- Introduction
- Work
- Work done by variable force
- |
- Mechanical Energy
- |
- Kinetic energy
- |
- Potential energy
- |
- Gravitational PE near the surface of the earth
- |
- Conversion of Gravitational PE to KE
- |
- PE of the spring
- |
- Conservation of energy of spring mass system
- |
- Conservative Forces
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- Power
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- Principle of conservation of energy
- |
- Solved examples

- So far we have defined work done by a force which is constant in both magnitude and direction.

- However, work can be done by forces that varies in magnitude and direction during the displacement of the body on which it acts.

- For simplicity consider the direction of force acting on the body to be along x-axis also consider the force F(x) is some known function of position x

- Now total displacement or path of the body can be decomposed into number of small intervals Δx such that with in each interval force F(x) can be considered to be approximately constant as shown below in the figure

- Workdone in moving the body from x
_{1}to x_{2}is given by

ΔW=F(x_{1})Δx_{1}where Δx_{1}=x_{2}-x_{1}

- Total workdone in moving the body from point A to point B

W=F(x_{1})Δx_{1}+F(x_{2})Δx_{2}+F(x_{3})Δx_{3}.....+F(x_{n})Δx_{n}

W=Σ F(x_{i})Δx_{i}where i=1 to i=n (4)

Where Σ is the symbol of summation

- Summation in equation 4 is equal to shaded area in figure 3(a) .More accuracy of results can be obtained by making these interval infintesimally smaller

- We get the exact value of workdone by making each interval so much small such that #916;x-> 0 which means curved path being decomposed into infinte number of line segment i.e

W= Lim_{Δx-> 0}Σ F(x_{i})Δx_{i}(5)

W =∫ F(x)dx with in the limits x_{A}and x_{B}

Where ∫ F(x)dx is the intregal of F(x) w.r.t x between the limits x_{A}and x_{B}and intregal can be evaluated using methods of calculus if F(x) of x is known

- Instead of x if the force also acts along y and z axis i.e direction of force keeps on changing then workdone bu such a force is given by

W=∫ F(**r**)d**r**with in the limits**r**and_{A}**r**(6)_{B}

Where F(**r**)=F(x)**i**+F(y)**j**+ F(z)**k**

and d**r**=dx**i**+dy**j**+ dz**k**

Here F(x),F(y) and F(z) are rectangular components of the force along x ,y and z axis .Similary dx,dy and dz are rectangular components of displacement along

x ,y and z axis

- we already have an idea that energy is associated closely with work and we have defined energy of a body as the capacity of the body to do work

- In dynamics body can do work either due to its motion ,due to its position or both due to its motion and position

- Ability of a body to do work due to its motion is called kinetic energy for example piston of a locomotive is capable of doing of work

- Ability of a body to do work due to its position or shape is called potential energy For example workdone by a body due to gravity above surface of earth

- Sum of kinetic energy and Potential energy of body is known as its mechanical energy

Thus

M.E=K.E+P.E

- Kinetic energy is the energy possesed by the body by virtue of its motion

- Body moving with greater velocity would posses greater K.E in comparison of the body moving with slower velocity

- Consider a body of mass m moving under the influenece of constant force F.From newton's second law of motion

F=ma

Where a is the acceleration of the body

- If due to this acceleration a,velocity of the body increases from v
_{1}to v_{2}during the displacement d then from equation of motion with constant acceleration we have

v_{2}^{2}-v_{1}^{2}=2ad or

a=v_{2}^{2}-v_{1}^{2}/2d Using this acceleration in Newton's second law of motion

we have

F=m(v_{2}^{2}-v_{1}^{2})/2d

or

Fd=m(v_{2}^{2}-v_{1}^{2})/2

or

Fd=mv_{2}^{2}/2 -mv_{1}^{2}/2 (7)

We know that Fd is the workdone by the force F in moving body through distance d

- In equation(7),quantity on the right hand side mv
^{2}/2 is called the kinetic energy of the body

Thus

K=mv^{2}/2

- Finally we can define KE of the body as one half of the product of mass of the body and the square of its speed

- Thus we see that quantity (mv
^{2}/2) arises purely becuase of the motion of the body

- In equation 7 quantity

K_{2}=mv_{2}^{2}/2

is the final KE of the body and

K_{1}=mv_{1}^{2}/2

is the initial KE of the body .Thus equation 7 becomes

W=K_{2}-K_{1}=ΔK (9)

- Where ΔK is the change in KE.Hence from equation (9) ,we see that workdone by a force on a body is equal to the change in kinetic energy of the body

- Kinetic energy like work is a scalar quantity

- Unit of KE is same as that of work i.e Joule

- If there are number of forces acting on a body then we can find the resultant force ,which is the vector sum of all the forces and then find the workdone on the body

- Again equation (9) is a generalized result relating change in KE of the object and the net workdone on it.This equation can be summerized as

K_{f}=K_{i}+W (10)

which says that kinetic energy after net workdone is equal to the KE before net work plus network done.Above statement is also known as work-kinetic energy theorem of particles

- Work energy theorem holds for both positive and negative workdone.if the workdone is positive then final KE increases by amount of the work and if workdone is negative then final KE decreases by the amount of workdone

Class 11 Maths page Class 11 Physics page

- Principles of Physics Extended (International Student Version) (WSE)
- university physics with modern physics by Hugh D. Young 13th edition
- NCERT Exemplar Problems: Solutions Physics Class 11
- H.C. Verma Concepts of Physics - Vol. 1
- CBSE All in One Physics Class 11 by Arihant
- NCERT Solutions: Physics Class 11th
- New Simplified Physics: A Reference Book for Class 11 (Set of 2 Parts)
- Pradeep's A Text Book of Physics with Value Based Questions - Class XI (Set of 2 Volumes)
- Oswaal CBSE Sample Question Papers For Class 11 Physics (For 2016 Exams)

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