(a) VolumeAnswer
(b) Surface Area
(c) Volume
(a) Volume of Cube =123 =1728Answer
Volume of Cuboid =11 *12 * 13 =1716
So cube is having more volume
(b) Volume of cylinder= π (10)2 14 =4400
Volume of Cuboid =10 *11 * 14 =1540
So cylinder is having more volume
(a) Volume = $L \times B \times H = (L \times B) \times H =\text(Base Area) \times H$Answer
$900=180 \times H$
or H=5 cm
(b) Volume of Cube = (side)3
$\text{side} =\sqrt [3] {Volume} = 4 \ cm$
(c) Volume of Cylinder = $ \pi r^2 h = (\pi r^2) \times h = \text{base area} \times h = 20 \times 10 =200 \ cm^2$
Volume of Cuboid= 60 × 54 × 30 =97200 cm3Answer
Volume of Cube = (12)3=1728 cm3
Total number of cube which can be placed in cuboid= 97200/1728= 56.25 =56
Volume of Cylinder = $ \pi r^2 h= \frac {\pi D^2 h}{4}$Answer
Therefore
$\frac {\pi (1.4)^2 h}{4}= 2.54$
h=1.64 m
Volume of water tank=1.5 × 2 × 7 =21 m3Answer
Now 1m3=1000 L
So quantity of water stored= 21000 L
$V_1=L^3$ and $SA_1= 6L^2$Answer
$V_2= (4L)^3 = 64L^3$ and $SA_2=6(4L)^2 = 16 \times 6L^2$
So, Volume becomes 64 times and Surface Area become 16 times
volume of reservoir = 108 m³=108000 LAnswer
Number of minute= 108000 /60=1800 minutes= 30 hours
$V=LBH$ and $SA= 2(LB + BH+ LH)$Answer
If Length, Breath, Height of a cuboid is tripled
$V_f= 3L \times 3B \times 3H= 27 LBH$
$SA_F= 2(3L \times 3B + 3B \times 3H + 3L \times 3H)=9 \times 2(LB + BH+ LH) $
So volumen increased by 27 times and Surface area increased by 9 times
$V= \pi r^2 h$ and $SA= 2 \pi rh$Answer
If radius of cylinder is tripled and height remains same,then
$V_2= \pi (3r)^2 h = 9 \pi r^2 h$
$SA_2 = 2 \pi (3r) h =3 \times 2 \pi rh$
So volume becomes 9 times and Surface area becomes 3 times
This Extra questions for Mensurations Class 8 Maths is prepared keeping in mind the latest syllabus of CBSE . This has been designed in a way to improve the academic performance of the students. If you find mistakes , please do provide the feedback on the mail.