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NCERT Solutions for Mensurations Class 8 Mathematics Chapter 11 CBSE Part 3





In this page we have NCERT Solutions for Mensurations Class 8 Mathematics Chapter 11 for EXERCISE 3 . Hope you like them and do not forget to like , social share and comment at the end of the page.
Question 1
 There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?
NCERT Solutions for Mensurations Class 8 Mathematics
Answer
Volume of the Cuboid   is given by
= Lx B x H
= 60 x 40 x 50 = 12000 cm3
Volume of Cube = Side3
=503 = 125000 cm3
As the volume of the cube is greater than that of the cuboid so it will require more material, and the cuboid will require less material
Question 2
A suitcase with measures 80 cm × 48 cm × 24 cm is to be covered with a tarpaulin cloth. How many metres of tarpaulin of width 96 cm is required to cover 100 such suitcases?
Answer
 Surface Area of Cuboid is given by
= 2(LB + LH + BH)
= 2 (80 x 48 + 80 x 24 + 48 x 24)
= 2(3840 + 1920 + 1152)
= 2 x 6912 = 13824
Hence, Surface Area of 100 suitcases = 1382400 cm2
Required tarpaulin will have same area
So required length of tarpaulin= Area /width
=1382400/96= 14400 cm=144 m

Question 3
 Find the side of a cube whose surface area is 600 cm2.
Answer
Let a be the side
Surface Area = 6 x side2
600 = 6 x a2
a2 = 100
a = 10 cm
Question 4
 Rukhsar painted the outside of the cabinet of measure 1 m × 2 m × 1.5 m. How much surface area did she cover if she painted all except the bottom of the cabinet?
Answer
Surface Area of Cabinet = 2(LB + LH + BH)
= 2(1 x 2 + 1 x 1.5 + 1.5 x 2)
= 2(2 + 1.5 + 3) = 2 x 6.5 = 13
Area of Bottom Surface = 1 x 2 = 2 m2
Hence, Area Covered by painting = 13-2 = 11 m2
Question 5
 Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m² of area is painted. How many cans of paint will she need to paint the room?
Answer
 Area of All walls, ceilings and floor = 2(LB + LH + BH)
= 2(15 x 10 + 15 x 7 + 10 x 7)
= 2(150 + 105 + 70)
= 2 x 325 = 650
Area of Floor = 15 x 10 = 150
Hence, Painted Area =650-150=500
As, one can of paint is enough for 100 sq m
So, 500/100 = 5 cans are needed to paint the hall.

Question 6
 Describe how the two figures given below are alike and how they are different. Which box has larger lateral surface area?

NCERT Solutions Free pdf download
Answer:
The similarity is that their dimensions are equal
The difference is the figure on the left is cylindrical and that on the right is cuboidal.
Lateral Surface area of cylinder= 2πrh=  154 cm2
Surface Area of Cube= 4×side=  196 cm2
It is clear that the cylinder is having a larger surface area.
Question 7
A closed cylindrical tank of radius 7 m and height 3 m is made from a sheet of metal. How much sheet of metal is required?
Answer
Surface Area of cylinder= 2πrh + 2πr2
=440 m2

Question 8
 The lateral surface area of a hollow cylinder is 4224 cm2. It is cut along its height and formed a rectangular sheet of width 33 cm. Find the perimeter of rectangular sheet?
Answer
 Area of Rectangular Sheet = Surface Area of the Cylinder
Area of Rectangle = Lx B
Or, Lx B = 4224
Lx 33 = 4224
L=128 cm
Question 9
A road roller takes 750 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 84 cm and length is 1 m.
Answer
 In one revolution the wheel of the roller will cover an area equal to its surface area.
Curved Surface Area of cylinder=2 πrh
=26400 cm2= 2.64 m2
Question 10
 A company packages its milk powder in cylindrical container whose base has a diameter of 14 cm and height 20 cm. Company places a label around the surface of the container (as shown in the figure). If the label is placed 2 cm from top and bottom, what is the area of the label.
NCERT Solutions for Mensurations Class 8 Mathematics
Answer: The cylindrical area covered by the label will have
Height = 20-4 = 16 cm
Curved Surface area of cylinder= 2 πrh
=704 cm2

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