- Mensuration
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- Area of Trapezium
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- Area of General Quadrilaterals
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- Solid Shapes
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- Volume,Surface area in case of Solid Figures
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- How to find the surface Area and Volume of the solid Figures
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- Surface Area and Volume of Cube and Cubiod
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- Surface Area and Volume of Right circular cylinder

In this page we have *NCERT Solutions for Mensurations Class 8 Mathematics Chapter 11* for
EXERCISE 3 . Hope you like them and do not forget to like , social share
and comment at the end of the page.

There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?

Volume of the Cuboid is given by

= Lx B x H

= 60 x 40 x 50 = 12000 cm

Volume of Cube = Side

=50

As the volume of the cube is greater than that of the cuboid so it will require more material, and the cuboid will require less material

A suitcase with measures 80 cm × 48 cm × 24 cm is to be covered with a tarpaulin cloth. How many metres of tarpaulin of width 96 cm is required to cover 100 such suitcases?

Surface Area of Cuboid is given by

= 2(LB + LH + BH)

= 2 (80 x 48 + 80 x 24 + 48 x 24)

= 2(3840 + 1920 + 1152)

= 2 x 6912 = 13824

Hence, Surface Area of 100 suitcases = 1382400 cm

Required tarpaulin will have same area

So required length of tarpaulin= Area /width

=1382400/96= 14400 cm=144 m

Find the side of a cube whose surface area is 600 cm

Let a be the side

Surface Area = 6 x side

600 = 6 x a

a

a = 10 cm

Rukhsar painted the outside of the cabinet of measure 1 m × 2 m × 1.5 m. How much surface area did she cover if she painted all except the bottom of the cabinet?

Surface Area of Cabinet = 2(LB + LH + BH)

= 2(1 x 2 + 1 x 1.5 + 1.5 x 2)

= 2(2 + 1.5 + 3) = 2 x 6.5 = 13

Area of Bottom Surface = 1 x 2 = 2 m

Hence, Area Covered by painting = 13-2 = 11 m

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m² of area is painted. How many cans of paint will she need to paint the room?

Area of All walls, ceilings and floor = 2(LB + LH + BH)

= 2(15 x 10 + 15 x 7 + 10 x 7)

= 2(150 + 105 + 70)

= 2 x 325 = 650

Area of Floor = 15 x 10 = 150

Hence, Painted Area =650-150=500

As, one can of paint is enough for 100 sq m

So, 500/100 = 5 cans are needed to paint the hall.

Describe how the two figures given below are alike and how they are different. Which box has larger lateral surface area?

The similarity is that their dimensions are equal

The difference is the figure on the left is cylindrical and that on the right is cuboidal.

Lateral Surface area of cylinder= 2πrh= 154 cm

Surface Area of Cube= 4×side

It is clear that the cylinder is having a larger surface area.

A closed cylindrical tank of radius 7 m and height 3 m is made from a sheet of metal. How much sheet of metal is required?

Surface Area of cylinder= 2πrh + 2πr

=440 m

The lateral surface area of a hollow cylinder is 4224 cm

Area of Rectangular Sheet = Surface Area of the Cylinder

Area of Rectangle = Lx B

Or, Lx B = 4224

Lx 33 = 4224

L=128 cm

A road roller takes 750 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 84 cm and length is 1 m.

In one revolution the wheel of the roller will cover an area equal to its surface area.

Curved Surface Area of cylinder=2 πrh

=26400 cm

A company packages its milk powder in cylindrical container whose base has a diameter of 14 cm and height 20 cm. Company places a label around the surface of the container (as shown in the figure). If the label is placed 2 cm from top and bottom, what is the area of the label.

Height = 20-4 = 16 cm

Curved Surface area of cylinder= 2 πrh

=704 cm

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Class 8 Maths Class 8 Science

Given below are the links of some of the reference books for class 8 Math.

- Mathematics Foundation Course for JEE/Olympiad : Class 8 This book can take students maths skills further. Only buy if child is interested in Olympiad/JEE foundation courses.
- Mathematics for Class 8 by R S Aggarwal Detailed Mathematics book to clear basics and concepts. I would say it is a must have book for class 8 student.
- Pearson Foundation Series (IIT -JEE / NEET) Physics, Chemistry, Maths & Biology for Class 8 (Main Books) | PCMB Combo : These set of books could help your child if he aims to get extra knowledge of science and maths. These would be helpful if child wants to prepare for competitive exams like JEE/NEET. Only buy if you can provide help to the child while studying.
- Reasoning Olympiad Workbook - Class 8 :- Reasoning helps sharpen the mind of child. I would recommend students practicing reasoning even though they are not appearing for Olympiad.

You can use above books for extra knowledge and practicing different questions.

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