Question 1:
Express the given complex number in the form a + ib: (5i)(-3i/5)
Question 2:
Express the given complex number in the form a + ib:
i
9 +i
19
Question 3:
Express the given complex number in the form a + ib: i
-39
Question 4:
Express the given complex number in the form a + ib: 3(7 + i7) + i(7 + i7)
Question 5:
Express the given complex number in the form a + ib: (1 – i) – (–1 + i6)
Question 6:
Express the given complex number in the form a + ib:
(1/5+2i/5)-(4+i5/2)
Question 7:
Express the given complex number in the form a + ib:
Question 8
Express the given complex number in the form a + ib: (1 – i)
4
Question 9:
Express the given complex number in the form a + ib: (1/3+3i)
3
Question 10
Express the given complex number in the form a + ib: (-2-1i/3)
3
Question 11:
Find the multiplicative inverse of the complex number 4 – 3i.
Question 12:
Find the multiplicative inverse of the complex number
Question 13
Find the multiplicative inverse of the complex number –i
Question 14
Express the following expression in the form of a + ib.
Solution 1
(5i)(-3i/5)
Multiplying
=-(15/5)i
2
Now we know that
i
2=-1
so
=3
Solution 2
i
9 +i
19
=i
2X4 +1 +i
4X4 +3
=(i
2)
4 I + (i
4)
4 i
3
Now i
2=-1 so i
4=1 and i
3=-i
=i+(-i)
=i-i=0
Solution 3
Solution 4:
3(7 + i7) + i(7 + i7)
=21+21i+7i+7i
2
Now i
2=-1
So
=21+28i-7
=14+28i
Solution 5:
(1 – i) – (–1 + i6)
=2-7i
Solution 6:
(1/5+2i/5)-(4+i5/2)
=[(1/5)-4] +i[(2/5) –(5/2)]
=(-19/5) +(-21/10)i
Solution 7:
Solution 8
(1 – i)
4
Can be written as
=[(1-i)
2]
2
=(1+i
2-2i)
2
=(1-1-2i)
2
=4i
2=-4
Solution 9
Solution 10
Solution 11
Let z=4-3i
Conjugate is given by
=4+3i
Modulus is given by
|z|=5
Multiple inverse of any complex number z is given by
Solution 12
Let z= √5+3i
Conjugate is given by
= √5-3i
Modulus is given by
|z|=5+9=14
Multiple inverse of any complex number z is given by
Solution 13
Let z=-i
Conjugate is given by
=i
Modulus is given by
|z|=1
Multiple inverse of any complex number z is given by
Solution 14
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Class 11 Maths
Class 11 Physics
