Let A & B are two sample of ideal gases of equal mole .let T be the temperature of both the gas Let $E_A$ and $E_B$ are there total energy respectively .Let $M_A$ and $M_B$ are these respective Molecular Mass .which of these is true

a. $E_A > E_B$

b. $E_A < E_B$

c. $E_A =E_B$

d. none of these

Solution

An Ideal gas undergoes an state change according to PV diagram. what is the value $V_x$

a. $\frac {V_0}{2}$

b. $V_0$

c. $2V_0$

d. $\frac {V_0}{4}$

Solution

A container contains $N_2$ gas at T K. The no of moles of gas is $n_0$. Consider it behaves like ideal gas. It rms speed is $v_0$

What is the total translational kinetic energy

a. $\frac {3}{2} n_0RT$

b. $\frac {3}{2} RT$

c. $\frac {1}{2} RT$

d. $\frac {1}{2} n_0RT$

Solution

Suppose the temperature of gas is tripled and $N_2$ molecules dissociate into atom. Then what will be the rms speed of atom.

a. $v_0 \sqrt {6}$

b. $ \sqrt {6 v_0}$

c. $v_0 \sqrt {3}$

d. $\sqrt {3 v_0}$

Solution

if $V_p$ denotes most probable velocity of N

a. $V_p : V_0= \sqrt {2} : \sqrt {3}$

b. $V_p : V_0= 1 : 1$

c. $V_p : V_0= 2 : 3$

d. $V_p : V_0= \sqrt {2 }: 3$

Solution

An ideal gas undergoes the process describe by equation

$P = P_0 - aV^2$

Where $P_0$ , a are positive constant and V is the volume of one mole of gas

Maximum temperature attainable by gas

a. $\frac {2}{3} (\frac {P_0}{R}) \sqrt { \frac {P_0}{3a}}$

b. $3 P_0 \sqrt {\frac {P_0}{2Ra}}$

c. $(\frac {1}{3R}) \sqrt {\frac {P_0}{3a}}$

d. $\frac {4}{3} (\frac {P_0}{R}) \sqrt { \frac {P_0}{2}}$

Solution

Let V, V

is m then

a. No molecule can have a speed greater the (2)

b. No molecule can have a speed less the V

c. V

d. The average kinetic charge of a molecule (3/4 )mV

Solution

A flask contains Oxygen, Hydrogen & chlorine in the ration of 3:2:1 mixture at 27 °C

Molecular mass of Oxygen = 32

Molecular mass of Hydrogen = 2

Molecular mass of Chlorine = 70.9

Find the ratio of average kinetic energy per molecule of Oxygen & Hydrogen

a. 1:2

b. 1:1

c. 1:16

d. 2:1

find the ratio of average Kinetic energy per molecule of Hydrogen & chlorine

a. 1:2

b. 1:1

c. 1:16

d. 1:1

Solution 8-9

find the ratio of mean speed of Oxygen, chlorine, Hydrogen

a. 4:1 : (.45)

b. 5:2 :(5)

c. 1: (.45)

d. 2 :(.45)

Solution

Suppose a container is evacuated to have just one molecule of a gas in it. Let V

a. V

b. V

c. V

d. V

Solution

The velocities of the molecules are v, 2v, 3v, 4v & 5v. The rms speed will be

a. 11v

b. v(11)

c. v

d. 3.3v

Solution

Equal Number of molecules of hydrogen & Oxygen are contained in a vessel at one atmosphere

pressure. The ratio of the collision frequency of hydrogen molecules to the of Oxygen molecules on the

container

a. 1:4

b. 4:1

c. 1:16

d. 16:1

Solution

The prefect gases A, B & C having masses m

is the final temperature of mixture.

a. [(m

b. [(M

c. [(m

d. [(M

Solution

M moles of a ideal polyatomic gas(C

(a) $3Q=4MRT$

(b) 2Q=3MRT

(c) $Q=4MRT$

(d) $7Q=4MRT$

Solution

A gas mixture consist of molecules of type A, B, C, D with molecular

masses M

Two statement are drawn from it

E

V

which one of following is true

a. Only A correct

b. Only B correct

c. A & B both are correct

d. A & B both are wrong

Solution

a. Statement I is true ,statement II is true ,statement II is correct explanation for statement I

b. Statement I is true ,statement II is true ,statement II is not a correct explanation for statement I

c. Statement I is true, Statement II is false

d. Statement I is False, Statement II is True

There are two statement

which one of the following is correct

a. A and B both

b. A only

c B only

d. A and B both are incorrect

Solution

There are two statement about Ideal gases

which one of the following is correct

a. A and B both

b. A only

c. B only

d. A and B both are incorrect

Solution

Solution

Solution

A container has a mixture of 1 mole of oxygen and 2 moles of nitrogen at 330K.The ratio of average rotational kinetic energy per O

a. 2:1

b. 1:2

c. 1:1

d. None of these

Solution

1 mole of an ideal gas is contained in a cubical volume V, ABCDEFGH at 300 K One face of the cube (EFGH) is made up of a material which totally absorbs any gas molecule incident on it.

At any given time

(a) the pressure on EFGH would be zero.

(b) the pressure on all the faces will the equal.

(c) the pressure of EFGH would be double the pressure on ABCD.

(d) the pressure on EFGH would be half that on ABCD.

Solution

According the Maxwell's Speed distribution law

$A(v) = 4 \pi (\frac {M}{2\pi RT})^{3/2} v^2 e^{-Mv^2/2RT}$

Where V is molecular speed

M = molar mass of gas

R = gas constant

T = Temperature

A (v) = Probability distribution function

A (v) dv = fraction of the molecules whose speed lie in the internal of width dv speed center on v

What is most probable speed

a. $\sqrt {\frac {2RT}{M}}$

b. $\sqrt {\frac {RT}{M}}$

c. $\sqrt {\frac {3RT}{M}}$

d.$\sqrt {\frac {8RT}{M}}$

Solution

When is of these is true with respect to above paragraph where the integral is from 0 to infinity

a. $\int_{0}^{\infty}A (v) dv = 1$

b. $\int_{0}^{\infty}A (v) dv = 2$

c. $\int_{0}^{\infty}A (v) dv = 1/2$

d. $\int_{0}^{\infty}A (v) dv = 0$

Solution

let A

a. A

b. A

c. A

d. None of these

Solution

What is the formula for V

a. $V_{avg} = \int_{0}^{\infty} vA (v) dv $

b. $V_{avg} = \int_{0}^{\infty} A (v) dv $

c. $V_{avg} = \int_{-\infty}^{\infty} vA (v) dv $

d. $V_{avg} = \int_{-\infty}^{\infty} A (v) dv $

Solution

The below figure show a hypothetical speed distribution for a sample of N gas particles.

What is the relation but a, b & v

a. $v_0 (2a+3b) = 2$

b. $v_0 (2a- 3b) = 2$

c. $v_0 (a+ b) = 1$

d. $v_0 (a- b) = 1$

Solution

How much fraction of molecules are in speed range v

a. $(\frac {v_0}{2}) (3b+a)$

b. $v_0(3b+c)$

c. $(\frac {v_0}{4}) (3b+a)$

d. $(\frac {v_0}{4}) (3b-a)$

Solution

What is the average speed of the molecules

a. $\frac {6av_0^2 + 20bv_0^2}{6}$

b.$\frac {6av_0^2 - 38bv_0^2}{6}$

c. $3av_0^2 + 2bv_0^2$

d. $3av_0^2 - 2bv_0^2$

Solution

A. Average energy of monatomic molecule

B. Average energy of Diatomic molecule

C. Average energy of Polyatomic molecule with no vibration

d. Average energy of Diatomic molecule which vibrate

U. $3K_BT$

V. $\frac {7}{2} K_BT$

X. $\frac {5}{2} K_BT$

Y. $\frac {3}{2} K_BT$

a. A - V,B - X,C - U,D - Y

b. A - Y,B - X,C - U,D - V

c. A -X,B - Y,C - U,D - V

d. A - Y,B - X,C - V,D - U

Solution

A vessel of volume V contains a mixture of 1 mole of Hydrogen and 1 mole of Oxygen (both considered as ideal). Let $f_1(v)dv$, denote the fraction of molecules with speed between v and (v + dv) with $f_2 (v)dv$, similarly for oxygen. Then

(a) $f_1(v) + f_2(v) =f(v)$ obeys the Maxwell's distribution law.

(b) $f_1 (v)$, $f_2(v)$ will obey the Maxwell's distribution law separately.

(c) Neither $f_1 (v)$, nor $f_2 (v)$ will obey the Maxwell's distribution law.

(d) $f_2 (v)$ and $f_1 (v)$ will be the same.

Solution

A gas has five molecules having velocities v,2v,3v,4v,5v.Match the column A to column B

Here V

P. (V

Q. (V

R (V

S. (V

W. 9v

X. 11v

Y. 10v

Z. 0

a.P-W,Q-X,R-Y,S-Z

b.P-X,Q-W,R-Z,S-Y

c.P-X,Q-W,R-Y,S-Z

d.P-X,Q-W,R-X,S-Z

Solution

A gas has $v_0$ as rms at temperature $T_0$ and pressure $p_0$.which of the following is correct

a.If the pressure is doubled keeping temperature constant T0 ,rms will remain same

b.if the mass of the gas molecules is tripled,rms will become .58v0

c. if the temperature is increased such that T=4T0,rms will become 2v0

d. None of the above

Solution

A cubic vessel (with faces horizontal + vertical) contains an ideal gas at NTP. The vessel is being carried by a rocket which is moving at a speed of 200 m/s in vertical direction. The pressure of the gas inside the vessel as observed by us on the ground

(a) remains the same because 200 m/s is very much smaller than $v_{rms}$ of the gas.

(b) remains the same because motion of the vessel as a whole does not affect the relative motion of the gas molecules and the walls.

(c) will increase by a factor equal to $(\frac { v_{rms}^2 + 2500)^2}{v_{rms}^2})$ where $v_{rms}$ was the original mean square velocity of the gas.

(d) will be different on the top wall and bottom wall of the vessel.

Solution

**Notes****Assignments****Revision Notes**

Class 11 Maths Class 11 Physics Class 11 Chemistry Class 11 Biology

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