154 cm
Circumference of roller = 2 π r= π D = 22/7 * 154 = 484 cm
Now Length travelled in 1 rev= Circumference of road roller
Therefore
Length of road = Length travelled in 750 = 750 * Circumference of road roller = 363,000 cm
Width of road = length of roller = 100 cm
Area of road = Area of rectangle = L * B = 363,000 * 100 = 363 * 105 cm 2


Question 9
A rectangular sheet of metal foil is 88 cm. long and 20 cm. wide. A cylinder is made out of it, by rolling the foil along width. Find the volume of the cylinder.

Answer

L = 88 cm
B= 20 cm
As per the question,Since cylinder is made out of it, by rolling the foil along width ,the circumference will be equal to the breadth of the sheet and the length will be the height of the cylinder.
Circumference=2 π r= 20 cm
or r= 10/π
Height of the cylinder = 88 cm
Now volume = π r^2 h = 88 *100/π = 2800 cm2


Question 10
The perimeter of the floor of a hall is 250 m. If the height is 4 m, find the cost of painting the four walls at the rate of Rs. 12 per square meter.

Answer

Surface area to be painted = 2(LH+BH) = 2H(L+B)
given perimeter of floor = 250m = 2(L+B)
and height is 4m
Substituting these values
Surface area=1000 m2
cost of painting 1 square metre=Rs 12
cost of painting 1000 square metre=1000*12= Rs 12000


Question 12
How many times do the volume and surface area of a cube increase if its edges get tripled.

Answer

$V_1=L^3$ and $SA_1= 6L^2$
$V_2= (3L)^3 = 27L^3$ and $SA_2=6(3L)^2 = 9 \times 6L^2$
So, Volume becomes 27 times and Surface Area become 9 times


Question 13
How many times do the volume and Lateral surface area of a cylinder increase if its radius doubled and height remains same

Answer

$V= \pi r^2 h$ and $SA= 2 \pi rh$
If radius is doubled and height remains same ,then
$V_2= \pi (2r)^2 h = 4 \pi r^2 h$
$SA_2 = 2 \pi (2r) h =2 \times 2 \pi rh$
So volume becomes four times and Surface area becomes doubled


Question 14
How many times do the volume and Lateral surface area of a cylinder increase if its radius remains same and height is doubled

Answer

$V= \pi r^2 h$ and $SA= 2 \pi rh$
if its radius remains same and height is doubled ,then
$V_2= \pi r^2 (2h) = 2 \pi r^2 h$
$SA_2 = 2 \pi r (2h) =2 \times 2 \pi rh$
So volume becomes doubled and Surface area becomes doubled


Question 15
The height of a cylinder is 30 cm. and curved surface area is 660 cm2. Find the radius of the cylinder

Answer

$2 \pi rh= 660$
$ 2\times (22/7) \times r \times 30 = 660$
r=3.5 cm


Summary

This Practice questions for Mensurations Class 8 maths is prepared keeping in mind the latest syllabus of CBSE . This has been designed in a way to improve the academic performance of the students. If you find mistakes , please do provide the feedback on the mail.


Download Practice questions for Mensurations Class 8 as pdf
Also Read




Class 8 Maths Class 8 Science


Latest Updates
Synthetic Fibres and Plastics Class 8 Practice questions

Class 8 science chapter 5 extra questions and Answers

Mass Calculator

3 Fraction calculator

Garbage in Garbage out Extra Questions7